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Here I have regex, in which I want it to filter only word length >8 and <15 characters. I added
(?=.{8,14})b$
REGEX-http://regex101.com/r/sA5xL5
but it does not make any diff.
`^(?=.{8,14})b$\(?(?:(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?\(?(?:0\)?[\s-]?\(?)?|0)(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}|\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4}|\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3})|\d{5}\)?[\s-]?\d{4,5}|8(?:00[\s-]?11[\s-]?11|45[\s-]?46[\s-]?4\d))(?:(?:[\s-]?(?:x|ext\.?\s?|\#)\d+)?)$^|^2(?:0[01378]|3[0189]|4[017]|8[0-46-9]|9[012])\d{7}|1(?:(?:1(?:3[0-48]|[46][0-4]|5[012789]|7[0-49]|8[01349])|21[0-7]|31[0-8]|[459]1\d|61[0-46-9]))\d{6}|1(?:2(?:0[024-9]|2[3-9]|3[3-79]|4[1-689]|[58][02-9]|6[0-4789]|7[013-9]|9\d)|3(?:0\d|[25][02-9]|3[02-579]|[468][0-46-9]|7[1235679]|9[24578])|4(?:0[03-9]|2[02-5789]|[37]\d|4[02-69]|5[0-8]|[69][0-79]|8[0-5789])|5(?:0[1235-9]|2[024-9]|3[0145689]|4[02-9]|5[03-9]|6\d|7[0-35-9]|8[0-468]|9[0-5789])|6(?:0[034689]|2[0-689]|[38][013-9]|4[1-467]|5[0-69]|6[13-9]|7[0-8]|9[0124578])|7(?:0[0246-9]|2\d|3[023678]|4[03-9]|5[0-46-9]|6[013-9]|7[0-35-9]|8[024-9]|9[02-9])|8(?:0[35-9]|2[1-5789]|3[02-578]|4[0-578]|5[124-9]|6[2-69]|7\d|8[02-9]|9[02569])|9(?:0[02-589]|2[02-689]|3[1-5789]|4[2-9]|5[0-579]|6[234789]|7[0124578]|8\d|9[2-57]))\d{6}|1(?:2(?:0(?:46[1-4]|87[2-9])|545[1-79]|76(?:2\d|3[1-8]|6[1-6])|9(?:7(?:2[0-4]|3[2-5])|8(?:2[2-8]|7[0-4789]|8[345])))|3(?:638[2-5]|647[23]|8(?:47[04-9]|64[015789]))|4(?:044[1-7]|20(?:2[23]|8\d)|6(?:0(?:30|5[2-57]|6[1-8]|7[2-8])|140)|8(?:052|87[123]))|5(?:24(?:3[2-79]|6\d)|276\d|6(?:26[06-9]|686))|6(?:06(?:4\d|7[4-79])|295[567]|35[34]\d|47(?:24|61)|59(?:5[08]|6[67]|74)|955[0-4])|7(?:26(?:6[13-9]|7[0-7])|442\d|50(?:2[0-3]|[3-68]2|76))|8(?:27[56]\d|37(?:5[2-5]|8[239])|84(?:3[2-58]))|9(?:0(?:0(?:6[1-8]|85)|52\d)|3583|4(?:66[1-8]|9(?:2[01]|81))|63(?:23|3[1-4])|9561))\d{3}|176888[234678]\d{2}|16977[23]\d{3}|7(?:[1-4]\d\d|5(?:0[0-8]|[13-9]\d|2[0-35-9])|624|7(?:0[1-9]|[1-7]\d|8[02-9]|9[0-689])|8(?:[014-9]\d|[23][0-8])|9(?:[04-9]\d|1[02-9]|2[0-35-9]|3[0-689]))\d{6}|76(?:0[012]|2[356]|4[0134]|5[49]|6[0-369]|77|81|9[39])\d{6}|80(?:0\d{6,7}|8\d{7})|500\d{6}|(?:87[123]|9(?:[01]\d|8[0-3]))\d{7}|8(?:4[2-5]|70)\d{7}|70\d{8}|56\d{8}|(?:3[0347]|55)\d{8}|8(?:001111|45464\d)$|(?:\((\+?\d+)?\)|(\+\d{0,3}))? ?\d{2,3}([-\.]?\d{2,3} ?){3,4}`
please dont bother about regex length.
It matches even if match length exceeds
What is missing to restrain it to filer 8-14 length pattern match only.
