Passing PHP value to jQuery progressbar - php

How to pass the PHP value $sources to the value of progress bar? I am trying to add into session in the below code but fail. Any easy way to get the $sources? Please help.
......
<link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<link rel="stylesheet" href="/resources/demos/style.css">
<script>
$(function() {
var score = '<%= session.getAttribute("sources") %>';
$( "#progressbar" ).progressbar({
value: score
});
});
</script>
</head>
<body>
<?php
session_start();
$sources=10;
......
echo '<td>Your answer was correct </td></tr>';
$sources+=1;
......
$_SESSION['sources']=$sources;
?>
<div id="progressbar"></div>
</body>
</html>

session_start() should be at the top of the page. after starting
then $_SESSION['sources'] should be set before calling it. otherwise you should check for it's value before printing to web page.
find below codes and rearrange your script.
<?php
session_start();
?>
......
<link rel="stylesheet" href="//code.jquery.com/ui/1.10.4/themes/smoothness/jquery-ui.css">
<script src="//code.jquery.com/jquery-1.10.2.js"></script>
<script src="//code.jquery.com/ui/1.10.4/jquery-ui.js"></script>
<link rel="stylesheet" href="/resources/demos/style.css">
<script>
$(function() {
var score = <? echo (isset($_SESSION['sources'])) ? $_SESSION['sources'] : ""; ?>;
$( "#progressbar" ).progressbar({
value: score
});
});
</script>
</head>
<body>
<?php
$sources=10;
......
echo '<td>Your answer was correct </td></tr>';
$sources+=1;
......
$_SESSION['sources']=$sources;
?>
<div id="progressbar"></div>
</body>
</html>

var score = '<%= session.getAttribute("sources") %>';
The <%= %> is java syntax for scriplets ,
additionally it's wrapped in quotes so it is treated as a string literal from javascript.
Below is the syntactically right way (I don't know if you'll get the right value. That
depends on your program structure).
var sources = <?php echo $_SESSION['sources']; ?>;

Related

Posting data using jQuery Ajax to another php file [duplicate]

This question already has answers here:
What is the order of inline onclick vs addeventlistener and why?
(3 answers)
Closed 2 years ago.
I have two PHP pages. On one of the pages, I want to post data to the other page when a button is pressed. However, when I try to access the post array from the other page, it appears empty. Would appreciate if someone could show me where I'm going wrong. (Also I'm not allowed to use a html form to post)
Page called test2.php:
<?php
if(isset($_POST['testing1'])){
die(json_encode($_POST));
}
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
<button id="testbtn" onclick="location.href='test1.php'">Test Button</button>
<script>
$(document).ready(function(){
$('#testbtn').click(function() {
$.ajax({
method: 'POST',
url: 'test1.php',
data: {
testing1: 'string1',
testing2: '111'
},
success: function(data){
alert(data);
output = JSON.parse(data);
}
});
});
});
</script>
</body>
</html>
Page called test1.php:
<?php
$testvar = json_encode($_POST);
echo $testvar;
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
</body>
</html>
the reason the it's failing is because you have so much html on test1.php
alert(data) is having an issue because there is so much content.
JSON.parse(data) is failing because it's not just json it's also html
test1.php should just simply parse post to json and echo it
<?php
echo json_encode($_POST);
?>
When you press the button 2 things are happening in same time :
The ajax call that sends data to the page test1.php
The page redirection beacause of the onClick attribute on the button.
The ajax request calls the page test1.php which is not the same instance as the page you call when you use the onClick attribute. So I think you could try placing "location.href = 'test1.php'" in the success function and store $_POST in a session variable. That way the data will reach the test1.php page before your redirect.
success: function(data){
alert(data);
output = JSON.parse(data);
location.href = 'test1.php';
}
Maybe like this:
Page called test2.php:
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
<button id="testbtn" onclick="location.href='test1.php'">Test Button</button>
<script>
$(document).ready(function(){
$('#testbtn').click(function() {
$.ajax({
method: 'POST',
url: 'test1.php',
data: "yourData="+"{
testing1: 'string1',
testing2: '111'
}",
dataType:"json",
success: function(data){
alert(data);
output = JSON.parse(data);
}
});
});
});
</script>
</body>
</html>
Page called test1.php:
<?php
if(isset($_POST["yourData"]){
$testvar = json_decode($_POST["yourData"]);
echo $testvar->testing1."<br/>";
echo $testvar->testing2;
}else{
echo"is not set";
}
if(!empty($_POST["yourData"]){echo $_POST["yourData"];}else{echo"is empty";}
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="styles.css">
<link rel="stylsheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.5.0/css/bootstrap.min.css">
<script src="https://cdnjs.cloudflare.com/ajax/libs/Chart.js/2.9.3/Chart.min.js" integrity="sha512-s+xg36jbIujB2S2VKfpGmlC3T5V2TF3lY48DX7u2r9XzGzgPsa6wTpOQA7J9iffvdeBN0q9tKzRxVxw1JviZPg==" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/gh/emn178/chartjs-plugin-labels/src/chartjs-plugin-labels.js"></script>
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
</head>
<body>
</body>
</html>
NB:
dataType:"json" used if you want to get a json answer;
if you use dataType:"json" that mean you have to change the method json_decode() in my code to json_encode();
isset() check if name of associative array is exist;
! means not;
empty() check that if the value of that name in associative array is empty (like ' ');
!empty() check that if the value of that name in associative array is not empty (not like ' ').

