want to be able to store the current date from PHP in to a mysql table.
$date = sprintf("%'04s-%'02s-%'02s",$year_number,$month_number,$day_number);
$sql="INSERT INTO `prg omran`.`paid`(`Comapny_id`,`Amount`,`Date`,`Creditrecord`) VALUES ('".$ID."','".$credit."','".$date."','".$yes."')";
Date's column type in database is DATE.
but date save in database like this: 0000-00-00
help me.
try this
$date = sprintf("%'04s-%'02s-%'02s",$year_number,$month_number,$day_number);
$sql="INSERT INTO `prg omran`.`paid`(`Comapny_id`,`Amount`,`Date`,`Creditrecord`) VALUES ('".$ID."','".$credit."',".$date.",'".$yes."')";
or
if you want to inset today's date use
$sql="INSERT INTO `prg omran`.`paid`(`Comapny_id`,`Amount`,`Date`,`Creditrecord`)
VALUES ('".$ID."','".$credit."',curdate(),'".$yes."')";
I need to store Date field in database for example VARCHAR(10) becouse, DATE type in mysql server don't support persian (farsi) date.
If you are getting the current date, just use one of the built-in MySQL functions for that:
$sql="INSERT INTO `prg omran`.`paid`(`Comapny_id`,`Amount`,`Date`,`Creditrecord`)
VALUES ('".$ID."','".$credit."',curdate(),'".$yes."')";
You won't ever have to worry about formatting or any sort of funny inputs and you can still do all sorts of addition, subtraction and the like using one of the many other functions.
Edit: I have just looked up some information on the date system and you will run into problems trying to squeeze that data into a date field. The first six months have 31 days, the next 5 have 30 days, then the last has 29 - unless it is a leap year in which case it has 30. The date field simply won't LET you insert these values into a date field.
You might need to convert your data to a timestamp and write a function to encode/decode it into the format you need.
Related
I'm having some troubles dealing with Timestamp data type in MySQL.
I'm saving simple records in my database using a simple DB structure, like:
ID int
Name varchar
Date timestamp
Text varchar
And then retrieve them with something like:
SELECT * FROM table WHERE Date BETWEEN '2013-01-01' AND '2013-06-30'
Everything works fine if I store records letting MySQL fill the Date field with the actual timestamp, for example: 2013-10-04 22:40:02 which means I don't add any value to the Date field in my INSERT query.
But I need to be able to add the date by my self since my application needs to store the date from where the application started, and not the date and time in which the query was sent to the database.
So what I do is I create the same date/time format my Date field uses which is 2013-10-04 22:40:02 and then do a simply insert:
INSERT INTO table (Name, Date, Text)
VALUES ('Peter', '2013-10-04 22:40:02', 'Hello...')
Now, doing it this way I'm unable to bring any result by date using a select query like this one:
SELECT * FROM table WHERE Date BETWEEN '2013-01-01' AND '2013-11-30'
Even if I try to sort results by Date using PHPMyAdmin interface, all the records that contain manually added dates disappear. If I sort them by ID, they re-appear. I checked and the dates and formats are correct. So I have no idea what the problem could be. I'm new at MySQL by the way.
Hope you can give me a hand. Thanks!
Well, I think I found the problem and it has nothing to do with PHP and MySQL, the problem is that I generate the date with JavaScript, and it's giving the wrong month.. :/
Thanks to everyone anyway!
While creating a table, I defined one column of DATE type and one of TIME type. As I insert the values using a php script like :
date--> 2013-11-11
time--> 12:12:12
and when I query the sql browser I see those values in exactly the same manner. But I am unaware of the format with which it stores the date and time. Like yyyy-mm-dd or yyyy-dd-mm.
Is there any way I change it ?
Dates and times are stored in MySQL in the format "YYYY-MM-DD" and "YYYY-MM-DD HH:MM:SS" which is not necessarily the format you want to display in your web page or application. There are two methods to reformat the date and time into the desired format. One is to do it in the SQL query in MySQL calling the DATE_FORMAT() function and the other is to do it with the programming language retrieving the data from the MySQL database.
From MySQL 5.1:
The DATE type is used for values with a date part but no time part.
MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The
supported range is '1000-01-01' to '9999-12-31'.
For second question: you can't change default DATE format for the storage, please see this question also
http://dev.mysql.com/doc/refman/5.5/en/datetime.html
MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format
http://dev.mysql.com/doc/refman/5.5/en/time.html
MySQL retrieves and displays TIME values in 'HH:MM:SS' format
I do not believe this can be changed. But you do not care. You can extract dates and times in the format of your liking with the DATE_FORMAT() and the TIME_FORMAT() functions.
If you want to know the internal storage of Date columns, you can check Date and Time Data Type Representation, but I think you want to select date in different format; which other guys already answered about it.
It is stored in 3 bytes, and it is always YYYY-MM-DD.
The datetime is in Y-m-d H:i:s format, or year month day and hour minute second. If you only use a part, the format stays the same.
