I extracted data from a database and sorted it based on the id. Now i need to separate out the rows with different ids. The aim is to find out the total price for each id and the latest date.
b_id price date
---- ----------------
1 98.30 2014-05-14
1 65.70 2014-05-07
2 14.40 2014-05-06
2 55.60 2014-05-07
2 38.20 2014-04-06
3 84.40 2014-04-02
3 31.30 2014-04-12
3 74.40 2014-05-06
I tried to separate it using -
while ($row = mysqli_fetch_array($result1)) {
if($row['b_id'] == 1){
}
}
But i cannot hard code it. How can i separate out the rows? Am i doing it wrong?
You can do what you want rigth on your query. It would be like:
select b_id, max(date) as maxdate, sum(price) total
from your table
group by b_id
order by b_id
If you want the total price, your extraction could be
SELECT b_id, SUM( price) AS total_price FROM your_table GROUP BY b_id
while ($row = mysqli_fetch_array($result1)) {
echo "Id : " . $row['b_id'] . " Price : " . $row['total_price'];
}
You should use SQL to achieve your goal. It's usually faster when the database handles simple calculations:
SELECT b_id,
SUM(price) AS 'Price',
MAX(date) AS 'Date'
FROM YourTable
GROUP BY b_id
Related
I've the following MySQL Table called store
id ref item_no supplier
1 10 x1 usa
2 10 x1 usa
3 11 x1 china
4 12 x2 uk
5 12 x3 uk
6 13 x3 uk
7 13 x3 uk
Now What i'm excepting the output to be is as follows :
id ref item_no supplier
1 10 x1 usa
3 11 x1 china
4 12 x2 uk
5 12 x3 uk
6 13 x3 uk
As you can see item_no x1 and x3 have same ref and supplier source, so what I want is to delete the duplicate record in-order to keep one item_no only !
I've create this PHP code to SELECT results only :
$query1 = "SELECT
DISTINCT(item_no) AS field,
COUNT(item_no) AS fieldCount,
COUNT(ref) AS refcount
FROM
store
GROUP BY item_no HAVING fieldCount > 1";
$result1 = mysql_query($query1);
if(mysql_num_rows($result1)>0){
while ($row1=mysql_fetch_assoc($result1)) {
echo $row1['field']."<br /><br />";
}
} else {
//IGNORE
}
How to tell the query to SELECT Duplicate records properly according to my needs before creating the DELETE query.
Thanks Guys
You can use the following query to produce the required result set:
SELECT t1.*
FROM store AS t1
JOIN (
SELECT MIN(id) AS id, ref, item_no
FROM store
GROUP BY ref, item_no
) AS t2 ON t1.id > t2.id AND t1.ref = t2.ref AND t1.item_no = t2.item_no
Demo here
To DELETE you can use:
DELETE t1
FROM store AS t1
JOIN (
SELECT MIN(id) AS id, ref, item_no
FROM store
GROUP BY ref, item_no
) AS t2 ON t1.id > t2.id AND t1.ref = t2.ref AND t1.item_no = t2.item_no
To find only duplicate records you can use
SELECT * FROM store WHERE id NOT IN
(SELECT id FROM store AS outerStore WHERE id =
(SELECT MAX(id) FROM store AS innerStore
WHERE outerStore.ref = innerStore.ref AND
outerStore.supplier = innerStore.supplier AND outerStore.item_no = innerStore.item_no))
Maybe long, but it should work.
If you want the select of the row to delete use
select * from store
where id not in (
select max(id) from store
group by distinct ref, item_no, supplier);
Or you can directly use a command for direct delete using
delete from store
where id not in (
select max(id) from store
group by distinct ref, item_no, supplier);
Why this query instead of displaying the sum of points for each user, it display the sum of all together
I have written an SQL query that displays the sum of all point for all users, whereas I would like it to: display the sum of points for each user.
The table that I have written contains the following:
id | Score
1 | 20
2 | 30
2 | 50
1 | 10
Total table :
id | points
1 | 30
1 | 40
What I want is to add the score for user(1) = 30 and user(2) = 80
Id: 1 = 30 = Fail
Id: 2 = 80 = Pass
The query I have written :
$query = "SELECT SUM(sg.score) as sum, SUM(a.total) as suma FROM points as sg, totalpoints as a
WHERE a.id = 1 GROUP BY sg.id";
And related PHP code is as follows:
<?php
foreach($rowsum as $rowsm):
if( ' '. htmlentities($rowsm['sum']) . '' > 50 )
echo 'Pass';
else if( ' '. htmlentities($rowsm['sum']) . '' >= 40 )
echo 'Failed';
echo ' ' . htmlentities($rowsm['sum'], ENT_QUOTES, 'UTF-8') . '<br>';
endforeach;
?>
You need to group by the users ID:
SELECT SUM(score) as sum FROM points GROUP BY id ORDER BY id
You also have an incorrect WHERE clause
WHERE id=id
isn't needed.
