merging mutidimensional arrays - php

Question

I have an array that looks like this:
getting array need to convert array as same key value as 0
foreach($array as $key=>$id){
$consumer_data[]=$this->App_model->get_session($id);
}
print_r($consumer_data);
Array
(
[0] => Array
(
[0] => Array
(
[ConsumerID] => 1
[name] => asdfd
)
[1] => Array
(
[ConsumerID] => 5
[name] => test
)
[2] => Array
(
[ConsumerID] => 3
[name] => test1
)
)
[1] => Array
(
[0] => Array
(
[ConsumerID] => 4
[name] => test4
)
)
i want to implement array like this in same key value as 0
Array
(
[0] => Array
(
[0] => Array
(
[ConsumerID] => 1
[name] => asdfd
)
[1] => Array
(
[ConsumerID] => 5
[name] => test
)
[2] => Array
(
[ConsumerID] => 3
[name] => test1
)
[3] => Array
(
[ConsumerID] => 4
[name] => test4
)
)
I am using PHP. Can anyone point me to a good starting point as to how I should go about doing this?

Answer 1

You can use array_merge():
$new_array[0] = array_merge($array[0], $array[1]);
Where $array is the first array.
SEE DEMO
OR for a more dynamic approach:
$new_array = array(0 => array());
foreach($array as $a) {
$new_array[0] = array_merge($new_array[0], $a);
}
SEE DEMO 2

Answer 2

The simpliest solution is to do it with:
$input = array(
array(
array('ConsumerID' => 1, 'name' => 'asdfd'),
array('ConsumerID' => 5, 'name' => 'test'),
array('ConsumerID' => 4, 'name' => 'test1'),
),
array(
array('ConsumerID' => 4, 'name' => 'test4'),
),
);
$output = array(
array()
);
foreach ($input as $data) {
$output[0] = array_merge($output[0], $data);
}

Answer 3

Try this->
$newArray = array();
foreach($values as $key=>$val){
$newArray [0][$key]=$val;
}
print_r($newArray);

Answer 4

Check this:
<?php
$arr[0] = array(0 => array("ConsumerID" => 1, "name" => "Ni"), 1 => array("ConsumerID" => 2, "name" => "Ab"));
$arr[1] = array(1 => array("ConsumerID" =>5, "name" => "GE"), 1 => array("ConsumerID" => 6, "name" => "DB"));
$new = array();
foreach($arr as $key => $value) {
foreach($value as $innerkey => $innervalue) {
$new[0][] = $innervalue;
}
}
print_r($new);
?>