PHP: accessing mysqli result by record id - php

i'm having an array which contains record ids as follows:
Array
(
[0] => 113
[1] => 43
[2] => 64
)
so for achieving the corresponding records, i'd have to run 3 queries:
select * from mytable where id=113
select * from mytable where id=43
select * from mytable where id=64
my question: wouldn't it be possible executing just ONE query on the whole table then directly access the mysqli result like an associative array by passing the ID?
something like $record = $res['id'][113];?
thanks in advance

You need the IN clause
SELECT * FROM mytable WHERE id IN ( 113,43,64 );

Custom function indexme takes an array of arrays (numeric or associative) and by default gets the first element value of each sub-array and makes it the associative index in a return array. Optionally, a column name can be passed as the second parameter to designate which column value to use for the index.
$array = array(array('id' => 12, 'name' => 'Joe'), array('id' => 9, 'name' => 'Jane'));
$array_keyed = indexme($array);
// > array(12 => array('id' => 12, 'name' => 'Joe'), 9 => array('id' => 9, 'name' => 'Jane'));
print $array_keyed[12]['name'];
// > Joe
function indexme($arr, $key = '') { // <- custom function indexme
$return_arr = array();
if ( '' == $key ) {
$keys = array_keys($arr[0]);
$key = $keys[0];
}
foreach ( $arr as $value ) {
$return_arr[$value[$key]] = $value;
}
return $return_arr;
}
Pass the mysqli response to this function to make an ID indexed array:
$results_keyed = indexme($result->fetch_assoc(), 'id');
Check out the accepted answer on this page MySQL Prepared statements with a variable size variable list for a nice solution to the WHERE IN technique.

Related

how to turn this function to be recursive with multiple dimensional array?

Hello I am think about how to build this array with a recursive function with a lot of layer.
So the data would like that.
id belongs_to
1a NULL
2a NULL
3a 1a
4a NULL
5a 2a
And non-recursive function like:
foreach ($first_layer as $first_layer_obj) {
$array[$first_layer_obj->id] = [];
$second_layer = /* SELECT id FROM client WHERE belongs_to $first_layer_obj->id */;
foreach ($second_layer as $second_layer_obj) {
$array[$first_layer_obj->id][$second_layer_obj->id] = [];
$third_layer = /* SELECT id FROM client WHERE belongs_to $second_layer_obj->id */;
foreach ($third_layer as $third_layer_obj->id) {
$array[$first_layer_obj->id][$second_layer_obj->id][$third_layer_obj->id] = [];
}
}
I am expecting the output is:
array(3) {
["1a"]=>
array(1){
["3a"]=>[]
}
["2a"]=>
array(1){
["5a"]=>[]
}
["4a"]=>[]
}
Certainly the first piece of advice that I have is, you should avoid performing recursive/iterated calls to your database. You should make a single call to extract all of the desired rows in a single result set and let php do the hard part.
I've decided to try a non-recursive approach. To permit this, the result set must be prepared so that "grander" children are listed first. Now, I realize that it is entirely possible that your sample data doesn't actually represent your project values and sorting cannot be used to prepare the result set adequately -- you'll have to let me know (and perhaps update your question with more accurate sample data).
[see inline comments for what's happening in my script]
*If you aren't using php7+, then my null coalescing operator ($row1['children'] ?? []) will cause issues. You can use: (isset($row1['children']) ? $row1['children'] : []
Code: (Demo)
// use ORDER BY belongs_to DESC, id ASC ... or usort() to prepare result set
$resultset = [
['id' => '6a', 'belongs_to' => '5a'],
['id' => '5a', 'belongs_to' => '3a'],
['id' => '8a', 'belongs_to' => '3a'],
['id' => '3a', 'belongs_to' => '1a'],
['id' => '1a', 'belongs_to' => null],
['id' => '2a', 'belongs_to' => null],
['id' => '4a', 'belongs_to' => null],
['id' => '7a', 'belongs_to' => null]
];
foreach ($resultset as $index1 => &$row1) { // make input array modifiable by reference (not working with a copy)
if ($row1['belongs_to']) { // original belongs_to value is not null (not a top-level parent)
foreach ($resultset as $index2 => $row2) { // search for targeted parent
if ($row2['id'] == $row1['belongs_to']) { // parent found
$resultset[$index2]['children'][] = [$row1['id'] => $row1['children'] ?? []]; // store original row as child
unset($resultset[$index1]); // remove original row (no reason to iterate it again in outer loop)
break; // halt inner loop (no reason to iterate further)
}
}
} else { // original belongs_to value is null (top-level parent)
$output[$row1['id']] = $row1['children'] ?? []; // store children to top
}
}
var_export($output);
Output:
array (
'1a' =>
array (
0 =>
array (
'3a' =>
array (
0 =>
array (
'5a' =>
array (
0 =>
array (
'6a' =>
array (
),
),
),
),
1 =>
array (
'8a' =>
array (
),
),
),
),
),
'2a' =>
array (
),
'4a' =>
array (
),
'7a' =>
array (
),
)

