I am a beginner in php and mysql and am trying to write code to insert values into a table. The problem is some variables like $upval and $aday are inserted correctly but $course and $chour are inserted as zeros, notice that I echo the ($course and $chour) before the insert query and the echo prints the correct values(not zero).
$res1=mysql_fetch_object($result1);
$course =$res1->cid;
$result2= mysql_query("select thoure from $tbl_name3 where cid='$course'");
$res2=mysql_fetch_object($result2);
$chour =$res2->thoure;
$sql ="insert into $tbl_name2 (SID,Cid,Tid,Adate,Ahoure) values ('$upval','$course','2','$aday','$chour')";
$result = mysql_query($sql);
also I try another way to write query but the same problem
$sql ="insert into $tbl_name2 (SID,Cid,Tid,Adate,Ahoure) values ('$upval','".$res1->cid."','2','$aday','".$res2->thoure."')";
This is your SQL statement:
$sql=insert into absent (SID, Cid, Tid, Adate, Ahoure)
values ('65','','2','2014-05-06','')
If Cid is being inserted as 0, that is because Cid is a numeric type (probably integer of some sort) and strings are converted to numbers. So, '' is inserted as to 0 into a number. Why the value is set to an empty string, I do not know.
Related
I was trying with this code but it didn't work. it's always get the MAX(eq_no) as 0
$sql1 =mysqli_query($con, "SELECT MAX(eq_no) AS val FROM tech_add_equip");
$sql2 = "INSERT INTO time (eq_no,status_no) VALUES ('$val', 4 );";
if (!mysqli_query($con,$sql2)) {
die('Error: ' . mysqli_error($con)); };
Finally, after I try with this code, it inserts in the right number of MAX(eq_no) but i still cant insert the values of status_no
INSERT INTO time (eq_no) SELECT MAX(eq_no) AS vale FROM tech_add_equip
Could you suggest me what did i missing in the code?
Thank you for your helping
One row returned from SELECT a,b,c statement in sub query is equivalent to set of values that is otherwise hardcoded as ('a-value','b-value','c-value')*. You can hardcode a value within select as well:
INSERT INTO time (eq_no, status_no)
SELECT MAX(eq_no), 4
FROM tech_add_equip
No need for aliases within select - order of columns matters.
*) One row result can be used for IN() clause. Another row would become set of values after comma - can't be uset for IN(), but it works ok for INSERT
('row1-a-value', 'row1-b-value'), ('row2-a-value', 'row2-b-value')
$max = SELECT MAX( customer_id ) FROM customers;
INSERT INTO customers( customer_id, statusno )
VALUES ($max , 4)
Not sure that this is even possible. I am inserting values into two tables at the same time using multi_query. That works fine. One of the tables has an auto increment column and I need to take the last auto incremented number and insert it into the second table so like this: insert into table 1 then take the last inserted number from column X and insert it along with other data into table 2. I have played around with using SELECT LAST and INSERT INTO but so far its just doing my head in. The insert statements looks like this:
$sql= "INSERT INTO tbleClients (riskClientId, riskFacility, riskAudDate) VALUES ('$riskclient2', '$facility2', '$riskdate2');";
$sql .="SELECT LAST(riskId) FROM tbleClients;";$sql .="INSERT INTO tblRiskRegister (riskId) SELECT riskId FROM tbleClients ;";
$sql .= "INSERT INTO tblRiskRegister (riskAudDate, riskClientId, riskSessionId, RiskNewId) VALUES ('$riskdate2', '$riskclient2', '$sessionid', '$risknewid')";
Individually they all produce results but I need it to happen simultaneously. I did toy with the idea of doing them all separately but figure thats not very efficient. Any pointers would be appreciated.
$sql= "INSERT INTO tbleClients (riskClientId, riskFacility, riskAudDate) VALUES ('$riskclient2', '$facility2', '$riskdate2');";
After executing the above query, using mysqli_insert_id(), which gives you the last insert id.
So below query is useless.
$sql .="SELECT LAST(riskId) FROM tbleClients;";
$sql .="INSERT INTO tblRiskRegister (riskId) SELECT riskId FROM tbleClients ;";
You can insert last_insert_id in above query.
Unable to find the relation between above & below query.
$sql .= "INSERT INTO tblRiskRegister (riskAudDate, riskClientId, riskSessionId, RiskNewId) VALUES ('$riskdate2', '$riskclient2', '$sessionid', '$risknewid')";
$sql = 'INSERT INTO photo '.
'(id,cid, path,date) '.
'VALUES (,`$cid`, `$new`,)';
There are four columns in the table, "photo".
1) id - auto increment
2) cid - $cid
3) path - $new
4) time - timestamp
Now I want to insert new data only to the cid and path fields. How can I do it with the above mentioned code
Try this:
//$con = you connection
$sql = "INSERT INTO photo (cid, path) VALUES ('$cid', '$new')";
mysqli_query($con, $sql);
this is as simple try this
$sql = "INSERT INTO photo (`cid`, `path`) VALUES ('$cid', '$new')";
Try this, if you know the value of id and date column value then pass it, other wise you just skip it or atlast pass the default value.