If you want to change the format there are many ways. The easiest would be to do something like return date("Y-d-m H:i:s", strtotime($mysqldatetime)); (will turn it to dutch date);
Keep in mind that you are using two seperate columns, one for time and one for the date. If you use only one column the missing values are filled with default values (time would be 00:00:00 and date would be 1970-01-01
I have what is most likely a very simple question.. I am designing a simple blogging system and I am trying to put the current date into the table where the blog post is stored whilst waiting for administrator approval. but the method I have used puts 0000-00-00 into the date column! What I am using is as follows:
$query = "INSERT INTO blogentry VALUES ('".$mnam."','".date('d-m-Y h:m:s') ."\n"."','".$mcom."','".$approve."')";
I am relatively new to php so stumble accross errors like this all the time... but I cant seem to google this one!
Thanks guys!
So the easiest way to do this is just let MySQL handle it with the NOW() function:
INSERT INTO blogentry VALUES( ..., NOW(), ... )
Another option is to use TIMESTAMPs by changing your table - set the column to type TIMESTAMP with DEFAULT CURRENT_TIMESTAMP, and you can just ignore that column when inserting - it will automatically be filled with the current time. You will need to specify the columns you're inserting to in order to skip a column:
INSERT INTO blogentry( column1, column2 ) VALUES( column1value, column2value )
Finally, you NEED to sanitize your inputs. Preferably using prepared statements and PDO (http://php.net/manual/en/pdo.prepared-statements.php), or at least using mysql_real_escape_string.
From the MySQL manual on DATE, DATETIME
The DATE type is used for values with a date part but no time part.
MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The
supported range is '1000-01-01' to '9999-12-31'.
This means you have to insert the dates in YYYY-MM-DD format. You are using date('d-m-Y h:m:s') format. Change that to date('Y-m-d') and it should insert correctly.
If you want the time as well, then you need to change the column datatype to DATETIME and then insert using the format date('Y-m-d H:i:s').
As other mention, you can use an INT column type instead and store a Unix timestamp which is stored in UTC so it is more portable. You can then easily manipulate the timestamp to output the date any way you would like.
Try just storing a strtotime() result. It creates a unique timestamp, which can then be parsed however you need it in the future.
You might need to give the timestamp to the date function:
date('d-m-Y h:m:s', strtotime('now'))
Also, to do a standard datetime format:
date('Y-m-d H:i:s', strtotime('now'))
I have 3 dropdowns on a form for the user to choose their birthday. One for date, one for month and one for year.
Right now I cam preparing the date given by the user like this:
$date = sanitize($_POST['year']).'-'.sanitize($_POST['month']).'-'.sanitize($_POST['day']);
and inserting $date into the database in a DATE field. I want to be able to do operations based on this field's values, like sorting by date etc...
Is this the right way to prepare the data or should there not be any hyphens?
According to the MySQL manual page on DATE, the proper format is 'YYYY-MM-DD', so this appears as if it would work and allow you use all of the MySQL date and date comparison operations and functions.
However, you should consider validating user input before sending it to the database (never trust the security or validity of user input). Maybe you should run it through PHP's date() to make sure that the date you are inserting is valid:
$date = date('Y-m-d', strtotime($_POST['month'].'-'.$_POST['day'].'-'.$_POST['year']));
I agree, I would convert the text using strtotime, then validated it, although you have 3 dropdowns maybe a data like Feb 30 might throw things off.
I had used javascript calender in my form. User have to input a date using this calender. And date is stored in the database but what I need is that only day of a date must be saved.
How can I do that as I cannot make changes in javascript code as i m not good at it.
$date_customer=date("d",strtotime($_POST['datum1']));
I had also tried it by changing the column name to "tinyint" but didn't work :( .... it only stores 127 and shows 1 when record is viewed from database.
Instead of sending date to server you could send the day by using
.getDay() method of javascript Date object.
I dont know the format of your date you get in your text input (when you click on one of the days in your calendar) but i'd suspect it to be dd/mm/yyyy or mm/dd/yyyy
So your php will need to be the following to only get the day
$date = explode("/",$_POST['datum1']);
// if format is dd/mm/yyyy then use the below
$date_customer = $date[0];
// otherwise if format is mm/dd/yyyy then use the below
$date_customer = $date[1];
Check out the explode function
i would save the date in MYSQL as an INT by using this function (save it as a unix timestamp) which would be helpful in comparing dates later on (up to the second) or add/remove days/years/months .
the idea would be send the whole date string generated by javascript to the PHP script "dd/mm/yyyy" ,
then in php using the explode function and create the unix timestamp using the mktime function
then save it to the database as an int ,
then when you want to read it , use the php date function to know the day/month/year/hour/second/minute , you could then also add hours (+3600) or days (+3600*days) etc... , or even get range of dates and many other functionalities you may use later ...
cheers
I suppose that you use mysql (TINYINT are mysql specific).
TINYINT are integer and in php integer are usually not prefixed by zeros
Use a DATE field and format it when you report it.
You can use mysql date_format(date,"%d") function in your query.
Or the php date function.
select date_format(date_field,"%d") from some_table;
You can use a VARCHAR(2) to store the date (ugly).
If you stick to store only the DAY in an int or tynint.
use sprintf("%02d",$day) to format it correctly in php.