I guess you should look forward using the GROUP BY clause :
SELECT
SUM(score) AS sum
FROM
points
GROUP BY
id
ORDER BY
id
You've omitted the GROUP BY clause:
$query = "SELECT SUM(score) as `sum` FROM points GROUP BY id ORDER BY id";
Your WHERE clause wasn't needed.
You need to do group by as below and it will give you the sum of scores for each user
SELECT SUM(score) as sum FROM points
group by id
ORDER BY id
If you need to find it for a specific user just add a where condition as
SELECT SUM(score) as sum FROM points
where id = 1
The above will give the sum of scores for id = 1 and can change for other values as needed.
I have the following tables, in a standard shop:
(id is always primary key, auto-increment, ts is always type TIMESTAMP, updated ON_UPDATE CURRENT_TIMESTAMP)
table sales:
id | total | tendered | flag | userID | ts
1 0.6 0.6 0 4 2013-11-21 08:12:23
Sales is the parent table, userID is related to the user that made the sale. total and tendered are both of type FLOAT. flag is of type VARCHAR and could be Free Order.
table receipts:
id | oID | pID | quantity | ts
1 1 26 1 2013-11-21 08:11:25
Receipts holds a line for each unique type of product sold. oID is type INT and relates to the id of table sales. pID is of type INT and relates to the id of table products.
table products:
id | name | price | cID | display | ts
1 Mars 0.6 3 1 2014-01-17 07:55:25
Products is the central data for each product in the database. Here is a line for mars bars. cID relates to the id in table categories.
table categories
id | name | display | ts
3 Snacks 1 2013-11-14 12:06:44
Categories is the table holding all the data about each category, and can have multiple products relating to a single row. display is of type INT and dictates when the category is enabled or disabled (1 = 'true')
My question is, I want to output information like this:
**Snacks**
(name) (quantity) (price) (total)
Fruit 3 50p £1.50
Twix 1 60p 60p
Boost 1 60 60p
**Hot Drinks**
(name) (quantity) (price) (total)
English Tea 15 60p £9.00
Speciality Teas 2 60p £1.20
Which I have the following SQL for:
SELECT categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts WHERE pID=r.pID AND DATE(ts) = CURDATE()) AS quantity,
products.price,r.ts
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN categories ON products.cID = categories.id
WHERE DATE(r.ts) = CURDATE()
GROUP BY r.pID
ORDER BY categories.name;
Which seems to give me the correct information, but I am not 100% certain. If anyone could verify that this works, I would be most grateful. But when I want to see a particular day, I get unusual figures with the following SQL:
$postfrom = $_POST['from_mm']."/".$_POST['from_dd']."/20".$_POST['from_yy'];
$postto = $_POST['to_mm']."/".$_POST['to_dd']."/20".$_POST['to_yy'];
$from = strtotime($postfrom . " 6:00");
$to = strtotime($postto . " 23:59");
$itemised = select("SELECT categories.name AS category, products.name, pID,
(SELECT SUM(quantity) FROM receipts WHERE pID = r.pID AND UNIX_TIMESTAMP(r.ts) > '{$from}' AND UNIX_TIMESTAMP(r.ts) < '{$to}')
AS quantity, products.price
FROM receipts r
LEFT JOIN products ON r.pID = products.id
LEFT JOIN categories ON products.cID = categories.id
WHERE UNIX_TIMESTAMP(r.ts) > '{$from}'
AND UNIX_TIMESTAMP(r.ts) < '{$to}'
GROUP BY r.pID
ORDER BY categories.name;");
(function 'select' simply returns an array of the SQL table). The thing is, I could find the results easily by looping through in PHP and adding it up that way. But I know this is possible with SQL, I just don't know why It isnt working. Can somebody please help?
Edit SQL sample fiddle is here: http://sqlfiddle.com/#!2/23af4 although I couldn't do more than half a day of data due to 8000 character restrictions.
