Heres my table:
Table: category
----------------
id | category
------------------
1 | category1
2 | category2
3 | category3
4 | category4
5 | category5
-
Table: news
------------------------------
id | title | category_id
------------------------------
1 | title 1 | 1
2 | title 2 | 2
3 | title 3 | 4
4 | title 4 | 5
5 | title 5 | 3
6 | title 6 | 3
7 | title 7 | 2
8 | title 8 | 5
9 | title 9 | 1
10| title 10 | 4
11| title 11 | 1
12| title 12 | 2
how to get mysql result like this:
(note: each category (1-5) assigned with one title only, then repeat again the cycle of category.)
I have tried using `group by order by.
Category 1 ===
title 1
Category 2
title
Category 3
title 5
Category 4
title 3
Category 5
title 4
Category 1 ===
title 9
Category 2
title
category 3
title 6
category 4
title10
category 5
title 8
category 1 ===
title 11
category 2
title 12
If you want to build such format using PHP, alternatively, you could use a while loop to create it. Consider this example:
First off, you need to properly query those values together, you can use join
// SAMPLE => SELECT * FROM `category`
// LEFT JOIN `news` ON `news`.`category_id` = `category`.`id`
Sample Output: SQL HERE
Secondly, after getting the values, you need to order them, In this case, (1, 2, 3, 4, 5)
Consider this example:
$results_from_db = array(
array('id' => 1, 'category' => 'category1', 'title' => 'title 1', 'category_id' => 1),
array('id' => 1, 'category' => 'category1', 'title' => 'title 9', 'category_id' => 1),
array('id' => 1, 'category' => 'category1', 'title' => 'title 11', 'category_id' => 1),
array('id' => 2, 'category' => 'category2', 'title' => 'title 2', 'category_id' => 2),
array('id' => 2, 'category' => 'category2', 'title' => 'title 7', 'category_id' => 2),
array('id' => 2, 'category' => 'category2', 'title' => 'title 12', 'category_id' => 2),
array('id' => 3, 'category' => 'category3', 'title' => 'title 5', 'category_id' => 3),
array('id' => 3, 'category' => 'category3', 'title' => 'title 6', 'category_id' => 3),
array('id' => 4, 'category' => 'category4', 'title' => 'title 3', 'category_id' => 4),
array('id' => 4, 'category' => 'category4', 'title' => 'title 10', 'category_id' => 4),
array('id' => 5, 'category' => 'category5', 'title' => 'title 4', 'category_id' => 5),
array('id' => 5, 'category' => 'category5', 'title' => 'title 8', 'category_id' => 5),
);
$ids = array();
foreach($results_from_db as $value) {$ids[] = $value['id'];}
$ids = array_values(array_unique($ids));
sort($ids);
$needle_key = 0;
// build the data (kinda like recursive searching)
$data = array();
while(true) {
$current_value = array_shift($results_from_db);
if($current_value['category_id'] == $ids[$needle_key]) {
$data[] = $current_value;
$needle_key++;
if($needle_key > count($ids)-1) {
$needle_key = 0; // resetter
}
} else {
array_push($results_from_db, $current_value);
}
if(empty($results_from_db)) {
break;
}
}
?>
<!-- if you want to echo -- >
<?php foreach($data as $key => $value): ?>
<?php echo '<strong>'.$value['category'].'</strong><br/>'; ?>
<?php echo str_repeat(' ', 8) . $value['title'].'<br/><br/>'; ?>
<?php endforeach; ?>
Should output something like this: Sample Fiddle
category1
title 1
category2
title 2
category3
title 5
category4
title 3
category5
title 4
category1
title 9
category2
title 7
category3
title 6
category4
title 10
category5
title 8
category1
title 11
category2
title 12
Related
Please help me how to add another nested group by based on game category relation. I have 3 tables related using laravel 5.4 eloquent.