First off, ^(?=.{8,14})b$ means "at the beginning of the string as asserted by ^, look ahead to see if we can find a single character between 8 and 14 times, and if yes, then match a single character b then the end of the line $. You cannot have one line that is both a single character b and 8 characters in length. This part of the expression can never match. See demo.
But your regex still finds an overall match. Why? Clearly, even if ^(?=.{8,14})b$ were able to match anything, it does not set a condition for the whole expression, because something later in the regex overrides it: an alternation (|) which means that we can match what's on the left OR what's on the right.
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I'm trying to do Regex code for product's code in VSCode's HTML. My product's code has the following conditions:
Required enter 6 characters
First 2 characters must be letter and uppercase
Next 4 characters must be numbers.
I have tried this regular expression and it doesn't work:
^[A-Z]{2}+\[0-9]{4}$
Your regex should be:
^[A-Z]{2}[0-9]{4}$
This corrects the escaping of your character class; that made it no longer a character class but a series of characters to match in the regex, ending with 4 ]s. The + also is not needed as the {2} is stating only 2 uppercase alpha characters are allowed.
You can also swap the [0-9] with \d which is the metacharacter for an integer. With PHP regexs you also need delimiters so something like:
/^[A-Z]{2}\d{4}$/
could be used in preg_match.
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I have a password field which needs to be validated on the backend and currently i have this regex pattern that checks if it is an alphanumeric
preg_match("/^[a-z0-9]+$/i", $sValue)
Right now I'm confused how can I required the password to be
Only letter is invalid
Only number is invalid
Must be a combination of number and letter.
in regex.
Any idea how can I implement it?
A simple way is
preg_match("/^(?!(?:[a-z]+|[0-9]+)$)[a-z0-9]+$/i", $sValue)
which disallows just a letter(s) or just a number(s)
^
(?!
(?: [a-z]+ | [0-9]+ )
$
)
[a-z0-9]+
$
Require at least a digit but disallow digits only while limiting the character set to alnum.
^(?!\d+$)[a-z]*\d[a-z\d]*$
(?!\d+$) at start look ahead for not only digits until end
[a-z]* any amount of alphas followed by at least one \d digit
[a-z\d]*$ any amount of alnum until $ end
See demo at regex101 (use with i caseless flag).
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I have the following string:
#35+#36+#37+#38+#39+#40+#46+#47+#48+#49+#50+#51
How would I achieve getting only numbers after the #.
Also how can I get any numbers that have no # in front?
To match numbers preceded by # use (?<=#)\d+ (positive lookbehind
for #, then a non-empty sequence of digits).
To match numbers not preceded by # use (?<!\d|#)\d+ (negative lookbehind).
This time however the "forbidden" preceding char is either a # or a digit.
Of course, use both patterns with g (global) option.
If you want to process all numbers is a single loop and within this
loop detect, whether the number has a preceding #, you can use another
option, namely (#?)(\d+).
This pattern contains 2 groups:
optional # and
a sequence of digits.
Then, processing each match, read the number from group 2 and check group 1,
whether it contains the #.
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Im a beginner in PHP I just want to ask can someone explain to me this line of code.
(preg_match('/^\w{5,}$/', $username))
Thankyou in advance. :) Your answer is so much appreciated. :)
Your PHP match string is
/^\w{5,}$/
and a PHP match string is surrounded by / characters which are not part of the RegEx string itself.
According to the comments your problem is about understanding regular expressions, not PHP.
^ is the beginning of the line, correct
$ is the end of the line, correct
\w Any word character (letter, number, underscore)
a{5,} does mean 5 or more characters 'a'
Therefore: If there are 5 or more any word characters in the username the function returns a positive result.
Or even easier: A username needs to contain at least five any word characters.
Learn more about regular expressions and how they work. Some explanation can be found in this comment.
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is it possible to check the ninth number from the right whether its 5 or not.
I want to check the 9th digit from the right is a five:
00966588696745
^-True
12088696748
^-False
is it possible ?
You can use a lookahead: 5(?=\d{8}$)
This will ensure that your test string contains a 5 followed by 8 digit and the end of the string.
A simple version of this would be as follows:
^5.{8}$
Explanation:
^ - start looking from beginning of the string
5 - you want to ensure that the string starts with 5
. - any character. But if you need to assure it is only digits you need to use \d instead (the \ is important)
{8} - you expect for 8 chars of any type (since we use dot: '.')
$ - means end of the string. This assures that you have exactly 8 chars before end of the string
I hope this answer is helpful and explains the parts inside the regexpr