Force json_encode to return array instead objects

I've been wondering if it's possible to force json_encode into returning Array instead an Object while still keeping the "integer" index.
What am I trying to achieve if you're asking is an array of usernames ( with their userID's as keys in the array ).
So if I have a list of mutual friends like this in PHP:
1 => 'John Doe',
2 => 'Jane Doe',
5 => 'Oliver Natefield',
11 => 'Chris Cole'
I'd like to use json_encode and I tried two methods.
First one is by simply adding into an empty PHP Array, values to their respective index ( userID ).
<?php
$list = array( );
foreach ( $friends as $userID => $name )
$list[ $userID ] = $name;
echo json_encode( $list );
?>
That creates me an Object sadly. Ok, then I tried something else...
<?php
$list = array( );
foreach ( $users as $userID => $name )
array_splice( $list, $userID, 0, $name );
echo json_encode( $list );
?>
Again, failed, this time, it's an Array, but the indexes are not taken into consideration.
I know that.. the array should be like :
undefined, // userID 0
'John Doe', // userID 1
'Jane Doe', // userID 2
undefined, // userID 3
undefined, // userID 4
'Oliver Natefield', // userID 5
undefined, //userID 6
undefined, // etc
But... if I have a friend with userID with the index 1504 .. shouldn't there be a memory downside ?
And while we're at it, can I see how much memory does an array of 1000 undefined elements use ? It's relevant because if it consumes too much memory, I'll just have to search through an array of objects for a username after a specific userID.
This is not really possible. It's a restriction of Javascript syntax, which is basically what JSON is. You can't specify array keys in a Javascript "shortcut" array definition, like you can with PHP. e.g.
$foo = array(1 => 'a', 10 => 'b');
There's no such notation in JS, the only shortcut allowed is
foo = ['a', 'b'];
which would give you the PHP equivalent 0 => 'a', 1 => 'b'. To use non-sequential array keys, you MUST use an Object:
foo = {1: 'a', 10: 'b'};

Access specific row in mysql recordset

I have a database table with options that looks like this
I do a SELECT * FROM options and load all records into a recordset.
How do I then access just the optionValue of optionName = SMSactive
[EDIT]
Yes, I could do SELECT * FROM options WHERE optionName ='SMSactive' - I know that.
But as I said, since I have a recordset with a bunch of rows in it (from the SELECT), I want to pull a specific row where optionName = SMSactive
[EDIT]
If you are using PHP >= 5.5 you can use array_column() http://php.net/array_column
But if not, the question has already been asked and answered here PHP multidimensional array search by value
To access to all records with optionName = SMSactive the SQL should be:
SELECT * FROM `TableName` WHERE `optionName` = 'SMSactive'
if your array result from the query is something like this:
$array = array(
0 => array(
'optionName' => 'lala0',
'optionDescription' => 'lala01',
'optionValue' => 'lala03',
),
1 => array(
'optionName' => 'lala1',
'optionDescription' => 'ala2',
'optionValue' => 'SMSactive',
)
);
You can grab who has 'optionValue' => 'SMSactive', by this way
foreach ($array as $key) {
if ($key['optionValue'] == 'SMSactive') {
$filtered[]=$key;
}
}
echo '<pre>';
print_r($filtered);
echo '</pre>';
Side Note: If the array is very large you have to be careful with the memory...it's advisable just get from the db what you are using in the moment...IMO