Pass JQuery variables to php

I want to pass jQuery variable to php file ,
this is my_js.js file
function updates() {
$.getJSON("php/fetch.php", function(data) {
$.each(data.result, function(){
var s_id = this['sender_id'];
});
});
}
and i want to display it here in php file,
<html>
<head><title>Pass jquery var to php file</title>
</head>
<body>
<div> <?php echo $s_id ; ?> </div>
<script type="text/javascript" src="my_js.js"></script>
<script type="text/javascript" src="jquery.js"></script>
</body>
</html>
You might consider using jQuery to set the s_id value in the page.
You can modify your HTML as follows (the important part being the added span element):
<html>
<head><title>Pass jquery var to php file</title>
</head>
<body>
<div><span id="s_id"></span></div>
<script type="text/javascript" src="my_js.js"></script>
<script type="text/javascript" src="jquery.js"></script>
</body>
</html>
And you can use jQuery in your getJSON callback to set the value as follows to find your added span element and modify its text:
function updates() {
$.getJSON("php/fetch.php", function(data) {
$.each(data.result, function(){
$("#s_id").text(this['sender_id']);
});
});
}

How to assign a PHP variable value to JavaScript variable

In this code which I am posting i have one problem. I want my PHP variable to be stored in JavaScript variable but it shows error. The code is below.
<?php
$name="anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1=.$name.";"
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
Now when I am assigning $name to the variable name1 than I get an syntax error. Please let me know what changes I have to make. So that I get the value of the PHP variable $name stored in JavaScript variable name1.
In javascript with echo version: var name1= "'.$name.'";
<?php
$name = "anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1= "'.$name.'";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
And you can use like var name1= "<?php echo $name; ?>"; seperated html and php
<?php
$name="anurag singh";
?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1= "<?php echo $name; ?>";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
<?php
$name="anurag singh";
echo '
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1='.$name.'";"
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
';
?>
echo it into a script tag
echo '<script> var name = '.$name.';</script>';
You can do it this way -
<?php $name="anurag singh"; ?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1="<?php echo $name ?>";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
You are pasing string $ame not variable as because you have used '...' this let the php know that its string no more variables inside this string.
<?php
$name="anurag singh";
?>
<html>
<head>
<script type="text/javascript" src="jquery-2.0.2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
var name1=<?pgp echo $name ?>;
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
});
</script>
</head>
<body>
<h1>This is the demo!</h1>
<h2>In echo we can add more than one statements</h2>
</body>
</html>
try this
$(document).ready(function(){
var name1="'.$name.'";
$.post("main_page.php",{input1: name1}, function(msg){
alert("hi "+msg);
});
you can assign this value like var name= "'. $name.'";

