I want to get the FRENCH GMT DATE from an Unix timestamp.
In my database, i saved the date in GMT+0 then i get the timestamp of this date and want to display the date with the good GMT+2
My timestamp is :1461857633 from database and it's equal to : 29/04/2016 12:27:11
And now i want to display this date with local GMT.
So i did this :
$timestamp = 1461857633;
$format = 'd/m/Y H:i:s';
$res = date($format, $timestamp);
echo $res;
and i have the same date 29/04/2016 12:27:11 where as my timezone is well 'Europe/Paris'
Normaly i should to have this date : 29/04/2016 14:27:11
$timestamp = 1461857633;
$effectiveDate = strtotime("+120 minutes", $timestamp);
$format = 'd/m/Y H:i:s';
$res = date($format, $effectiveDate);
echo $res;
date_default_timezone_set("UTC");
$HUTC = date("h");
date_default_timezone_set("Europe/Paris");
$HParis = date("h");
$diff = $HParis - $HUTC;
$timestamp = 1461857633;
$timestamp = 1461857633 + $diff * 60 * 60;
$format = 'd/m/Y H:i:s';
$res = date($format,$timestamp);
echo $res;
This will work both summer and winter time
You can simply add 2 hours to the timestamp or you can create a DateTime object and modify it by adding 2 hours to it:
$timestamp = 1461857633 + 2 * 60 * 60;
or
$dateTime = new DateTime();
$dateTime->setTimestamp(1461857633)->modify('+2 hours');
echo $dateTime->format('d/m/Y H:i:s');
or, another solution would be to calculate the seconds between the timezone you want to convert to and the Greenwich time zone (which is GMT+0) like:
$greenwichTimeZone = new DateTimeZone('Greenwich Mean Time');
$parisTimeZone = new DateTimeZone('Europe/Paris');
$dateTimeGreenwich = new DateTime('now', $greenwichTimeZone);
$seconds = $parisTimeZone->getOffset($dateTimeGreenwich);
$dateTime = new DateTime();
$dateTime->setTimestamp(1461857633 + $seconds);
echo $dateTime->format('d/m/Y H:i:s');
I have a variable like this,
$Timestamp = "Tue Mar 8 15:59:00 UTC-05:00 2016";
How do I change its format to YYYYMM-DD HH:MM AM/PM and change the timezone from UTC to Pacific Time using PHP?
PHP's DateTime object is pretty flexible.
$UTC = new DateTimeZone("UTC");
$TZ = new DateTimeZone("America/New_York");
$date = new DateTime( "2016-03-09 15:00:00", $UTC );
$date->setTimezone( $TZ );
echo $date->format('Y-m-d H:i:s');
Use php date: date('Y/m/d H:i', $timestamp) but your timestamp should be int:
$timestamp = strtotime('22-09-2008');
You can try following
$Timestamp = "Tue Mar 1 15:59:00 UTC-05:00 2016";
$datetime = new DateTime($Timestamp);
$datetime->format('Y-m-d H:i:s') . "\n";
$new_time = new DateTimeZone('Pacific/Apia');
$datetime->setTimezone($new_time);
//New formatted time
echo $datetime->format('Y-m-d H:i:s');
Assume I get a string like 08/22/2015 10:56 PM and that this date/time string always refers to only one particular time zone. I need to be able to convert that to this format: 'Ymd\THis\Z', which is the iCal format.
How do I convert that string to Zulu time and into 'Ymd\THis\Z'
How do I then add, say, 30 minutes to that date/time?
Been trying to hack this with strtotime and DateTime, but I'm worried that I'm going about this the wrong way. Maybe there's a simpler and more straightforward solution?
