php if pg true show button on navigation bar - php

Question

I want a button to show on my navigation bar only if the page is = to employees.
I was doing this to accomplish this.
on employees.php
<?php $pg = employees; ?>
on header.php
<?php
if ($pg == $employees)
?>
<?php
<a class="btn btn-info" href="https://www.ebillity.com/Firm4.0/Login.aspx?CorpLogin=1">Time Sheets</a>
?>
Here is the error im getting in the browser
Parse error: syntax error, unexpected '<' in /Applications/XAMPP/xamppfiles/htdocs/lpnew/includes/header.php on line 60

Answer 1

You have done some typing errors, so you have got an error
on employees.php
<?php $pg = $employees; ?>
on header.php
<?php
if($pg == $employees){
?>
<a class="btn btn-info" href="https://www.ebillity.com/Firm4.0/Login.aspx?CorpLogin=1">Time Sheets</a>
<?php } ?>

Answer 2

The error you are getting is because you aren't using echo on your link and you need to swap your double quotes for single quotes.
Try this for your link:
echo "<a class='btn btn-info' href='https://www.ebillity.com/Firm4.0/Login.aspx?CorpLogin=1'>Time Sheets</a>";
It looks like your if statement is not finished either you don't have anything in {}. It also appears you are trying to call the current page? I'm making a few assumptions but try this:
if (basename($_SERVER['PHP_SELF'])== 'employee.php'){
//do something
}
else{
//do something else
}