Parse Error, Inserting PHP code in MyBB

I'm inserting this code in the <head> </head> for a mybb forum:
<?php if(isset($_REQUEST['url'])): // <-- only include jQuery if url set ?>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.9.2/themes/base/jquery-ui.css" />
<script src="http://code.jquery.com/jquery-1.8.3.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<script>
$(function() {
$( "#dialog-modal" ).dialog({
height: 140,
modal: true
});
});
</script>
<?php endif; ?>
Seeing two errors at the top of the page saying
Parse error: syntax error, unexpected $end in /home/content/87/9583687/html/a/global.php(524) : eval()'d code(2) : eval()'d code on line 1
Parse error: syntax error, unexpected T_ENDIF in /home/content/87/9583687/html/a/global.php(524) : eval()'d code(14) : eval()'d code on line 1
Is there any issue or syntax problem with first line code? I mean this:
<?php if(isset($_REQUEST['url'])): // <-- only include jQuery if url set ?>
Thank you!
UPDATE::
Thank you! I have tried but I think i'm sure some mistakes? :/
<?php if(isset($_REQUEST['url'])):
$str = <<<EOD
<link rel="stylesheet" href="http://code.jquery.com/ui/1.9.2/themes/base/jquery-ui.css" />
<script src="http://code.jquery.com/jquery-1.8.3.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<script>
$(function() {
$( "#dialog-modal" ).dialog({
height: 140,
modal: true
});
});
</script>
EOD;
echo $str;
endif;
?>
"UPDATE"
This is the actual file named headerinclude :
<link rel="alternate" type="application/rss+xml" title="{$lang->latest_threads} (RSS 2.0)" href="{$mybb->settings['bburl']}/syndication.php" />
<link rel="alternate" type="application/atom+xml" title="{$lang->latest_threads} (Atom 1.0)" href="{$mybb->settings['bburl']}/syndication.php?type=atom1.0" />
<meta http-equiv="Content-Type" content="text/html; charset={$charset}" />
<meta http-equiv="Content-Script-Type" content="text/javascript" />
<script type="text/javascript" src="{$mybb->settings['bburl']}/jscripts/prototype.js?ver=1603"></script>
<script type="text/javascript" src="{$mybb->settings['bburl']}/jscripts/general.js?ver=1603"></script>
<script type="text/javascript" src="{$mybb->settings['bburl']}/jscripts/popup_menu.js?ver=1600"></script>
{$stylesheets}
<script type="text/javascript">
<!--
var cookieDomain = "{$mybb->settings['cookiedomain']}";
var cookiePath = "{$mybb->settings['cookiepath']}";
var cookiePrefix = "{$mybb->settings['cookieprefix']}";
var deleteevent_confirm = "{$lang->deleteevent_confirm}";
var removeattach_confirm = "{$lang->removeattach_confirm}";
var loading_text = '{$lang->ajax_loading}';
var saving_changes = '{$lang->saving_changes}';
var use_xmlhttprequest = "{$mybb->settings['use_xmlhttprequest']}";
var my_post_key = "{$mybb->post_code}";
var imagepath = "{$theme['imgdir']}";
// -->
</script>
{$newpmmsg}
I want to add below php code in this file:
<?php if(isset($_REQUEST['url'])): // <-- only include jQuery if url set ?>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.9.2/themes/base/jquery-ui.css" />
<script src="http://code.jquery.com/jquery-1.8.3.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<script>
$(function() {
$( "#dialog-modal" ).dialog({
height: 140,
modal: true
});
});
</script>
<?php endif; ?>
This headerinclude file included in the file Global.php in this way:
// Set up some of the default templates
eval("\$headerinclude = \"".$templates->get("headerinclude")."\";");
eval("\$gobutton = \"".$templates->get("gobutton")."\";");
eval("\$htmldoctype = \"".$templates->get("htmldoctype", 1, 0)."\";");
eval("\$header = \"".$templates->get("header")."\";");
I think you will need this plugin : PHP in Templates / Complex Templates
Because MyBB don't allow to use <?php ... ?> inside the template. But if you use that plugin, you can but it has some limitations (you can see in the link I provide)
This plugin is the most powerful plugin I ever seen for MyBB. For example, if I don't want the guest to see New Thread in forumdisplay.php, I just need to change the template to:
<if $mybb->user['uid'] != 0 then>
<a href="newthread.php?fid={$fid}>New Thread</a>
</if>
Have fun with MyBB!
Apparently, phpBB will put everything inside <?php ?> blocks in an eval. In your case this means it throws
if(isset($_REQUEST['url'])):
in an eval. And that is an unfinished if construct. To fix it, put the entire PHP code inside one <?php ?> block. Use strings handling or HERE documents to do the HTML.
Example HEREDOC:
<?php
if(isset($_REQUEST['url'])):
$str = <<<EOD
... put your HTML here ...
EOD;
echo $str;
endif;
?>

