I want the result for this array sql query in one mysql_num_rows
how can I do that? i always get the result for last array query
I have MySQL records example: "1290511", "211223","08910"
$no=array("905","1122","891");
$arrlength=count($no);
for ($x=0; $x<$arrlength; $x++) {
$result = mysql_query(
"SELECT * FROM spe_no WHERE replace(sp_no,' ','') LIKE '%{$cars[$x]}%'"
) or die(mysql_error());
}
while ($row = mysql_fetch_array( $result )) {
$number = $row['sp_numbers'];
echo $number;
}
i always get the last record with "891"
it should all the example
Please help
You are issuing a query multiple times, but only fetching the result set from the last time you issue it. I believe you want this.
for($x=0;$x<$arrlength;$x++) {
$result = mysql_query("SELECT * FROM spe_no WHERE replace(sp_no,' ','') LIKE '%{$cars[$x]}%'") or die(mysql_error());
while($row = mysql_fetch_array( $result )) {
$number = $row['sp_numbers'];
echo $number;
}
}
Pro tip: Always indent your conditionals and loops so you can see at a glance the logic of your program's flow.
Pro tip: Avoid the mysql_interface, and switch to mysqli or PDO::.
Pro tip: Avoid SELECT *. Instead use a list of columns such as SELECT sp_numbers.
Related
I am trying to query a db for an entire column of data, but can't seem to get back more than the first row.
What I have so far is:
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_fetch_array($medicationItemObj, MYSQLI_NUM)){
echo count($row);
}
It's not my intention to just get the number of rows, I just have that there to see how many it was returning and it kept spitting out 1.
When I run the sql at cmd line I get back the full result. 6 items from 6 individual rows. Is mysqli_fetch_array() not designed to do this?
Well, I had a hard time understanding your question but i guess you are looking for this.
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
if($row = mysqli_num_rows($medicationItemObj))
{
echo $row;
}
Or
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
$i = 0;
while ($row = mysqli_fetch_array($medicationItemObj))
{
$medicationItem[] = $row[0];
$i++;
}
echo "Number of Rows: " . $i;
If you just want the number of rows i would suggest using the first method.
http://php.net/manual/en/mysqli-result.num-rows.php
You can wrote your code like below
$medicationItem = array();
$medicationItemSql = "SELECT medication FROM medication";
$medicationItemObj = mysqli_query($connection, $medicationItemSql);
while ($row = mysqli_fetch_assoc($medicationItemObj))
{
echo $row['medication'];
}
I think this you want
You could give this a try:
$results = mysqli_fetch_all($medicationItemObj, MYSQLI_NUM);
First, I would use the object oriented version of this and always use prepared statements!
//prepare SELECT statement
$medicationItemSQL=$connection->prepare("SELECT medication FROM medication");
// execute statement
$medicationItemSQL->execute();
//bind results to a variable
$medicationItemSQL->bind_result($medication);
//fetch data
$medicationItemSQL->fetch();
//close statement
$medicationItemSQL->close();
You can use mysqli_fetch_assoc() as below.
while ($row = mysqli_fetch_assoc($medicationItemObj)) {
echo $row['medication'];
}
I have a script like this:
$result = array();
$sql = "SELECT DISTINCT Name FROM servers"; //doesn't really matter what this MySQL script is
//storing the same query in two different variables
$result[0] = mysql_query($sql);
$result[1] = $result[0];
for($i = 0; $i < 3; $i++) {
$result[0] = $result[1];
while($ret = mysql_fetch_array($result[0]) {
//run some code
}
}
Unfortunately, the above code executes once and then for the next iterations returns nothing. What am I doing wrong?
I am not so sure what are you trying to do. but if i understand, try this. remove the for loop, just put the while loop and do what ever you want to.
$sql = "SELECT DISTINCT Name FROM servers";
$result = mysql_query($sql);
while($ret = mysql_fetch_array($result) {
//run some code
echo $ret['Name'];
}
}
you will get all 3 records in each iteration and do what ever process you want to do for each record. no need to make a three 3 query for 3 records. One query will have all records and do while loop to get each record. hope it helps.
