I've been trying to teach myself php and I came across this code (as with all code I try it out myself to get a better understanding etc) but this one doesn't run.
<?php
$i = 0;
while($i++){
switch ($i) {
case 5:
echo "At 5<br />";
break 1;
case 10:
echo "At 10; quitting<br />";
break 2;
default:
break;
}
}
?>
The output is just blank but would i be correct in saying that $i is incremented until it hits 5, at which point switch($i) would go to case 5 at echo "At 5" and then it'll break that switch statement and continue in the while loop incrementing $i till it reaches 10, then it'll repeat the same process and go to echo "At 10; quitting" and the break 2 would leave the switch and while loop?
During all the other values for $i i'm assuming it goes to default and just breaks out of the switch
Thank You.
The problem is this:
$i = 0;
while($i++){
When you do $i++ the variable $i is incremented with one but the value that is returned is still the old value, see the manual on Incrementing/Decrementing operators. So the first time when $i is still 0, the condition evaluates to false and the whole while() loop is never run / your switch is never reached.
To increase first and then return the value, you do:
$i = 0;
while(++$i){
See the example.
Try and make your code more readable by using variables/constants instead of magic numbers and you can also use labels on loops to break/continue on. Here is an example for you:
define("SOMETHING", 5);
define("SOMETHING_ELSE", 10);
$count = 0;
mainLoop:
while($count < 100) { #loop virtually forever
switch(++$count) { #increment and switch on $count in each iteration
case SOMETHING: #$count = 5
#do something here
echo "At 5<br />";
break; #break switch, continue while loop
case SOMETHING_ELSE: #$count = 10
#do something else here
echo "At 10; quitting<br />";
break mainLoop; #break while loop
}
}
Related
what I am trying to achieve here is to be able to loop from 0 to 100 (100, 98, 96, 94 ...) but has to stop at 0. What is doing right now is it passes 0 and -2 -4 which crashes the server. What am I doing wrong?
for ($i = 100; $i <= 100; $i--){
echo $i--;
echo "<br>";
}
Maybe a little explanation would be useful.
The middle part of the for loop $i <= 100 is what makes it infinite. That expression is checked before each iteration of the loop, and the loop will continue as long as that expression evaluates to true.
Since you set $ito 100 in the first section of the loop, and you're doing nothing except making it smaller, it will always be <= 100, forever.
The loop will work fine just the way you have it written if you change the continuation condition.
for ($i = 100; $i >= 0; $i--){
echo $i--;
echo "<br>";
}
That way it will continue until $i is reduced to less than zero, then $i >= 0 will be false, and the loop will end.
The third argument in for loop is what will be executed at the end of the loop. So:
for ($i = 100; $i >= 0; $i -= 2){
echo "$i<br>";
}
Will do the trick
As you can read here https://secure.php.net/manual/en/control-structures.for.php
At the end of each iteration, expr3 is evaluated (executed).
Alternatively:
<?php
foreach(range(100, 0, -2) as $n) {
echo $n;
}
for ($i = 100; $i >= 0; $i-=1){
echo $i--;
echo "<br>";
}
I figured it out somehow. Has been studying JavaScript for a year; Loop is still confusing to me
I am running a for loop 10 times in order to populate data in a data table. In doing this, I wanted to use number_format in order to format the numbers. However, when I apply the number_format the For loop for some reason runs one additional time.
It works just fine when I exclude the number_format. Can anyone explain why this happens?
<?php
foreach($data['data'] as $result) {
For ($n = 0; $n <= 10; $n++){
echo "<td>";
echo number_format($result[$n], 0, ".", ",");
echo "</td>";
}
}
?>
TL;DR: Your loop will always run an additional time. Assuming that there are no errors in your number_format function call, all you have to do to get this to run 10 times is change your code to for($n = 0; $n < 10; n++). Note the use of < and not <=.
