SELECT does not selects [duplicate] - php

Question

This question already has answers here:
Call to undefined method mysqli_stmt::get_result
(10 answers)
Closed 8 years ago.
I'm tryign to creat user_login system for my website. And now i got problems with selection of user_info from database , using mysqli and prepared statements .
My problem is , that i can't get any output . But i'm using the manual at php.net .
Here is what i have got the moment:
<?php
require_once 'php/includes/constants.php';
$connection = new mysqli(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME)or die("Error");
$phone = "0661488342";
$password = "1234";
$query = " SELECT *
FROM userinfo
WHERE phone = ? AND password = ?
LIMIT 1";
$stmt = $connection->prepare($query);
$stmt->bind_param('ss', $phone, $password);
$stmt->execute();
$res = $stmt->get_result();
$row = $res->fetch_assoc();
echo "Password = ".$row['password'];
The error :
Call to undefined method mysqli_stmt::get_result() in Z:...
Can you advise me something about this ?
Edition 1
PHP version is 5.2.12.(sorry, i forgot this)
But the question remains the same . How can i get the user_info ?

Answer 1

You need to have PHP 5.3.0 and also this method requires the mysqlnd driver. Othervise you will get this error:
Call to undefined method mysqli_stmt::get_result()
Which is what appears to be happening to you.

Answer 2

What is your PHP version, and mysql version?
You should learn more about MySQLi here: http://www.php.net/manual/en/book.mysqli.php

Answer 3

You have an error in your SQL, which you can detect by checking for errors (in this case it outputs them but there are better ways to handle errors.
if (!$stmt->execute()) {
echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}
if (!($res = $stmt->get_result())) {
echo "Getting result set failed: (" . $stmt->errno . ") " . $stmt->error;
}
$row = $result->fetch_row()
In your case password column name is a reserved word in MySQl (there is a PASSWORD function). Your SQL should backtick column names and table names:
$query = " SELECT *
FROM `userinfo`
WHERE `phone` = ? AND `password` = ?
LIMIT 1";
FINALLY, it looks like you are stroing passwords in the clear which means you are doing it wrong. See PHP The Right Way: Password Hashing