I want to fetch the landing_page value from this SQL table and add it to header location
: Ive got the following code at the top of the page but this is giving me a blank page:
<?php
foreach($[user_name] as $user) {
$location="Location:http://".$user['landing_page'];
header($location);
}
?>
<!-- if you need user information, just put them into the $_SESSION variable and output them here -->
Order: <?php echo $_SESSION['user_name']; ?>. You are securely logged in.
Where am i going wrong?
The original code is a login script with me trying to make the user to go google.com once logged in
You are not appending the variable properly. Try with,
header('"'.$user['landing_page'].'");
I think you can do this by Simply appending the argument in header
header("Location: " . $user['landing_page']);
try this:
<?php
header("Location: ".$user['landing_page']);
?>
Try this
<?php
foreach($user_name as $user) {
header("Location:http://".$user['landing_page']);
}
?>
or
<?php
foreach($user_name as $user) {
$location="Location:http://".$user['landing_page'];
header($location);
}
?>
Related
I created an app to receive and tally votes. I am trying to make the voter's selection carry over to a confirmation page so that I can display the name of the candidate for whom they voted on the confirmation page.
I am trying to use $_SESSION on the variable of the selected candidate from the voter's submission, and then call the variable on the confirmation page, however I continue to get undefined variable error.
voterSubmit.php:
<?php
$selectedCandidate = $_POST['candidateid'];
session_start();
$selection = $_SESSION[$selectedCandidate];
//Redirect to results page
header("Location: views/confirmation.php");
confirmation.php
<?php
session_start();
$_SESSION[$selectedCandidate] = $selection;
include "views/confirmation.php";
confirmation view:
<?php include "../partials/header.php"; ?>
<h1>Thanks For Your Vote!!</h1><br>
//This is where the error occurs (on my selection variable):
<h2>You voted for <?=$selection?>
View Results
<?php include "../partials/footer.php"; ?>
I want the name of the selected candidate to appear on the confirmation page by way of the $selection variable. However, all I receive on the front end is an "undefined variable" error. I also would like to note that instead of using the $selectedCandidate variable in my session, I have also tried grabbing the name directly by just using the name of the radio button selection as such:
$_SESSION['candidateid'] = $selection
I also would like to mention that i have tried the reverse:
on confirmation.php:
session_start();
$selection = $_SESSION[$selectedCandidate];
on voteSubmit.php:
session_start();
$_SESSION[$selectedCandidate] = $selection;
Your using the $_SESSION variable incorrectly.
Try:
voterSubmit.php:
<?php
$selectedCandidate = $_POST['candidateid'];
session_start();
$_SESSION['selectedCandidate'] = $selectedCandidate;
//Redirect to results page
header("Location: views/confirmation.php");
confirmation.php
<?php
session_start();
$selection = $_SESSION['selectedCandidate'];
include "views/confirmation.php";
voterSubmit.php looks ok... but I don't understand why you have include "views/confirmation.php"; in the confirmation.php file.
<?php
session_start();
$_SESSION[$selectedCandidate] = $selection;
include "views/confirmation.php";
Try coding your HTML/PHP this way:
<?php
/* confirmation.php */
session_start();
$_SESSION[$selectedCandidate] = $selection;
require_once("../partials/header.php");
//This is where the error occurs (on my selection variable):
echo <<<_STRT
<h1>Thanks For Your Vote!!</h1><br>
<h2>You voted for $selection</h2>
<p>View Results</p>
_STRT;
require_once("../partials/footer.php");
?>
I essentially eliminated a lot of start/stop code. The start of your PHP recalls the session and variable. Then I go into the HTML portion to provide the results to your site visitor. Give it a shot. Comment on it if it doesn't resolve your issue so we can rethink it.
I think session_start() needs to be the first line after the php tag.
$_SESSION is an array. So you need to assign it values like:
$_SESSION['keyname'] = $value;
voterSubmit.php:
<?php
session_start();
$_SESSION['selectedCandidate'] = $_POST['candidateid'];
//Redirect to results page
header("Location: views/confirmation.php");
confirmation.php
<?php
session_start();
$selection = $_SESSION['selectedCandidate'];
include "views/confirmation.php";
There are 2 issues in your code :
session_start() defined in the wrong place.
Wrong way of assigning value to your session variable.
Answer :
session_start() should be the first thing defined after your php
tag.
Correct way to declare session variables is : $_SESSION["selectedCandidate"] = $selectedCandidate; where, $selectedCandidate is the value to be assigned to your session variable, named selectedCandidate.
You have done 2 mistakes in your code:
1. Session should be defined in starting of page it means you have to define it like this:
<?php
session_start();
//php code goes here.
