Minus 7 days from MYSQL date variable in PHP? - php

Question

I have a script that counts how many days have past since the start date stored in my database.
The theory is, a user signs up and has 7 days to complete registration, from the admin side of things, this script is used to monitor where a user is upto and how many days have past since they registered.
So in this example we give the user 7 days grace in which to complete. This echos out like '(number of days out of 7 have past'
Then after 7 days this should change to give the number of days overdue. so if a user has 7 days to complete and they take 8 days then this will take into account the first 7 days grace and then have an overdue date of 1 day.
so for instance it should echo out '1 day overdue', rather than what it is currently doing and saying 8 days overdue, i am trying to do this by minusing the first 7 days.
i have been told this will help however i am having trouble getting it to work with my date variable
$pre_date=date('Y-m-d', strtotime('-7 days'));
heres my compelte code, please can someone show me where i am going wrong
<?php include 'config.php';
$data = mysql_query("SELECT *,
TIMESTAMPDIFF(DAY, date, CURDATE()) AS expire_date
FROM supplier_session
ORDER BY expire_date ASC")
or die(mysql_error());
echo "<table class=\"table\" style=\"width:995px; font-family: 'Lucida Grande', Tahoma, Verdana, Arial, sans-serif;
font-size:11px;\" >
<tr>
<td style=\"width:100px;\">ID:</td><td>Company Name:</td><td>Company Reg No:</td><td>Application Started:</td><td style=\"width:200px;\">Application Duration:</td><td style=\"width:100px;\">Date:</td><td>Status:</td></tr>";
while($row = mysql_fetch_array( $data )) {
$days = $row['expire_date'];
$when = $days*0;
$str = $row['expire_date'];
$str2 = substr($str, 0); // "quick brown fox jumps over the lazy dog."
$pre_date=date('Y-m-d', strtotime('-7 days'));
if ($when <= 31){
echo "<tr><td style=\"width:100px;\"><p>".$row['id'] . "</p></td>";
echo "<td style=\"width:150px;\"><p>".$row['company_name'] . "</p></td>";
echo "<td style=\"width:150px;\"><p>".$row['company_reg_number'] . "</p></td>";
echo "<td>"; echo date('d/m/Y',strtotime($row['date'])); echo "</td>";
if ($days >= 8) {
echo "<td style=\"width:200px;\"><p>{$pre_date} days overdue</td>";
}
elseif ($when <= 7){
echo "<td style=\"width:200px;\"><p>{$str2} of 7 days past</td>";
}
}
echo "<tr>";
}
echo "</table>"; //Close the table in HTML
?>

Answer 1

You've forgotten to pass the date variable to strtotime, so you are always substracting 7 days to the actual date and getting 8 as a result.
Try with a subraction of the actual date minus the expire date in order to get the number of days that have past.

Answer 2

I think u have some mistake in ur function
$pre_date=date('Y-m-d', strtotime('-7 days'));
For example u can try to use somth like that
$datetime = date("Y-m-d", strtotime( date( 'Y-m-d' )." +2 days"));
Result of function looks like:
2014-05-08
Also there more information what u need:
Click.
With unixtime looks like that. We take difference between 2 dates in second and divide it on number of seconds in day
<?php
date_default_timezone_set('UTC');
$now_time = time();
$date_before = time()-(7*24*60*60);// 7 days; 24 hours; 60 mins; 60secs
echo($now_time);
echo('<br>');
echo($date_before);
echo('<br>');
$difference = $now_time - $date_before;
$result = intval($difference/(24*60*60)); //seconds in day
echo($difference);
echo('<br>');
echo($result);
also u can get time from date with:
$unixtime = strtotime('22-09-2008');