You can use DateTime, example bellow:
<?php
$datetime = '08/22/2015 10:56 PM';
$tz_from = 'America/New_York';
$tz_to = 'UTC';
$format = 'Ymd\THis\Z';
$dt = new DateTime($datetime, new DateTimeZone($tz_from));
$dt->setTimeZone(new DateTimeZone($tz_to));
echo $dt->format($format) . "\n";
$minutes = 30;
$dt->add(new DateInterval('PT' . $minutes . 'M'));
echo $dt->format($format) . "\n";
according to subject line; To convert local time to UTC you need the timezone name of given local time, or if you have timezone offset in GMT; you can try the following:
//assume time zone is +3 hours
$offset = 3 * 60 * 60;
$date = date('H:i:s', strtotime("10:56 PM")- $offset);
echo $date;
This will output : 19:56:00 which is UTC Time
I have $adate; which contains:
Tue Jan 4 07:59:59 2011
I want to add to this date the following:
$duration=674165; // in seconds
Once the seconds are added I need the result back into date format.
I don't know what I'm doing, but I am getting odd results.
Note: both variables are dynamic. Now they are equal to the values given, but next query they will have different values.
If you are using php 5.3+ you can use a new way to do it.
<?php
$date = new DateTime();
echo $date->getTimestamp(). "<br>";
$date->add(new DateInterval('PT674165S')); // adds 674165 secs
echo $date->getTimestamp();
?>
Just use some nice PHP date/time functions:
$adate="Tue Jan 4 07:59:59 2011";
$duration=674165;
$dateinsec=strtotime($adate);
$newdate=$dateinsec+$duration;
echo date('D M H:i:s Y',$newdate);
Given the fact that $adate is a timestamp (if that's the case), you could do something like this:
$duration = 674165;
$result_date = strtotime(sprintf('+%d seconds', $duration), $adate);
echo date('Y-m-d H:i:s', $result_date);
// add 20 sec to now
$duration = 20;
echo date("Y-m-d H:i:s", strtotime("+$duration sec"));
Do this:
$seconds = 1;
$date_now = "2016-06-02 00:00:00";
echo date("Y-m-d H:i:s", (strtotime(date($date_now)) + $seconds));
$current_time_zone = 150;
date("Y-m-d H:i:s",strtotime(date("Y-m-d H:i:s"))+$current_time_zone);
I made this example for a timezone, but if you change some parts it may help you out:
$seconds_to_add = 30;
$time = new DateTime();
$time->setTimezone(new DateTimeZone('Europe/London'));
$time2 = $time->format("Y/m/d G:i:s");
$time->add(new DateInterval('PT' . $seconds_to_add . 'S'));
$timestamp = $time->format("Y/m/d G:i:s");
echo $timestamp;
echo '========';
echo $time2;
Result:
2018/06/17 3:16:23========2018/06/17 3:15:53
It would be easier with DateTime::modify
(new DateTime($str))->modify("+$duration seconds"); //$str is the date in string
I have trouble with strtotime() to resolve my problem of add dynamic data/time value in the current time
This was my solution:
$expires = 3600; //my dynamic time variable (static representation here)
$date = date_create(date('Y-m-d H:i:s')); //create a date/time variable (with the specified format - create your format, see (1))
echo date_format($date, 'Y-m-d H:i:s')."<br/>"; //shows the date/time variable without add seconds/time
date_add($date, date_interval_create_from_date_string($expires.' seconds')); //add dynamic quantity of seconds to data/time variable
echo date_format($date, 'Y-m-d H:i:s'); //shows the new data/time value
font: https://secure.php.net/manual/en/datetime.add.php (consult Object Oriented style too, the Elzo Valugi solution)
(1) https://secure.php.net/manual/en/function.date.php
I want to add number of days to current date:
I am using following code:
$i=30;
echo $date = strtotime(date("Y-m-d", strtotime($date)) . " +".$i."days");
But instead of getting proper date i am getting this:
2592000
Please suggest.
This should be
echo date('Y-m-d', strtotime("+30 days"));
strtotime
expects to be given a string containing a US English date format and will try to parse that format into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 UTC), relative to the timestamp given in now, or the current time if now is not supplied.
while date
Returns a string formatted according to the given format string using the given integer timestamp or the current time if no timestamp is given.
See the manual pages for
http://www.php.net/manual/en/function.strtotime.php
http://www.php.net/manual/en/function.date.php
and their function signatures.