?>
2.wrong initialization of session variable .you should do it like this:
<?php
$_SESSION['selectedCandidate']=$selectedCandidate;
?>
Say I'm on /page_1.php. I run the following code under a certain condition:
global $URL_BEFORE_PAGE2;
$URL_BEFORE_PAGE2 = $_SERVER['REQUEST_URI'];
header('location: /page_2.php');
I am now on /page_2.php. This page contains the following link:
Return to Previous Page
PROBLEM: The link using $URL_BEFORE_PAGE2 points to /page_2.php instead of the expected /page_1.php.
I assume the problem is that $URL_BEFORE_PAGE2 is storing a reference to $_SERVER['REQUEST_URI'] instead of just storing the value. How can I keep the original value of $URL_BEFORE_PAGE2 without it updating every time $_SERVER['REQUEST_URI'] changes?
On page_1.php, use the following code to create a session that will store the uri
session_start();
$_SESSION['URL_BEFORE_PAGE2'] = $_SERVER['REQUEST_URI'];
header('location: /index2.php');
On page_2.php, simply use the session to get the uri again
<?php
session_start();
?>
Return to Previous Page
More info on sessions
session_start()
You could do that with javascript:
function goBack() {
window.history.back();
}
<button onclick="goBack()">Go Back</button>
You could do that with PHP like this:
<?php
header('Location: ' . $_SERVER['HTTP_REFERER']);
?>
I developing a Intranet and I'm a bit stuck with allowing access for individual users. All works fine when I limit the access to an element, if that element in at the bottom/last element. I need this to usable where ever I want. If you are in the Directors group, get the element. If you are in the All group only, you get nothing. Any help would be great.
The HTML:
.....
<?php include('admin/Directors.php');
echo 'foooooo':
?>
....
<?php include('admin/All.php');
echo 'baaaar':
?>
...
The PHP (Directors.php):
<?php
session_start();
$allowed_users = array('mark','joe','allan');
if(!in_array($_SESSION['user'],$allowed_users)) die('');
?>
From wat I understand is happening here is that its reading the Directors.php file and applying it to entire HTML file.
Try this In your Directors.php:
session_start();
$allowed_users = array('mark','joe','allan');
return in_array($_SESSION['user'],$allowed_users));
And this in your html:
$allowed = include('admin/Directors.php');
if($allowed)
{
echo 'foooooo';
}
Instead of killing script with die() simply return the evaluation value check it in your html. But if there is other stuff in Director.php you can do this.
Try this In your Directors.php:
session_start();
$allowed_users = array('mark','joe','allan');
$allowed =in_array($_SESSION['user'],$allowed_users));
And this in your html:
include('admin/Directors.php');
if($allowed)
{
echo 'foooooo';
}
With this snippet of code, I'm attempting to show a clickable link (if "admin" is logged in), which will redirect me to adminarea.php
Right now it just prints out "Admin" in text. Nothing to click on. Just simple text.
Am I missing anything? Surely I got it wrong but I cannot see what's missing.
Here is the code:
<?php if (getUser("user") == "admin") { ?>
<option value="adminarea.php">Admin</option>
<?php } ?>
You're printing an option, which is part of the select form input. You're probably looking for an anchor?
Admin
Possibly a better way to do this would be to declare two options for a variable in your PHP first. Something like:
<?php
if(getUser("user") == "admin") {
$adminlink = 'Admin';
} else {
$adminlink = NULL;
}
?>
And in the html:
<?php echo $adminlink; ?>
This would show the href link if the PHP condition was true, and would display nothing if not. Hope this helps!
Well based on your title am assuming you want a link. By the way you can use PHP friend html syntax instead of making the code look "dirty".
<?php if(getUser("user") == "admin"): ?>
Admin
<?php endif; ?>
I have a file, index.php that produces a link to a page that I want my user to only be able to access if some $var == True.
I want to be able to do this through the $GLOBALS array, since my $_SESSION array is already being filled with instances of a specific class I want to manipulate further on.
My index.php page:
<?php
$var = True;
$GLOBALS["var"];
echo "<p><a href='next.php'>Click to go to next page</a></p>";
?>
My next.php page:
<?php
if($GLOBALS["var"] == False)
exit("You do not have access to this page!");
else
echo "<p>You have access!</p>";
?>
Currently, next.php is echoing the exit text. Am I accessing/assigning to the $GLOBALS array correctly? Or am I not using it properly?
Thanks!
EDIT:
So I've tried some of the suggestions here. This is my new index.php:
<?php
$GLOBALS["var"] = True;
echo "<p><a href='next.php'>Click to go to next page</a></p>";
?>
My next.php:
<?php
if($GLOBALS["var"] == False)
exit("You do not have access to this page!");
else
echo "<p>You have access!</p>";
?>
However, I'm still running into the same issue where the exit statement is being printed.
It's much better to use sessions for this, since they are more secure and exist for this purpose. The approach I would recommend, is starting a new separate session array.
session_start();
$_SESSION['newSession']['access'] = true;
Then to access it use the same key/value.