Game Providers Table
+----+-------------+--------------+------------------+
| id | game_name | game_type_id | game_category_id |
+----+-------------+--------------+------------------+
| 1 | Sample | 1 | 1 |
| 1 | Sample 0 | 1 | 2 |
| 2 | Sample 1 | 2 | 1 |
| 3 | Sample 2 | 2 | 2 |
+----+-------------+--------------+------------------+
Game Types
+----+-------------+
| id | name |
+----+-------------+
| 1 | Chess |
| 2 | Poker |
+----+-------------+
Game Categories
+----+-------------+
| id | name |
+----+-------------+
| 1 | Recommended |
| 2 | Optional |
+----+-------------+
I'm done of for first nested for game type relation but i dont know how to add another group by for game categories
$game_providers = GameProvider::all();
$game_providers = $game_providers->groupBy(function ($game_provider) {
return $game_provider->game_type->name;
})->all();
and its output
Array{
'Chess' => Array{
0 => Array{
'id' => 1,
'game_name' => 'Sample',
'game_type_id' => 1,
'game_category_id' => 2
},
1 => Array{
'id' => 2,
'game_name' => 'Sample 0',
'game_type_id' => 1,
'game_category_id' => 2
},
},
'Poker' => Array{
0 => Array{
'id' => 3,
'game_name' => 'Sample 1',
'game_type_id' => 2,
'game_category_id' => 1
},
1 => Array{
'id' => 4,
'game_name' => 'Sample 2',
'game_type_id' => 2,
'game_category_id' => 2
},
},
}
My expected output
Array{
'Chess' => Array{
'Recommended' => Array{
0 => Array{
'id' => 1,
'game_name' => 'Sample',
'game_type_id' => 1,
'game_category_id' => 2
}
},
'Optional' => Array{
0 => Array{
'id' => 2,
'game_name' => 'Sample 0',
'game_type_id' => 1,
'game_category_id' => 2
}
}
},
'Poker' => Array{
'Recommended' => Array{
0 => Array{
'id' => 3,
'game_name' => 'Sample 1',
'game_type_id' => 2,
'game_category_id' => 1
}
},
'Optional' => Array{
0 => Array{
'id' => 4,
'game_name' => 'Sample 2',
'game_type_id' => 2,
'game_category_id' => 2
}
}
}
}
With L5, one way of acieving this can be:
GameProvider::with('game_categories.game_types')
->get()
->groupBy([
'gameTypes.name',
'gameCategories.name'
]);
Should be something along the lines of :
GameProvider::with('game_categories.game_types')->get()->map(function ($game) {
return $game->game_categories->groupBy('name')->map(function ($catGame) {
return $catGame->map(function ($category) {
return $category->game_types->groupBy('name');
});
});
});
I need your help. Maybe it's all about logical. So my case is:
I have mySql tables, they are:
record table
_______________________________________
Student ID | Question ID | Answer
_______________________________________
1 | 1 | A
2 | 1 | C
3 | 1 | E
1 | 2 | D
2 | 2 | B
3 | 2 | A
....... | .......... | ........
_______________________________________
and student table:
_________________________________
Student ID | Student Name
_________________________________
1 | Ronaldo
2 | Messi
3 | Neymar
.......... | .............
_________________________________
And I want to echoing them in my report page with table like this:
_________________________________________________
Student | Question and Answer
|____________________________________
| 1 | 2 | 3 | ... | ... | ... | ... |
_________________________________________________
Ronaldo | A | D | ...........................
Messi | C | B | ...........................
Neymar | E | A | ...........................
........ | ...................................
_________________________________________________
I use PHP so I repeat with foreach(){} function. But how to echoing data vertically and horizontally in once query?
Sorry for my bad php knowledge and logical. Thanks for your attention.
A simple way to do it (but by no means the only one) :
First fetch your users along with their answers :
SELECT
s.id AS student_id,
s.name AS student_name,
q.question_id,
q.answer
FROM
students AS s
INNER JOIN
questions AS q
ON
s.id = q.student_id;
You should get rows like that :
array(
'student_id' => '1',
'student_name' => 'Ronaldo',
'question_id' => 1,
'answer' => 'A',
)
OR
array(
'student_id' => '2',
'student_name' => 'Messi',
'question_id' => 1,
'answer' => 'C',
),
You could then loop through them to reorganize them :
$data = array();
foreach($rows as $row){
if(!isset($data[$row['student_id']])){
$data[$row['student_id']] = array(
'student_name' => $row['student_name'],
'questions' => array(),
);
}
$data[$row['student_id']]['questions'][] => array(
'question_id' => $row['question_id'],
'answer' => $row['answer'],
);
}
Which will give you this array :
$data = array(
'1' => array(
'student_name' => 'Ronaldo',
'questions' => array(
array(
'question_id' => 1,
'answer' => 'A',
),
array(
'question_id' => 2,
'answer' => 'D',
),
),
),
'2' => array(
'student_name' => 'Messi',
'questions' => array(
array(
'question_id' => 1,
'answer' => 'C',
),
array(
'question_id' => 2,
'answer' => 'B',
),
),
),
);
Finally, loop through the last array to display data the way you want :
foreach($data as $student){
echo $student['student_name'] . ' : ' ;
foreach($student['questions'] as $question){
echo 'Question ' . $question['question_id'] . ' : ' . $question['answer'] . "\n";
}
}
You will need to do some adaptation to suit your need.
