How to access a model method with javascript - php

Question

Please have a look at the below CakePHP code
Flip2.php (Model)
<?php
class Flip2 extends AppModel {
var $name = 'Flip2';
public $useTable = false;
//Increment the correct_answer field of the specific user
public function correctAnswer($userID=89, $word)
{
$setQuery = "UPDATE `users_words` SET `correctanswer` = `correctanswer`+1 WHERE `userid`=$userID && `wordid`='$word' ";
query($setQuery);
}
}
Flip2Controller.php (Controller)
<?php
class Flip2Controller extends AppController {
public function index()
{
}
}
?>
index.ctp (View)
<?php
//echo $this->Html->css(array('bootstrap', 'mark', 'style'));
echo $this->Html->script(array('timer','swfobject','bootstrap.min.js'));
?>
<style>
#hideall {
display: none;
opacity: 0.7;
position: fixed;
height: 100%;
width: 100%;
top: 0;
left: 0;
background: #000;
border: 1px solid #cecece;
z-index: 1;
vertical-align:middle;
text-align:center;
}
.removeCardflip{
transition: rotateY(0deg);
-webkit-transition: rotateY(0deg);
transition-duration: 0s;
}
/* SECTIONS */
.section {
clear: both;
padding: 0 10px 0 10px;
margin: 0px;
}
</style>
<div id="hideall">
<?php //echo $this->Html->image('progress.gif', array('alt' => 'Wait', 'style' => 'text-align:center; padding-top:200px;'));?>
</div>
<!--<div class="wrapper" style="border: 1px solid red; width: 100%;">-->
<div class="section group" style="margin-top: 50px;">
<div class="col span_3_of_3">
<h3 style="margin:0px; font-size:22px;">Play word game: </h3>
</div>
</div>
<div class="">
<div>
<div>
<span class="remainWords"><?php //echo count($words);?></span> oxxxxxxxxxxxxxxxf <?php //echo $totalWords;?>
</div>
<div>
<?php
echo $this->Html->image("comic_edit.png",
array(
"alt" => "Pareto List",
"id" => "paretoList",
'url' => "javascript:;"
)
);
?>
</div>
</div>
</div>
<div class="container"><div class="row">
<?php
foreach($worddeck as $worcard)
{
?>
<div class="xy col-lg-3 col-md-4 col-sm-6 img-rounded" id="card1" style="width:250px; height:200px; background-color:grey; heiht:170px; margin: 10px 10px;">
<div id="enside1" >
<h1 data-pos="<?php //echo ; ?>" ><?php echo $worcard['unique_wordsforcards']['en_word']; $enSpell = $worcard['unique_wordsforcards']['en_word']; ?></h1>
</div>
<div id="ptside1" style="display:none;">
<?php echo $phonemer[$enSpell]; ?>
<p><?php echo $worcard['unique_wordsforcards']['hint']; ?></p>
</div>
<div id="cntrol1">
<button type="button" id="2" class="a btn btn-success mr5 btn-lg">Acertei</button>
<button type="button" id="2" class="e btn btn-danger mr5 btn-lg">Errei</button>
</div>
</div>
<?php
}
?>
</div></div>
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script type="text/javascript">
$(document).ready(function(){
$( ".btn-danger" ).click(function(){
console.log("Red Button");
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
console.log( "The act has been done");
toclose.toggle();
});
});
$( ".btn-success" ).click(function(){
console.log("Red Button");
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
console.log( "The act has been done");
toclose.toggle();
});
});
$( ".xy" ).click(function(){
$(this).find("#enside1").toggle();
$(this).find("#ptside1").toggle();
console.log(this);
});
});
</script>
Now, what I need to do is, this. When the user click on the Acertei button, I need to execute the function correctAnswer. I am very new to PHP and CakePHP so I am really confused about how to do this when a button is clicked. Any advice please?

Answer 1

You have
<div id="cntrol1">
<button type="button" id="2" class="a btn btn-success mr5 btn-lg">Acertei</button>
<button type="button" id="2" class="e btn btn-danger mr5 btn-lg">Errei</button>
</div>
You should use different IDs for each button.
You can call the correctAnswer function with ajax:
Change the button to something like
<button type="button" id="2" data-word="<?php $worcard['unique_wordsforcards']['en_word'] ?>" class="a btn btn-success mr5 btn-lg">Acertei</button>
And then add the following code in $(document).ready()
$(document).ready(function(){
$(".btn-success").click(function(){
var word = $(this).data('word');
$.post('/flip2/correct.json', { word: word })
.done(function(data) {
alert('Saved');
});
I am not sure how the user part works. You should probably have that in the session, and not sent to the function. I hardcoded user 89 and added a way for you to send the word.

Answer 2

Use an appropriate model method
The function correctAnswer in the model would better be written using updateAll:
public function correctAnswer($userId, $word) {
return $this->updateAll(
array('correctanswer' => 'correctanswer + 1'),
array(
'userid' => $userId,
'wordid' => $word
)
);
}
Written in this way the inputs ($userId and $word) will be escaped appropriately and not susceptible to sql injection.
Create a controller action
The doorway to the web for an application is a controller action, create a simple function, calling the model method, and write it to output json:
public function correct() {
$postData = $this->request->data;
$word = $this->request->data['word'];
$userId = $this->Auth->user('id');
$result = false;
if ($userId && $word) {
$result = $this->Flip2->correctAnswer($userId, $word);
}
$this->set('_serialize', array('result'));
$this->set('result', $result);
}
Note that
It'll only work via a post request.
The Auth component (the session) is used to get the current user id, it's not a user-defined input.
This function is defined such that it'll work as a json response.
There's no need to create a view file with the above code.
Be sure to setup your app to handle json requests:
After adding Router::parseExtensions('json'); to your routes file, CakePHP will automatically switch view classes when a request is done with the .json extension, or the Accept header is application/json.
Call the controller action
The required js would be of the form:
$(".btn-success").click(function(){
var word = ...;
$.post(
'/flip2/correct.json',
{word: word},
function (data) {
console.log(data);
// {result: bool}
}
);
});
Note that:
The url ends in .json which is a simple and robust way to provoke CakePHP to respond as json.
It is a post request.
The response will be of the form defined by _serializein the controller action.