For loops are really just syntactical sugar for while loops. The statement for(initial_statement; bound_condition; loop_statement) { code; } is equivalent to
initial_statement;
while(bound_condition) {
code;
loop_statement;
}
Which, functionally, is equivalent to
initial_statement;
while(true) {
code;
loop_statement;
if(!bound_condition) break;
}
This means that if you want a loop to run, say, 2 times, and you write for($i = 0; $i <= 2; $i++) your code will loop as follows:
$i = 0
i++; (i now equals 1)
i <= 2 (condition is true, so continue)
$i = 1
i++; (i now equals 2)
i <= 2 (condition is true, so continue)
$i = 2
i++; (i now equals 3)
i <= 2 (condition is FALSE, so break)
Using the <= operator when your control variable starts at 0 causes an extra iteration to occur, since there are three integer values of i such that 0 <= i <= 2 (0, 1, and 2). To ensure that there are only two iterations, use the < operator, and now the loop will only be executed for values in the domain 0 <= i < 2 (0 and 1).
If you are still bent on using the <= operator and are fine with a non-zero-based iteration count, then you can simply change the initial value of i to 1 to offset the error.
By the way your code is written, I assume that you wish for your inner loop to run 10 times, not 11. This would explain why you are getting an extra iteration, and the issue is quite unrelated to the use of number_format. If you are only getting 10 iterations when you don't use that function, you might want to make sure that the statement 1 == 1 evaluates to true in your PHP interpreter.
Additionally, as a code styling issue, I would recommend using consistent case in your statements; you write foreach (lowercase) but also use For (uppercase). The convention is to use lowercase for both.
I have no clue why you would be only getting 10 iterations without number_format. You might be counting incorrectly? Try changing it to < and see if that resolves your issue.
Case 1 loop inside another loop Can I assign both the $i variable for incrementing?
for($i=0; $i < 10; $i++)
{
for($i=0; $i < 5; $i++)
{
echo "You are too cute";
}
}
Case 2 : if it's not inside, Could I declare $i for both?
like this
for($i=0; $i < 10; $i++)
{
}
for($i=0; $i < 5; $i++)
{
}
There are already some answers that are just fine, but here's a slightly different perspective.
It depends on what you mean by "can". You can do this in the sense that it is syntactically correct PHP code.
for($i=0; $i < 10; $i++)
{
for($i=0; $i < 5; $i++)
{
echo "You will never see this text in your browser.";
}
}
But because a loop does not introduce a new variable scope in PHP, it creates an infinite loop.
The outer loop will execute once, then the inner loop will reset $i to 0, increment it to 5, return control to the outer loop, which will execute once, immediately causing the inner loop to start again, resetting $i to 0 and incrementing it to 5, and so on, forever (at least until your script times out). The outer loop can never end because the inner loop affects $i so that it can never satisfy the exit condition of the outer loop.
In other words, just use a different variable for the inner loop. Removing one integer variable is not going to be a noticeable optimization of your code, if that's what you're concerned about.
In the second example, there's no reason not to reuse $i.
Case 1: It will you get a really odd result, check it out here
How to do it properly? Check that out here
for($i=0; $i < 10; $i++){
for($k=0; $k < 5; $k++){
echo "1)".$i." 2)".$k."\n";
}
echo "\n";
}
Case 2: Works fine as stated in above comments and other answer. But, may I also add that in for instance this example.
for($i=0; $i < 10; $i++){
echo $i."\n";
}
echo "\n Outside the loop: ".$i." \n";
for($i=0; $i < 5; $i++){
echo $i."\n";
}
You can acces $i still after the loop has happend. The reason why you can use $i again is because you are declaring it $i =0; again, without interest toward another loop that is currently running (as is happening in case 1).
You can test this example here
Case 1 : No, you cant. you need to create variable individually for each loop.
for($i=0; $i < 10; $i++)
{
for($j=0; $j < 5; $j++)
{
echo "You are too cute";
}
}
Case 2 : Yes you can.
for($i=0; $i < 10; $i++)
{
echo "You are too cute";
}
for($i=0; $i < 5; $i++)
{
echo "You are too cute";
}
Case 1:
Short answer No you can't .
Long Answer .
First you need to understand what actually a variable is and How that Loop actually works .
Each and every variably is actually a reference to memory. In you example you have created a variable named $i and it can't be greater or equal 10 after incrementing value by one.
In the machine level it is translated to an address in the memory. say for example $i points to a random address 0xF25 When ever you loop it and incrementing it, the next address becomes 0xF30.
When ever you write a for loop, compiler automatically assigns a fixed memory address and that address it limited to your variable scope.