I need help in order to assign the results of a nested query into array. This is the scenario:
$Date_Collection = mysql_query("SELECT DISTINCT Date FROM TblDate");
while($date = mysql_fetch_array($Date_Collection)) // Loop through all the dates
{
$var_date = $date['Date'];
$result = mysql_query("select min(Speed) as Min_spd, max (Speed) as Max_spd, avg
(Speed) as Avg_spd from ... where Date= $var_date");
while($row = mysql_fetch_array($result))
{
echo "row[Min_spd]";
echo "row[Max_spd]";
echo "row[Avg_spd]";
}
}
The output from this query is like this:
Min_Spd |Max_Spd |Avg_Spd| Date|
12.0| 25.0| 20.4| 2012-10-01|
11.0| 28.0| 21.4| 2012-10-02|
10.0| 26.0| 23.4| 2012-10-05|
08.0| 22.0| 21.4| 2012-10-08|
I basically need to show the sum of Min_Spd, Sum of Max_spd, Sum of Avg_spd for all these dates. So, I thought that If I can assign these values into an array and later compute these sum from the array, it might be a good idea.
Can anyone please help me regarding this? Can I use an array to store the values and later access these values and calculate the sum of these values. If I can use an array, could anyone please show me the syntax of using array in PHP. I would really appreciate any help regarding this.
Is there any alternative way rather than using an array, such as creating a temporary table to save these values and later delete the temporary table. If a temporary table can be used, could you please show me how to do that. I could use the temptable for a single loop, but there is a nested loop and I don't exactly know what to do to create a temp table inside the nested loop to store all the values.
$data = array();
while ($row = mysql_fetch_assoc($result)) {
$data[] = $row;
}
then later on you can do
foreach($data as $row) {
echo $row['Min_spd'];
echo ...
...
}
I don't know if the MySQL SUM function can be used to do that on te query, try it. But on this example, using arrays you should store the values and then use array_sum to return the sum of the elements. Something like this:
$min_spd = array();
$max_spd = array();
$avg_spd = array();
while($row = mysql_fetch_assoc($result))
{
$min_spd[] = $row['Min_spd'];
$max_spd[] = $row['Max_spd'];
$avg_spd[] = $row['Avg_spd'];
}
echo array_sum($min_spd);
It can also be done using variables to store and add the values:
$min_spd = 0;
$max_spd = 0;
$avg_spd = 0;
while($row = mysql_fetch_assoc($result))
{
$min_spd += $row['Min_spd'];
$max_spd += $row['Max_spd'];
$avg_spd += $row['Avg_spd'];
}
echo $min_spd;
I would first of all save yourself a nested query by doing the first query as:
$result = mysql_query("select Date, min(Speed) as Min_spd, max (Speed) as Max_spd, avg(Speed) as Avg_spd from ... group by Date")
And then create a running total for the sums as you're looping through each row:
$sumMinSpeeds=0;
$sumMaxSpeeds=0;
$sumAvgSpeeds=0;
while($row = mysql_fetch_array($result))
{
echo row['Min_spd'];
echo row['Max_spd'];
echo row['Avg_spd'];
$sumMinSpeeds += $row['Min_spd'];
$sumMinSpeeds += $row['Max_spd'];
$sumMinSpeeds += $row['Avg_spd'];
}
echo $sumMinSpeeds;
echo $sumMaxSpeeds;
echo $sumAvgSpeeds;
Instead of doing several MySQL queries in a loop, consider constructing such a query, which will return all the results you need.
SQL
First of all, it would make sense to use the GROUP SQL construct.
SELECT
s.Date date,
MIN(s.Speed) min,
MAX(s.Speed) max,
AVG(s.Speed) avg
FROM speed_table s
WHERE s.Date IN (SELECT DISTINCT d.Date FROM date_table d)
GROUP BY s.Date
It is important to understand what each part of this query does. If you run into any problems, consult the MySQL reference manual.
PHP
Forget about using mysql_* functions: they are deprecated and better implementations have emerged: PDO and mysqli. My example uses PDO.
try {
$dbh = new \PDO('mysql:dbname=my_db_name;host=127.0.0.1', 'dbuser', 'dbpass');
} catch (\PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = '...'; // This is the query
$stmt = $pdo->prepare($sql);
$stmt->execute();
You can now either iterate over the returned result set
while ($row = $stmt->fetch()) {
printf("%s; %s; %s; %s\n", $row['date'], $row['min'], $row['max'], $row['avg']);
}
or have the Statement object return the whole array by using
$result = $stmt->fetchAll(\PDO::FETCH_ASSOC);
I am selecting names of my products from products table in MySQL then I want to present these names to something like $names = array(name1, name2, ...) Where name1, ... are the names of the products from MySQL. I have gone through suggested similar cases but none seems to solve my problem. I am a newbie and just trying to learn.
$result = mysql_query("SELECT name FROM products");
$names=array();
while ($row = mysql_fetch_row($result)) $names[]=$row[0];
mysql_free_result($result);
You need the loop, as there is no way to directly get all rows of the complete result set.