Try this:
SELECT categories.name AS category, products.name AS name,
receipts.quantity AS quantity, products.price AS price,
(receipts.quantity * products.price) AS total
FROM categories
JOIN products
ON categories.id = products.cID
JOIN receipts
ON receipts.pID = products.ID
WHERE DATE(receipts.ts) = CURDATE()
ORDER BY categories.name
SQLFiddle demo
With regard to the date restriction, you could use BETWEEN ... AND ... to specify the date and time. Using an absolute date and time moment or relative to the current day and time, for example WHERE DATE(receipts.ts) BETWEEN concat(curdate() -5,' 6:00:00 AM') AND curdate() -4
i have database with this condition :
table hotel -----> table hotel price
table hotel :
hotel_id | hotel_name |
1 hotel1
2 hotel2
table hotel price
price_id | hotel_id | room_type | single | Double | extra |
1 1 superior 5 10 20
2 1 deluxe 3 5 10
and i would show start smallest price from hotel1
hotel1 star from "smallest value"
i tried with this but not work
$query = ("SELECT LEAST(COL1,COL2,COL3) FROM rug WHERE COL1 != '' AND COL2!= '' AND COL3 != ''");
$result=mysql_query($query);
if (!$result) {
die('Invalid query: ' . mysql_error());}
$num=mysql_numrows($result);
$i=0;
while ($i < $num)
{
$pricing[$i]=mysql_result($result, $i);
$i++;
}
sort($pricing);
$lowest_price = $pricing[0]; //lowest price
thank raymond for the answer this is almost correct
select
*
, least(single, `double`, extra) as lowest_price
from hotel_price
where
hotel_id = 1
order by
lowest_price
;
with this will show lowest_price column at hotel price table
PRICE_ID HOTEL_ID ROOM_TYPE SINGLE DOUBLE EXTRA HOTEL_NAME LOWEST_PRICE
2 1 deluxe 3 5 10 hotel1 3
1 1 superior 5 10 20 hotel1 5
but i want just show one lowest price from lowest_price column
the smallest is 3
Any thoughts? Thanks!
Not completely sure if you need this..
if you know the id of hotel with name "hotel1" already
select
*
, least(single, `double`, extra) as lowest_price
from hotel_price
where
hotel_id = 1
order by
lowest_price
;
If you don't know the id of the hotel you need to join
select
*
, least(single, `double`, extra) as lowest_price
from
hotel_price
inner join
hotel
on
hotel_price.hotel_id = hotel.hotel_id
where
hotel.hotel_name = 'hotel1'
order by
lowest_price
;
see http://sqlfiddle.com/#!2/f947b/3 for demo note the demo has more queries what should give you the same results
By your SQL syntax I presume you are using MySQL. Than you can solve this by this approach:
SELECT
(SELECT COL1 from rug) as myField
UNION
(SELECT COL2 from rug)
UNION
(SELECT COL3 from rug)
order by myField ASC LIMIT 1
I have table Orders:
O_Id OrderDate OrderPrice Customer
1 2008/11/12 1000 Hansen
2 2008/10/23 1600 Nilsen
3 2008/09/02 700 Hansen
4 2008/09/03 300 Hansen
5 2008/08/30 2000 Jensen
6 2008/10/04 100 Nilsen
and query:
SELECT COUNT(Customer) AS CustomerNilsen FROM Orders
WHERE Customer='Nilsen'
but is possible add to this results IDs results?
I would like receive
count: 2
and
ids: 2 and 6
GROUP_CONCAT may help:
SELECT
COUNT(Customer) AS CustomerNilsen,
GROUP_CONCAT(O_Id) as IDS
FROM
Orders
WHERE
Customer='Nilsen'
Better to just fetch all the IDs and then use the appropriate row count function:
SELECT `O_Id` FROM `Orders`
WHERE `Customer` = 'Nilsen'
I don't really understand your question, but from what I can tell you just want to SELECT the o_id column in your query:
SELECT COUNT(Customer) AS CustomerNilsen, O_Id AS OrderID FROM Orders WHERE Customer='Nilsen'
You might check this
SELECT Customer,
COUNT(Customer) AS CustomerNilsen
FROM Orders
WHERE Customer = 'Nilsen'
GROUP BY Customer
HAVING CustomerNilsen = 1
Try this
SELECT O1.O_Id AS OrderID,Count(O1.O_Id) AS OrderCount FROM Orders O1
INNER JOIN Orders O2 ON O1.Customer = O2.Customer
WHERE O1.Customer='Nilsen'
GROUP BY O1.Customer,O1.O_Id