What compiler does is, it creates a table for that token($i). In simple form Look below an example
$i(This is the token ) -> 0xF25 (This is the value)
This value is updated when you do $i++
In nested Loop compiler assigns same table(though outer loop cant access inner loop variables). If compiler puts same variable for inner loop, it will be contradictory. Because inner loop may start from memory address 0xE21. In that case when your outer loop increment value by One it will be 0xE22 but as discussed above it needs to be 0xF30 .
That is why compiler does not allow this and we need to use CASE 2 example.
I have infinite loop in PHP and need to know the integer after the break in the switch case. Right now I use break 5; but I am now sure if this is right. Could someone tells me how to break out of all of the loops but while (true). I removed the unnecessary code so only the loops are left.
$i = 0;
while (true)
{
// After the break 5 in the switch we should land here again
foreach ($users as $user)
{
while ($i < 10)
{
if (!empty($user))
{
if (isset($user->id))
{
switch($user->id)
{
case 1:
break 5;
default:
break 5; // Need to break out the foreach. So a break five right?
}
}
}
$i++;
}
}
$i=0;
}
The answer is 3, as break ends execution of the current for, foreach, while, do-while or switch structure.
Where break 1 only exists the switch, 2 the while and 3 the foreach and 4 the main while.
But perhaps this is a better method, as you specifically state where to go instead of guessing. You cannot place the goto marker inside a loop, but in your case you can just make it before the loop.
$i = 0;
mybegin:
while (true){
# 1. After the break 3 in the switch we will -not- land here.
# 3. So if you want to start here, you will need to use the goto statement.
foreach ($users as $user){
while ($i < 10){
if (!empty($user)){
if (isset($user->id)){
switch($user->id){
case 1:
break 3;
default:
goto mybegin;
}
}
}
$i++;
}
}
# 2. Using break 3, the code continues here.
$i=0;
}
But I have to say that I never needed that many loops or a goto statement for that matter as there is always a better way.
Why doesn't the double equals work in a PHP for loop? The following works:
$cnt = 5;
for ($z = 0; $z <= $cnt; $z++) {
echo $z."!<br />";
}
But why doesn't this work?
$cnt = 5;
for ($z = 0; $z == $cnt; $z++) {
echo $z."!<br />";
}
The loop executes only if the condition evaluates to true. At the first iteration, $z == $cnt is false, so the loop never executes.
A common loop strategy is to use a sentinel value:
$cnt = 5;
$stop = $cnt + 1;
for ($z = 0; $z != $stop; $z++) {
. . .
}
Note that the comparison is negative (!= or !==). Using a sentinel is usually unnecessary for numerical loop variables (I wouldn't recommend it for your posted code), but is useful for other situations (e.g., when $stop represents null, an illegal value, etc.). It's particularly helpful when the loop variable changes in a pattern that is not easy to characterize succinctly.
because on the first iteration $z != $cnt, so the loop stops immediately.
Let us look at this from the computer's perspective:
If I am a computer this is what you told me to do:
set $cnt = 5;
set $z = 0;
check if $z equals $cnt
if so do whatever is in the loop, then increment $z
Trouble is, 5 does not equal 0 and never will, so the loop will simply be skipped. If you had $cnt = $z+1 inside the loop this would be an infinite loop.
So, you see, == works just fine, it simply doesn't do what you think it should do.
Hope this helps!
A for loop works by looping until a condition is made false. In the first example the loop will execute until z = 5 after that z will not longer be less than or equal to cnt (z starts at 0 and increments through each loop). In the second example you have $z == $cnt as your condition, and since z = 0 and cnt = 5 the loop will stop automatically because the condition is made false. You can use not equals instead like following:
$cnt = 6;
for ($z = 0; $z != $cnt; $z++) {
echo $z."!<br />";
}
The syntax of for is:
for (<init>; <condition>; <increment>)
The loop tests <condition> before each iteration. If it's true, it executes that iteration; if it's false, the loop terminates.
In your case, since $z == $cnt is false before the first iteration, the loop terminates immediately.
To do what you want, invert the test. You also need to bump the end value up by one, since the original version used <=, not <. Note that in both cases, the loop executes $cnt+1 times, because you start from 0.
for ($z = 0; $z != $cnt+1; $z++)