I need help with an application I'm creating.
I have a table, looks kind like this:
+----+-----------+---------+
| id | parent_id | name |
+----+-----------+---------+
| 1 | null | test |
+----+-----------+---------+
| 2 | null | test2 |
+----+-----------+---------+
| 4 | 1 | test3 |
+----+-----------+---------+
| 5 | 2 | test4 |
+----+-----------+---------+
And now, I get all the data in one array. I would like to get kinda this structure (php array as an cascade):
array(
0 => array(
'id' => 1,
'parent_id' => null,
'name' => 'test',
'children' => array(
'id' => 4,
'parent_id' => 1,
'name' => 'test3'
)
),
1 => array(
'id' => 2,
'parent_id' => null,
'name' => 'test2',
'children' => array(
'id' => 5,
'parent_id' => 2,
'name' => 'test4'
)
)
)
So there will every entry with a "parent_id=null" be a parent, and every entry with an id in "parent_id" will be in a child array.
I started it like this:
$newArray = array();
foreach($names as $name) {
if($name['parent_id'] == null || $name['parent_id'] == 0) {
// entry is parent
$newArray[$name['id']] = $name['name'];
} else {
// entry is child
}
}
But here is also my end, I don't know how to do that. I think i have to use some kind of recursive loop function, but I don't know how to start.
Would be awesome if somebody could help me.
Kind regards,
Matt.
You can use a recursive function like this (I only added the code which is relevant for understanding):
function get_children($parentId) {
$array = array();
//Load/Find $children
foreach($children as $child) {
$array[] = array(
'id' => $child->id,
'name' => 'YourName',
'children' => get_children($child->id)
);
}
return $array;
}
If you save the data in such an array, it isn't necessary to save the parent_id, because you can get it by searching for the parent elements id.
TABLE `people`
+----+------------+-------+
| sn | name | upper |
+----+------------+-------+
| 1 | Clement | 0 |
| 2 | Jean | 1 |
| 3 | Annie | 1 |
| 4 | Yuan | 2 |
| 5 | Mei | 2 |
| 6 | Blue | 3 |
| 7 | Yang | 5 |
| 8 | Lorinda | 0 |
+----+------------+-------+
The structure is like:
Clement
Jean
Yuan
Mei
Yang
Annie
Blue
Lorinda
The column upper states the upper person of himself/herself.
The problem is: How can I get a nested/multi-dimensional array from MySQL?
I thought I could use loops to fetch, but I failed to automated fetch all the lowers.
The array could be like this:
Array
(
[1]=>Array
(
[self]=>Clement
[2]=>Array
(
[self]=>Jean
[4]=>Array
(
[self]=>Yuan
)
[5]=>Array
(
[self]=>Mei
[7]=>Array
(
[self]=>Yang
)
)
)
[3]=>Array
(
[self]=>Annie
[6]=>Array
(
[self]=>Blue
)
)
)
[8]=>Array
(
[self]=>Lorinda
)
)
Since we don't know how many 'upper' persons does one have, the solution should be an automated function that build a complete array, not just for three or four dimension.
In other word, the function should deep into all the lower person from a top person.
