avoiding doplicate lines and getting insert ids after multiple insertion - php

First question is I have a sql query like below.. And how to get ids of test, test1 and test2?
INSERT IGNORE INTO tags (tag_name) VALUES ('test'),('test1'),('test2')
There is a table to match tag_id and ann_id(announcements).The structure of the table is
tag_id(int 6)
ann_id(int 6)
I want to avoid duplicate lines. Is there anything that i can do with mysql for solve this problem? Or I must create a select query and count?

Related

PHP MySQL AUTO_INCREMENT with INSERT INTO .. ON DUPLICATE KEY

I have searched for an answer for days, however I can't seem to find the right solution. Therefore, I ask the following question:
Suppose I have a table with a column ID which is an AUTO_INCREMENT field and a column Word which is unique. I run the following queries:
"INSERT IGNORE INTO Table (Word) VALUES('Test')"
"INSERT IGNORE INTO Table (Word) VALUES('Test1')"
"INSERT IGNORE INTO Table (Word) VALUES('Test2')"
"INSERT IGNORE INTO Table (Word) VALUES('Test')" //THIS ONE WILL BE IGNORED
The problem is I can't get the last $mysqli->insert_id from the last query, because it isn't inserting anything. However I need this ID which is already in the DB. therefore, I thought I should use a ON DUPLICATE KEY UPDATE statement, however this leads to the situation where AUTO_INCREMENT is skipping values, because it updates the value but ALSO increments the AUTO_INCREMENT value although this value isn't assigned to any row.
So in the end, I end up with a table like this:
ID |Word
1 |Test
2 |Test1
3 |Test2
//Trying to insert words that where already in the table..
12 |Test3
//Trying to insert words that where already in the table..
17 |Test4
My answer would be to first retrieve the id for the word from the table and only if it fails to insert it. In both cases you have the id ready.
My guess is also that it will be faster this way around since you are not creating any ignored errors in mysql.

How to Insert values into one table from all tables from database

I have problems with the last line of the code:
if(isset($_POST['kolona']))
{
foreach($_POST['kolona'] as $vrednost)
mysql_query("ALTER TABLE tablica ADD $vrednost text NOT NULL");
mysql_query("INSERT INTO tablica ( ".(implode(',',($_POST['kolona']))).") SELECT ".(implode(',',($_POST['kolona'])))." FROM druga");
}
First query is making columns in table 'tablica' and second query suppose to insert values in that columns from all tables from which are the columns, for now it's just hard coded, it's only from table 'druga', but i don't know how to go through the all tables, not just 'druga'. I tried with a loop and also with implode function but nothing seems to be working. Can anyone help?
You can tackle merging problems like this using the ON DUPLICATE KEY feature:
INSERT INTO target (id, column1, column2)
SELECT id, column1, column2 FROM source
ON DUPLICATE KEY UPDATE column1=VALUES(column1), column2=VALUES(column2)
It works well provided you have a PRIMARY KEY column without conflicts between your source and target tables.

Avoid entering duplicate entries based on date, without using select statement

I am running a insert statement to insert data, but I want to check for any duplicate entries based on date and then do an entry.
All I want is if today a user enters product_name='x', 'x' is unique so that no one can enter product name x again today. But of course the next day they can.
I do not want to run a select before the insert to do the checking. Is there an alternative?
You can either use
1. Insert into... on duplicate update
2. insert.. ignore
This post will answer your question
"INSERT IGNORE" vs "INSERT ... ON DUPLICATE KEY UPDATE"
You can use the mysql insert into... on duplicate update syntax which will basically enter in a new row if one isn't there, or if the new row would have caused a key constraint to kick in, then it can be used to update instead.
Lets say you have the following table:
MyTable
ID | Name
1 | Fluffeh
2 | Bobby
3 | Tables
And ID is set as the primary key in the database (meaning it CANNOT have two rows with the same value in it) you would normally try to insert like this:
insert into myTable
values (1, 'Fluffster');
But this would generate an error as there is already a row with ID of 1 in it.
By using the insert on duplicate update the query now looks like this:
insert into myTable
values (1, 'Fluffster')
on duplicate key update Name='Fluffster';
Now, rather than returning an error, it updates the row with the new name instead.
Edit: You can add a unique index across two columns with the following syntax:
ALTER TABLE myTable
ADD UNIQUE INDEX (ID, `name`);
This will now let you use the syntax above to insert rows while having the same ID as other rows, but only if the name is different - or in your case, add the constraint on the varchar and date fields.
Lastly, please do add this sort of information into your question to start with, would have saved everyone a bit of time :)