Create array from mysql query. Column2 as key Column 1 as value

I have a table that contains
column 1 = state column 2 = link
Alabama auburn.alabama.com
Alabama bham.alabama.com
Alabama dothan.alabama.com
I need to grab from my database table and put into an array that i can array_walk() through. they need to be accessed like this array.
$arraytable = array(
"auburn.alabama.com"=>"Alabama",
"bham.alabama.com"=>"Alabama",
"dothan.alabama.com"=>"Alabama",
);
I have tried everything but not sure how make this work using php to print the array like such. Any help is greatly appreciated.
Note Your question title is inconsistent with your example. In the title you ask for column 1 as the key, but your example uses column 2 as the key. I've used column 2 here...
It isn't clear what MySQL API you are using to fetch, but whichever it is, use the associative fetch method and create new array keys using the pattern $arraytable[$newkey] = $newvalue. This example would be in object-oriented MySQLi:
$arraytable = array();
while($row = $result->fetch_assoc()) {
// Create a new array key with the 'link' and assign the 'state'
$arraytable[$row['link']] = $row['state'];
}
You can use array_column for this, since PHP5.5 (http://php.net/array_column)
Description
array array_column ( array $array , mixed $column_key [, mixed $index_key = null ] )
array_column() returns the values from a single column of the array, identified by the column_key. Optionally, you may provide an index_key to index the values in the returned array by the values from the index_key column in the input array.
For PHP < 5.5:
https://github.com/ramsey/array_column/blob/master/src/array_column.php
To implement AcidReign's suggestion, here is the snippet:
Code: (Demo)
$resultset = [
['state' => 'Alabama', 'link' => 'auburn.alabama.com'],
['state' => 'Alabama', 'link' => 'bham.alabama.com'],
['state' => 'Alabama', 'link' => 'dothan.alabama.com']
];
var_export(array_column($resultset, 'state', 'link'));
// ^^^^-- use this column's data for keys
// ^^^^^-- use this column's data for values
Output:
array (
'auburn.alabama.com' => 'Alabama',
'bham.alabama.com' => 'Alabama',
'dothan.alabama.com' => 'Alabama',
)
However, array_column() won't directly work on a result set object, but a foreach() can immediately access the data set using array syntax without any fetching function calls.
Body-less foreach: (Demo)
$result = [];
foreach ($mysqli->query('SELECT * FROM my_table') as ['link' => $link, 'state' => $result[$link]]);
var_export($result);
Or a foreach with a body: (Demo)
$result = [];
foreach ($mysqli->query('SELECT * FROM my_table') as $row) {
$result[$row['link']] = $row['state'];
}
var_export($result);
All of the above snippets return:
array (
'auburn.alabama.com' => 'Alabama',
'bham.alabama.com' => 'Alabama',
'dothan.alabama.com' => 'Alabama',
)

Retrieve value of child key in multidiensional array without knowing parent key

Given this multidimensional array, I'm trying to retrieve the value of one of the child keys:
$movieCast = Array(
'1280741692' => Array(
...
, 'userid' => 62
, 'country_id' => '00002'
...
)
, '1280744592' => Array(
...
, 'userid' => 62
, 'country_id' => '00002'
...
)
)
How can I retrieve the value of country_id?
The top-level array key could be anything and the value of country_id will always be the same for a specific user. In this example, user #62's country_id will always be 00002.
You have to iterate through the outer array:
foreach ($outer as $inner) {
//do something with $inner["country_id"]
}
Another option is to build an array with the contry_ids (example uses PHP >=5.3 functionality, but that can be worked around easily in earlier versions):
array_map(function ($inner) { return $inner["country_id"]; }, $outer);
EDIT If the ids are all the same, even easier. Do:
$inner = reset($outer); //gives first element (and resets array pointer)
$id = $inner["country_id"];
a more general-purpose solution using php 5.3:
function pick($array,$column) {
return array_map(
function($record) use($column) {
return $record[$column];
},
$array
);
}
You need to use this:
array_column($movieCast, 'country_id')
The result will be:
array (
0 => '00002',
1 => '00002',
)

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