Checking hour and minutes inside datetime - php

Question

Is there a way to see inside this function if $hours and $minutes are any other than 00:00, so that if they arent, i wont show the time?
public static function datetimedutch($date)
{
if ($date != '')
{
list($newdate, $time) = explode(' ', $date);
list($date_year, $date_month, $date_day) = explode('-', $newdate);
list($hours, $minutes, $seconds) = explode(':', $time);
$dag = array('zondag','maandag','dinsdag','woensdag','donderdag','vrijdag','zaterdag');
$maand = array('maand','januari','februari','maart','april','mei','juni','juli','augustus','september','oktober','november','december');
$weekdag = date("w", mktime($hours, $minutes, $seconds, $date_month,$date_day,$date_year));
$maandnr = date("n", mktime($hours, $minutes, $seconds, $date_month,$date_day,$date_year));
$maand_dag = date("j", mktime($hours, $minutes, $seconds, $date_month,$date_day,$date_year));
return $dag[$weekdag] . ' ' . $maand_dag . ' ' . $maand[$maandnr] . ' ' . $hours . ':' . $minutes;
}
}

Answer 1

This should do it :)
function datetimedutch($date)
{
if (!empty($date))
{
$someDate = strtotime($date);
$hours = date('H',$someDate);
$minutes = date('i',$someDate);
$dag = array('zondag','maandag','dinsdag','woensdag','donderdag','vrijdag','zaterdag');
$maand = array('maand','januari','februari','maart','april','mei','juni','juli','augustus','september','oktober','november','december');
$weekdag = date("w", $someDate);
$maandnr = date("n", $someDate);
$maand_dag = date("j", $someDate);
if($hours>0 || $minutes>0) {
return $dag[$weekdag] . ' ' . $maand_dag . ' ' . $maand[$maandnr] . ' ' . $hours . ':' . $minutes;
} else {
return $dag[$weekdag] . ' ' . $maand_dag . ' ' . $maand[$maandnr];
}
} else {
return false;
}
}
echo datetimedutch('2014-05-15 12:39:06');
echo "<br />";
echo datetimedutch('2014-05-15 00:00:06');

Answer 2

I really recommend using automated way of getting locale formatted date, for example:
function formatDateInDutch($date = null) {
$date = strtotime($date);
$currentLocale = setlocale(LC_TIME, 0);
switch (PHP_OS){
case 'WIN':
case 'WINNT':
setlocale(LC_TIME, 'Dutch');
break;
case 'LINUX':
default:
setlocale(LC_TIME, 'nl_NL');
}
// format: http://pl1.php.net/manual/en/function.strftime.php
$ret = strftime('%A %w %B %m', $date);
// has minutes, display hour:minute
if ((int)date('i', $date) != 0) {
$ret .= ' '.date('H:i', $date);
// has only hours
} elseif ((int)date('H', $date) != 0 AND (int)date('i', $date) == 0) {
$ret .= ' '.date('H', $date);
}
// restore default locale
setlocale(LC_TIME, $currentLocale);
return $ret;
}
function formatDateInDutchBetter($date = null){
$date = new DateTime($date, new DateTimeZone('Europe/Amsterdam'));
// format: http://www.icu-project.org/apiref/icu4c/classSimpleDateFormat.html#details
$formatPattern = 'EEEE e LLLL dd ';
// NOTE: $date->format and IntlDateFormatter format patterns ARE DIFFERENT!!!
// if datetime has minutes then display hour:minutes
if ((int)$date->format('i') != 0) {
$formatPattern .= 'HH:mm';
// if datetime has only minutes display minutes
} elseif ((int)$date->format('H') != 0 AND (int)$date->format('i') == 0) {
$formatPattern .= 'HH';
}
$formattedDate = IntlDateFormatter::formatObject($date, $formatPattern, 'nl_NL');
return $formattedDate;
}
print formatDateInDutch(date('Y-m-d H:m:s'));
print '<hr>';
print formatDateInDutchBetter(date('Y-m-d H:m:s'));
And I really recommend second approach: using internationalization extension from PHP. It requires enabling extension but it is platform independent and it is very easy to add/change other locales.