echo timestamp in proper day field - php

Question

In mysql I have unix epoch time inserted and it needs to be displayed in calendar like table.
Every timedate should be echoed in row that represents that day.
Code that I have is this and it echoes 31 days in one column and all timestamps in one row. How to put them in correct day/row? Thank you.
<table>
<tr>
<td><strong>day</strong></td>
<td><strong>timestamp</strong></td>
</tr>
<?php
$sel = "select time from rv where id=$id";
$rez = mysql_query($sel) or die(mysql_error());
$n = mysql_num_rows($rez);
for($day=1; $day<32; $day++){
echo "<tr>";
echo "<td>$day.</td>";
while ($re = mysql_fetch_array($rez)){
$time_b = $re["time"];
$time_a = new DateTime("#$time_b");
echo "<td>";
echo $time_a->format('h:i:s');
echo "</td>";
}
echo "</tr>";
}
?>
</table>
Update:
Here is what I get now. And I need every date to be displayed in correct day/row
http://s3.postimg.org/nvmlf1mtv/test.jpg

Answer 1

Supposing you want your days from the database sorted from 1-31, your working the wrong way rond.
You first want to sort the values from the database, store by day and then display them.
Warning: I'm using your code for this answer, but DON'T USE mysql, use mysqli.
//make an array with all 31 days
$mydays=array_fill(1,31,array());
//loop the database results and fill the array
while ($re = mysql_fetch_array($rez)){
$day=date('d',$re["time"]);
//store the value in the $mydays array
$mydays[$day][]=$re["time"];
}
//now loop the days and display them
for($i=1;$i<32;$i++){
if(count($mydays[$i])<1)continue; //the is no data in this day
// else loop the data inside this day
foreach($mydays[$i] as $thisday){
echo "<tr>";
echo "<td>$i</td>";
echo "<td>";
echo date('h:i:s',$thisday);
echo "</td>";
echo "</tr>"
}
}