Given your input as:
$input = array(
array('sn' => 1, 'name' => 'Clement', 'upper' => 0),
array('sn' => 2, 'name' => 'Jean', 'upper' => 1),
array('sn' => 3, 'name' => 'Annie', 'upper' => 1),
array('sn' => 4, 'name' => 'Yuan', 'upper' => 2),
array('sn' => 5, 'name' => 'Mei', 'upper' => 2),
array('sn' => 6, 'name' => 'Blue', 'upper' => 3),
array('sn' => 7, 'name' => 'Yang', 'upper' => 5),
array('sn' => 8, 'name' => 'Lorinda', 'upper' => 0),
);
using references you can build a tree with the following loop:
$map = array();
foreach ($input as $node) {
// init self
if (!array_key_exists($node['sn'], $map)) {
$map[$node['sn']] = array('self' => $node['name']);
}
else {
$map[$node['sn']]['self'] = $node['name'];
}
// init parent
if (!array_key_exists($node['upper'], $map)) {
$map[$node['upper']] = array();
}
// add to parent
$map[$node['upper']][$node['sn']] = & $map[$node['sn']];
}
print_r($map[0]);
demo: http://3v4l.org/vuVPu
Assuming the data is like this
$data = array(
array(1, 'Clement', 0),
array(2, 'Jean ', 1),
array(3, 'Annie ', 1),
array(4, 'Yuan ', 2),
array(5, 'Mei ', 2),
array(6, 'Blue ', 3),
array(7, 'Yang ', 5),
array(8, 'Lorinda', 0),
);
this recursive function might work:
function tree($data, $node) {
foreach($data as $e)
if($e[2] == $node[0])
$node['children'] []= tree($data, $e);
return $node;
}
Use it like this:
$tree = tree($data, array(0));
print_r($tree);
using a reference map
$input = array(
array('sn' => 1, 'name' => 'Clement', 'upper' => 0),
array('sn' => 2, 'name' => 'Jean', 'upper' => 1),
array('sn' => 3, 'name' => 'Annie', 'upper' => 1),
array('sn' => 4, 'name' => 'Yuan', 'upper' => 2),
array('sn' => 5, 'name' => 'Mei', 'upper' => 2),
array('sn' => 6, 'name' => 'Blue', 'upper' => 3),
array('sn' => 7, 'name' => 'Yang', 'upper' => 5),
array('sn' => 8, 'name' => 'Lorinda', 'upper' => 0),
);
$map = []; // map a reference by id for each item
foreach ($input as &$inp) {
$map[$inp['sn']] = &$inp;
}
foreach ($map as &$_inp) { // assign each item to its parent, with help of the map
if ($_inp['upper']) {
$map[$_inp['upper']]['children'] = &$map[$_inp['upper']]['children'] ?? [];
$map[$_inp['upper']]['children'][] = &$_inp;
}
}
$result = array_filter($map, fn($item) => !$item['upper']);
print_r($result);```
Ok, so here's my table structure:
+--------------------------+ +----------------+ +-------------------------------+
| pages | | menus | | menu_pages |
+--------------------------+ +----+-----------+ +-------------------------------+
| id | title | slug | | id | name | | menu_id | page_id | parent_id |
+-------+---------+--------+ +----+-----------+ +---------+---------+-----------+
| 1 | Home | index | | 1 | default | | 1 | 1 | 0 |
+-------+---------+--------+ +----+-----------+ +---------+---------+-----------+
| 2 | About | about | | 2 | footer | | 1 | 2 | 0 |
+-------+---------+--------+ +----+-----------+ +---------+---------+-----------+
| 3 | Test 1 | test-1 | | 1 | 3 | 2 |
+-------+---------+--------+ +---------+---------+-----------+
| 4 | Test 2 | test-2 | | 1 | 4 | 2 |
+-------+---------+--------+ +---------+---------+-----------+
| 5 | Test 3 | test-3 | | 1 | 5 | 4 |
+-------+---------+--------+ +---------+---------+-----------+
So basically, we have pages, menus, and a menu_pages linking table which specifies the menu, the page, and the parent of each menu item.
Here's my query:
$query = "SELECT pages.id, pages.title, pages.slug, menu_pages.parent_id
FROM menus, pages, menu_pages WHERE menus.name = '$menu'
AND menus.id = menu_pages.menu_id
AND pages.id = menu_pages.page_id";
$results = $db->Query($query);
Here's the question: How do I get the menu items properly nested under their respective parents in an array? I've tried quite a few things already, but none of them worked beyond simply 2 levels, so I won't clutter up the question with it. Obviously I need some kind of recursion in PHP, or to modify my query maybe in a way that I can get the SQL to return them properly?
It should look something like this in the output:
[0] => array(
'id' => 1,
'title' => 'Home',
'slug' => '/',
'parent_id' => '0'
)
[1] => array(
'id' => 2,
'title' => 'About',
'slug' => 'about',
'parent_id' => 0,
'sub_menu' => array(
[0] => array(
'id' => 3,
'title' => 'Test 1',
'slug' => 'test-1',
'parent_id' => 2
)
[1] => array(
'id' => 4,
'title' => 'Test 2',
'slug' => 'test-2',
'parent_id' => '2',
'sub_menu' => array(
[0] => array(
'id' => 5,
'title' => 'Test 3',
'slug' => 'test-3',
'parent_id' => 4
)
)
)
)
)
Thanks for the help!