How to Update if the data exist else insert the new data (multiple rows)

I need to create a insert and update statement, when today date is not in the database it will insert else it will update the QTY (from excel [this part I have done]) get from today.
But, there have a lots of row need to be insert and update.
1) it will check for the last 4 days in database, if there doesn't include today, it will just insert the data for today and update the last 3 days data. in the other hand, if there contain today it will just update.
P.S: I had try to use INSERT... ON DUPLICATE KEY UPDATE but it only 1 row affected.
If else statement , when i used this it only insert one row of data then the rest it just doing update.
Can give me some advise or example.
suppose you bulk copy your data from excel to a temporary table tbl and your actual table is tbl1 then do something like this
begin transaction;
if not exists(select * from tbl(updlock holdlock) where...)
begin
insert into tbl1...
else
begin
update tbl1...
end
commit;
What language are you using to do this? I have done something similar in Ruby before. I would make the column (Date in your case) unique at the database level then simply try inserting each record. When I get an exception thrown because the Date is not unique I would then proceed to update the QTY.
I found this article on mysql which says it supports multiple insert.
http://dev.mysql.com/doc/refman/5.0/en/insert-on-duplicate.html
INSERT INTO table (a,b,c) VALUES (1,2,3),(4,5,6)
ON DUPLICATE KEY UPDATE c=VALUES(a)+VALUES(b);
That statement is identical to the following two statements:
INSERT INTO table (a,b,c) VALUES (1,2,3)
ON DUPLICATE KEY UPDATE c=3;
INSERT INTO table (a,b,c) VALUES (4,5,6)
ON DUPLICATE KEY UPDATE c=9;
So if we want to edit straight, we could do something like this.
INSERT INTO table (uniquekey,data) VALUES (1,2),(4,5)
ON DUPLICATE KEY UPDATE data=VALUES(data);

MySQL: updating a row and deleting the original in case it becomes a duplicate

I have a simple table made up of two columns: col_A and col_B.
The primary key is defined over both.
I need to update some rows and assign to col_A values that may generate duplicates, for example:
UPDATE `table` SET `col_A` = 66 WHERE `col_A` = 70
This statement sometimes yields a duplicate key error.
I don't want to simply ignore the error with UPDATE IGNORE, because then the rows that generate the error would remain unchanged. Instead, I want them to be deleted when they would conflict with another row after they have been updated
I'd like to write something like:
UPDATE `table` SET `col_A` = 66 WHERE `col_A` = 70 ON DUPLICATE KEY REPLACE
which unfortunately isn't legal in SQL, so I need help finding another way around.
Also, I'm using PHP and could consider a hybrid solution (i.e. part query part php code), but keep in mind that I have to perform this updating operation many millions of times.
thanks for your attention,
Silvio
Reminder: UPDATE's syntax has problems with joins with the same table that is being updated
EDIT: sorry, the column name in the WHERE clause was wrong, now I fixed it
Answer to revised question:
DELETE FROM
table_A
USING
table AS table_A
JOIN table AS table_B ON
table_A.col_B = table_B.col_B AND
table_B.col_A = 70
WHERE
table_A.col_A = 66
This gets rid of the rows that would cause problems. Then you issue your UPDATE query. Ideally you will do it all inside a transaction to avoid a situation where troublesome rows are re-inserted in between the two queries.
Are there any foreign keys referencing this table? If not then the following should do:
CREATE PROCEDURE `MyProcedure` (IN invarA INT, IN invarB INT)
LANGUAGE SQL
NOT DETERMINISTIC
MODIFIES SQL DATA
SQL SECURITY DEFINER
BEGIN
DELETE FROM table WHERE col_B = invarB;
IF ROW_COUNT() > 0 THEN
INSERT INTO table (`col_A`, `col_B`) VALUES (invarA, invarB);
END IF;
END
Example call:
CALL `MyProcedure`(66, 70)

Categories