Something not working as expected in this PHP function - php

Question

I am trying to pull data from MySQL and this supposed to show complete data but this is showing only one row. This is supposed to show all rows of users. I don’t know what I did wrong:
Here is the code:
function getCashoutRequests($uid, $limit) {
if (!empty( $limit )) {
$query = mysql_query( '' . 'SELECT * FROM cashouts WHERE uid = ' . $uid . ' ORDER BY id DESC LIMIT ' . $limit );
}
else {
$query = mysql_query( '' . 'SELECT * FROM cashouts WHERE uid = ' . $uid . ' ORDER BY id DESC' );
}
if (mysql_num_rows( $query )) {
if ($row = mysql_fetch_object( $query )) {
$row->id;
$amount = $row->amount;
$status = $row->status;
$client_notes = nl2br( $row->user_notes );
$admin_notes = nl2br( $row->admin_notes );
$request_date = $row->request_date;
$payment_date = $row->payment_date;
$fee = $row->fee;
$priority = $hid = $row->priority;
$method = $row->method;
if ($payment_date != '0000-00-00 00:00:00') {
$payment_date = date( 'd M, Y', strtotime( $payment_date ) );
}
$request_date = date( 'd M, Y', strtotime( $request_date ) );
$payHistory []= array( 'id' => $hid, 'cash' => $amount, 'status' => $status, 'method' => $method, 'client_notes' => $client_notes, 'admin_notes' => $admin_notes, 'date' => $request_date, 'payment_date' => $payment_date, 'fee' => $fee, 'priority' => $priority );
}
return $payHistory;
}
return false;
}

Answer 1

On this line you have if:
if ($row = mysql_fetch_object( $query )) {
If you use if that would only go to the first value since if simply tests a condition once. Instead try while like this:
while ($row = mysql_fetch_object( $query )) {
As explained in the PHP manual entry for while:
The meaning of a while statement is simple. It tells PHP to execute
the nested statement(s) repeatedly, as long as the while expression
evaluates to TRUE.