SELECT duplicate columns in MYSQL database PHP - php

Question

I have a database table titled products.
I have 2 columns in the table titled name and image
I have 4 entries in my database
item 1 | image1.jpg
item 2 | image1.jpg
item 3 | image1.jpg
item 4 | image2.jpg
I need to display the results on a page but I only need to display image.1jpg once, my while() loop is obviously displaying all 4 images.
I've been at this for hours, please help!
My code:
$query = mysql_query("SELECT * FROM products WHERE page='Birthdays' ORDER BY id ASC");
while($fetch = mysql_fetch_assoc($query)){
$image = $fetch['image'];
$name = $fetch['name'];
echo ''.$name.'';
echo '<img src="'.$thumbnail_image.'"/>';
}

Answer 1

What you need is using GROUP BY in your query. So change the query as
SELECT * FROM products WHERE page='Birthdays' GROUP BY image ORDER BY id ASC

Answer 2

Try the code below;
$query = mysql_query("SELECT * FROM products WHERE page='Birthdays' GROUP BY image ORDER BY id ASC");
while($fetch = mysql_fetch_assoc($query)){
$image = $fetch['image'];
$name = $fetch['name'];
echo ''.$name.'';
echo '<img src="'.$thumbnail_image.'"/>';
}

Answer 3

You can also use a trick like not using while statement at all. If you just write the
$fetch = mysql_fetch_assoc($query) without while you would just get the first result in the query. I hope this helps.