This isn't quite as simple as it first sounds - if you want to get into how to do it with SQL, you are looking for a recursive sql statement.
Unfortunately mysql doesn't support this directly, and you would need to write a body of code to get it working. There is an example of how to do it here. Not simple.
http://explainextended.com/2009/03/17/hierarchical-queries-in-mysql/
In case you're interested in how to pick this apart, you would implement it in Oracle like this:
SELECT p.id, p.title, p.slug, mp.parent_id, level
FROM menu_pages mp
JOIN pages p ON ( p.id = mp.page_id )
JOIN menus m ON ( m.id = mp.menu_id )
CONNECT BY PRIOR mp.page_id = mp.parent_id
START WITH ( m.name = 'default' AND mp.parent_id = 0 )
You are basically saying:
START WITH a query for the top level of the menu
CONNECT that back to the result set by joining the parent to the child
You end up with a result set like this:
id title slug parent level
------------------------------------
1 Home index 0 1
2 About about 0 1
3 Test 1 test-1 2 2
4 Test 2 test-2 2 2
5 Test 3 test-3 4 3
All this actually gives you in addition to what you already have is:
The "level" of each point in the menu.
If a sub menu appeared multiple times in your structure it would be repeated correctly.
Sections of the menu that are not connected properly will not be returned.
So, for small, simple and consistent menus it's probably over-kill anyway.
Plus, even in this case you would need to process this in PHP to get the structure you're looking for.
So, using that as inspiration you can see how you could implement it in mysql by just doing the post processing.
You start off with your original query:
SELECT pages.id
, pages.title
, pages.slug
, menu_pages.parent_id
FROM menus
, pages
, menu_pages
WHERE menus.name = 'default'
AND menus.id = menu_pages.menu_id
AND pages.id = menu_pages.page_id
You can then loop over this result and build the array structure yourself manually.
In order to avoid the problem of recursion, we're instead going to take advantage of the fact that we can have two variables pointing at the same data structure - we're going to use references so that changing the value of the variable in one reference will change the value of the variable in the other.
I.E. The difficulty you get is finding the right point in the hierarchy to add each child. With references you don't have to.
Create an empty menu array
Loop over the results from your SQL statement
Create a copy of each menu item and put it into a simply indexed store (by the id of the item)
If you have the root menu item, add it to your menu array (as a reference)
If you don't have the root menu item, find the parent in your simple store and add your new item to it.
At the end you should have the nice nested structure you're looking for.
Like this:
<?php
// As if it came back from mysql...
// Assumed that it's ordered so that every possible parent appears before all its childern
$aResults = array( array( 'id' => 1, 'title' => 'Home', 'slug' => 'index', 'parent_id' => 0 )
, array( 'id' => 2, 'title' => 'About', 'slug' => 'about', 'parent_id' => 0 )
, array( 'id' => 3, 'title' => 'Test 1', 'slug' => 'test-1', 'parent_id' => 2 )
, array( 'id' => 4, 'title' => 'Test 2', 'slug' => 'test-2', 'parent_id' => 2 )
, array( 'id' => 5, 'title' => 'Test 3', 'slug' => 'test-3', 'parent_id' => 4 ) );
// the menu you're creating
$aMenu = array();
// the simple store of the menu items you're going to use to find the parents
$aBaseMenuIndex = array();
foreach( $aResults as $aMenuItem ) {
$aMenuItem['sub_menu'] = array();
// add your menu item to the simple store
$aBaseMenuIndex[ $aMenuItem['id'] ] = $aMenuItem;
if ( $aMenuItem['parent_id'] == 0 ) {
// if it's a base menu item, add it to the menu
$aMenu[] =& $aBaseMenuIndex[ $aMenuItem['id'] ];
} else {
// if it's not a base item, add it to the sub menu, using the simply indexed store to find it
// adding it here will also add it to $aMenu, as $aMenu contains a reference to this
$aBaseMenuIndex[ $aMenuItem['parent_id'] ]['sub_menu'][] =& $aBaseMenuIndex[ $aMenuItem['id'] ];
}
}
var_dump( $aMenu );