$sql = "INSERT INTO photo (cid, path,`date`) VALUES ('$cid', '$new',now())";
$sql = "INSERT INTO photo (cid, path,`date`) VALUES ('$cid', '$new',CURRENT_TIMESTAMP)";
1st of all... this is how you do debugging:
Run the query in phpmyadmin (echo query from php then run in phpmyadmin to see exactly what error you are getting, then adjust and test until it works properly
2nd: The ID. Either you lose it, like other people suggested above or you set it NULL and it gets auto incremented if it's set right in the schema.
I'm not trying to just give you a solution, i'm trying to get you some information, so you don't have to ask the next time.
$sql = "INSERT INTO photo (id,cid, path,date) VALUES (NULL,'".$cid."', '".$new."',now())";
mysqli_query($con, $sql);
You have some errors in your query
You have used tick mark around the variables which is invalid
Unwanted , at starting while entering values
This is not an error, but an advice:There is no need for breaking a query into several parts until it is large.
For inserting only cid and path Do like this
$sql = "INSERT INTO photo (cid, path) VALUES ('".$cid."', '".$new."')";
im having trouble inserting my data's from textbox into postgresdb.
my insert into tbl_ingredients is working fine but my insert into tbl_item is having a troubles can't figure it out how and where?
Connect();
$sql="INSERT INTO tbl_item VALUES('$itemname', '$highthreshold', '$lowthreshold', '$Qpunit', '$description', '$date');";
$iteminfo = pg_query($sql);
$sql1="SELECT MAX(itemid) as newid FROM tbl_item;";
$iden_new = pg_query($sql1);
$fetched_row = pg_fetch_row($iden_new,NULL,PGSQL_BOTH);
$newid=$fetched_row['newid'];
$sql2="INSERT INTO tbl_ingredient VALUES('$newid', '$Brandname');";
$ingredients = pg_query($sql2);
CloseDB();
if(!$sql)
{
$sucmsg = "Successfully added new Item, ".ucfirst($itemname)."!";
echo $sucmsg;
}
else
{
echo "error in saving data";
}
table structure:
tbl_item
itemid>itemname>highquantitythreshold>lowquantitythreshold>qntyperunit>Itemtype>description>dateadded
tbl_ingredient
itemid>brandname
im getting wamp "Warning: pg_query(): Query failed: ERROR: invalid input syntax for integer: "Strawberry" LINE 1: INSERT INTO tbl_item VALUES('Strawberry', '6', '3', '1300gra... ^ in D:\Wamp\wamp\www\Php\CTea\AddItem.php on line 247"
can someone lend me a helping hand thanks!.
You either need to use NULL ->
$sql="INSERT INTO tbl_item VALUES(NULL, '$itemname', '$highthreshold', '$lowthreshold', '$Qpunit', '$description', '$date');";
OR
You need to specify the columns you are inserting into ->
$sql="INSERT INTO tbl_item (itemname, highquantitythreshold, lowquantitythreshold, qntyperunit, description, dateadded) VALUES('$itemname', '$highthreshold', '$lowthreshold', '$Qpunit', '$description', '$date');";
Without the NULL or column name, the database does not know that you are skipping the first column - itemid - so it will try to insert the 1st value into that column.
from the manual - http://www.postgresql.org/docs/9.1/static/sql-insert.html
The target column names can be listed in any order. If no list of
column names is given at all, the default is all the columns of the
table in their declared order; or the first N column names, if there
are only N columns supplied by the VALUES clause or query. The values
supplied by the VALUES clause or query are associated with the
explicit or implicit column list left-to-right.
Each column not present in the explicit or implicit column list will
be filled with a default value, either its declared default value or
null if there is none.
How can I insert in two different tables from the same form ?
$sql = "INSERT INTO CLINET (IDMAT, TYPE, MARQUE,MODEL,PRIXACH,PRIXV)
VALUES
('$_POST[id_mat]','$_POST[type]','$_POST[marque]','$_POST[model]'),$_POST[prixach]','$_POST[prixv]'";
$sql1 = "INSERT INTO FOURNIR(IDFOUR, QTTE, IDMAT)
VALUES
('$_POST[id_four]','$_POST[qtte]','$_POST[id_mat]','$_POST[model]');
$sql = "INSERT INTO CLINET (IDMAT, TYPE, MARQUE,MODEL,PRIXACH,PRIXV)
VALUES
('$_POST[id_mat]','$_POST[type]','$_POST[marque]','$_POST[model]'),$_POST[prixach]','$_POST[prixv]'";
$sql1 = "INSERT INTO FOURNIR(IDFOUR, QTTE, IDMAT)
VALUES
('$_POST[id_four]','$_POST[qtte]','$_POST[id_mat]','$_POST[model]');
For the first query your missing a ')' at the end of your values.
For the second query, You have three column names, and four values. The amount of columns must match the amount of values.
Try checking basic syntax next time.