Saving Changes in SlickGrid with php

I have a SlickGrid set up, it is reading data from my database with PHP, my problem is arising when i try to save the data back to my database, I am trying to use JSON to give me an array that I can then use to write back to the database, i have see this thread explaining this:
Saving changes in SlickGrid
So I have the hidden form element in my code, and am using JSON to encode the data variable, the assign it to the data hidden input on the form, this form posts to a page called save_price.php, the trouble is when I print_r, or var_dump the data variable, I get null as an output, I think it might be something to do with how I am using PHP to add the content into the data variable, either that or I am doing something really obviously wrong, hopefully you can see what the problem is, there isn't a great deal of documentation online about retrieving/saving to a db with PHP, so I'm kinda stuck banging my head against the wall on this one, here's my code:
Ok so I found the problem, just incase anyone is struggling to get this all to work, here is the working code, it gets data from a database, then sends the changed data to another page for processing, it nees a little bit of refinements, that will happen once I've got it all implemented:
<?php
include("includes/check_session.php");
require_once('includes/functions.php');
require_once('includes/config.php');
$data = '';
$i = 0;
$query = "
SELECT * FROM `prices`";
$result = mysql_query($query);
while($row = mysql_fetch_array($result, MYSQL_ASSOC)){
$data .= '
data['.$i.'] = {
id: "'.$row['id'].'",
title: "'.$row['title'].'",
duration: "'.$row['duration'].'",
percentComplete: "'.$row['percentComplete'].'",
start: "'.$row['start'].'",
finish: "'.$row['finish'].'",
effortDriven: "'.$row['effortDriven'].'"
};
';
$i++;
echo $data;
}
?>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset=utf-8>
<?php // include("includes/cms_head_scripts.php"); ?>
<link rel="stylesheet" href="css/slick.grid.css" type="text/css" media="screen" charset="utf-8" />
<link rel="stylesheet" href="css/smoothness/jquery-ui-1.8.5.custom.css" type="text/css" media="screen" charset="utf-8" />
<link rel="stylesheet" href="css/examples.css" type="text/css" media="screen" charset="utf-8" />
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script language="javascript" src="js/jquery.json.js"></script>
</head>
<body>
<div id="content_cont">
<div id="main">
<div style="position:relative">
<div style="width:600px;">
<div id="myGrid" style="width:100%;height:500px;"></div>
</div>
</div>
pricing
</div><!-- #main -->
</div><!-- #content_cont -->
<script src="lib/firebugx.js"></script>
<script src="lib/jquery-ui-1.8.5.custom.min.js"></script>
<script src="lib/jquery.event.drag-2.0.min.js"></script>
<script src="slick.core.js"></script>
<script src="plugins/slick.cellrangeselector.js"></script>
<script src="plugins/slick.cellselectionmodel.js"></script>
<script src="slick.editors.js"></script>
<script src="slick.grid.js"></script>
<script type="text/javascript">
var grid;
var data = [];
var columns = [
{id:"title", name:"Title", field:"title", editor:TextCellEditor},
{id:"duration", name:"Duration", field:"duration", editor:TextCellEditor},
{id:"%", name:"% Complete", field:"percentComplete", editor:TextCellEditor},
{id:"start", name:"Start", field:"start", editor:TextCellEditor},
{id:"finish", name:"Finish", field:"finish", editor:TextCellEditor},
{id:"effort-driven", name:"Effort Driven", field:"effortDriven", editor:TextCellEditor}
];
var options = {
editable: true,
enableCellNavigation: true,
asyncEditorLoading: false,
autoEdit: true
};
$(function() {
<?php echo $data ?>
grid = new Slick.Grid($("#myGrid"), data, columns, options);
})
</script>
<form method="POST" action="save_price.php">
<input type="submit" value="Save">
<input type="hidden" name="data" value="">
</form>
<script type="text/javascript">
$(function() {
$("form").submit(
function() {
$("input[name='data']").val($.JSON.encode(data));
}
);
});
</script>
</body>
</html>

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