$result = mysql_query("
SELECT `productname` FROM `products`
")or die($result."<br/><br/>".mysql_error());
$numrows = mysql_num_rows($result);
while ($row = mysql_fetch_assoc($result))
{
$productname[$i] = $row['productname'];
// to print out use the following
echo $productname[$i];
$i++;
}
Well, from an academic point of view, I suppose there's a "viable" alternative in doing something like
$names = explode('<|>', mysql_result(mysql_query(
"SELECT GROUP_CONCAT(name separator '<|>') FROM products GROUP BY 'name'"
), 0));
All the power of loops and arrays in single line, for the low, low price of making baby Jesus cry. And yes, you should probably use a loop. Unless you have a phobia ever since a loop waited for you outside your school when you were little and beat you up, I guess.
Dunno why everione sticked to one-liner but anyway it's always good idea to make your code less bloated
create a function
function dbGgetCol($sql) {
$ret = array();
$res = mysql_query($sql) or trigger_error(mysql_error()." in ".$sql);
if ($res) {
while ($row = mysql_fetch_row($result)) {
$ret[] = $row[0];
}
mysql_free_result($res);
}
return $ret;
}
place it in some config file included into each script
and then get your array with this simple code
$names = dbGetCol("SELECT name FROM products");
I have a small problem and since I am very new to all this stuff, I was not successful on googling it, because I dont know the exact definitions for what I am looking for.
I have got a very simple database and I am getting all rows by this:
while($row = mysql_fetch_array($result)){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
Now, my question is: how do I filter the 2nd result? I thought something like this could work, but it doesnt:
$name2= $row['name'][2];
Is it even possible? Or do I have to write another mysql query (something like SELECT .. WHERE id = "2") to get the name value in the second row?
What I am trying to is following:
-get all data from the database (with the "while loop"), but than individually display certain results on my page. For instance echo("name in second row") and echo("id of first row") and so on.
If you would rather work with a full set of results instead of looping through them only once, you can put the whole result set to an array:
$row = array();
while( $row[] = mysql_fetch_array( $result ) );
Now you can access individual records using the first index, for example the name field of the second row is in $row[ 2 ][ 'name' ].
$result = mysql_query("SELECT * FROM ... WHERE 1=1");
while($row = mysql_fetch_array($result)){
/*This will loop arround all the Table*/
if($row['id'] == 2){
/*You can filtere here*/
}
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
$counter = 0;
while($row = mysql_fetch_array($result)){
$counter++;
if($counter == 2){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
}
This While loop will automatically fetch all the records from the database.If you want to get any other field then you will only need to use for this.
Depends on what you want to do. mysql_fetch_array() fetches the current row to which the resource pointer is pointing right now. This means that you don't have $row['name'][2]; at all. On each iteration of the while loop you have all the columns from your query in the $row array, you don't get all rows from the query in the array at once. If you need just this one row, then yes - add a WHERE clause to the query, don't retrieve the other rows if you don't need them. If you need all rows, but you wanna do something special when you get the second row, then you have to add a counter that checks which row you are currently working with. I.e.:
$count = 0;
while($row = mysql_fetch_array($result)){
if(++$count == 2)
{
//do stuff
}
}
Yes, ideally you have to write another sql query to filter your results. If you had :
SELECT * FROM Employes
then you can filter it with :
SELECT * FROM Employes WHERE Name="Paul";
if you want every names that start with a P, you can achieve this with :
SELECT * FROM Employes WHERE Name LIKE "P%";
The main reason to use a sql query to filter your data is that the database manager systems like MySQL/MSSQL/Oracle/etc are highly optimized and they're way faster than a server-side condition block in PHP.
If you want to be able to use 2 consecutive results in one loop, you can store the results of the first loop, and then loop through.
$initial = true;
$storedId = '';
while($row = mysql_fetch_array($result)) {
$storedId = $row['id'];
if($initial) {
$initial = false;
continue;
}
echo $storedId . $row['name'];
}
This only works for consecutive things though.Please excuse the syntax errors, i haven't programmed in PHP for a very long time...
If you always want the second row, no matter how many rows you have in the database you should modify your query thus:
SELECT * FROM theTable LIMIT 1, 1;
See: http://dev.mysql.com/doc/refman/5.5/en/select.html
I used the code from the answer and slightly modified it. Thought I would share.
$result = mysql_query( "SELECT name FROM category;", db_connect() );
$myrow = array();
while ($myrow[] = mysql_fetch_array( $result, MYSQLI_ASSOC )) {}
$num = mysql_num_rows($result);
Example usage
echo "You're viewing " . $myrow[$view_cat]['name'] . "from a total of " . $num;