This one might be good
function addDayswithdate($date,$days){
$date = strtotime("+".$days." days", strtotime($date));
return date("Y-m-d", $date);
}
$date = new DateTime();
$date->modify('+1 week');
print $date->format('Y-m-d H:i:s');
or print date('Y-m-d H:i:s', mktime(date("H"), date("i"), date("s"), date("m"), date("d") + 7, date("Y"));
$today=date('d-m-Y');
$next_date= date('d-m-Y', strtotime($today. ' + 90 days'));
echo $next_date;
You can add like this as well, if you want the date 5 days from a specific date :
You have a variable with a date like this (gotten from an input or DB or just hard coded):
$today = "2015-06-15"; // Or can put $today = date ("Y-m-d");
$fiveDays = date ("Y-m-d", strtotime ($today ."+5 days"));
echo $fiveDays; // Will output 2015-06-20
Keep in mind, the change of clock changes because of daylight saving time might give you some problems when only calculating the days.
Here's a little php function which takes care of that:
function add_days($date, $days) {
$timeStamp = strtotime(date('Y-m-d',$date));
$timeStamp+= 24 * 60 * 60 * $days;
// ...clock change....
if (date("I",$timeStamp) != date("I",$date)) {
if (date("I",$date)=="1") {
// summer to winter, add an hour
$timeStamp+= 60 * 60;
} else {
// summer to winter, deduct an hour
$timeStamp-= 60 * 60;
} // if
} // if
$cur_dat = mktime(0, 0, 0,
date("n", $timeStamp),
date("j", $timeStamp),
date("Y", $timeStamp)
);
return $cur_dat;
}
You could also try:
$date->modify("+30 days");
You can do it by manipulating the timecode or by using strtotime(). Here's an example using strtotime.
$data['created'] = date('Y-m-d H:i:s', strtotime("+1 week"));
You can use strtotime()
$data['created'] = date('Y-m-d H:m:s', strtotime('+1 week'));
I know this is an old question, but for PHP <5.3 you could try this:
$date = '05/07/2013';
$add_days = 7;
$date = date('Y-m-d',strtotime($date) + (24*3600*$add_days)); //my preferred method
//or
$date = date('Y-m-d',strtotime($date.' +'.$add_days.' days');
You could use the DateTime class built in PHP. It has a method called "add", and how it is used is thoroughly demonstrated in the manual: http://www.php.net/manual/en/datetime.add.php
It however requires PHP 5.3.0.
$date = "04/28/2013 07:30:00";
$dates = explode(" ",$date);
$date = strtotime($dates[0]);
$date = strtotime("+6 days", $date);
echo date('m/d/Y', $date)." ".$dates[1];
You may try this.
$i=30;
echo date("Y-m-d",mktime(0,0,0,date('m'),date('d')+$i,date('Y')));
Simple and Best
echo date('Y-m-d H:i:s')."\n";
echo "<br>";
echo date('Y-m-d H:i:s', mktime(date('H'),date('i'),date('s'), date('m'),date('d')+30,date('Y')))."\n";
Try this
//add the two day
$date = "**2-4-2016**"; //stored into date to variable
echo date("d-m-Y",strtotime($date.**' +2 days'**));
//print output
**4-4-2016**
Use this addDate() function to add or subtract days, month or years (you will need the auxiliar function reformatDate() as well)
/**
* $date self explanatory
* $diff the difference to add or subtract: e.g. '2 days' or '-1 month'
* $format the format for $date
**/
function addDate($date = '', $diff = '', $format = "d/m/Y") {
if (empty($date) || empty($diff))
return false;
$formatedDate = reformatDate($date, $format, $to_format = 'Y-m-d H:i:s');
$newdate = strtotime($diff, strtotime($formatedDate));
return date($format, $newdate);
}
//Aux function
function reformatDate($date, $from_format = 'd/m/Y', $to_format = 'Y-m-d') {
$date_aux = date_create_from_format($from_format, $date);
return date_format($date_aux,$to_format);
}
Note: only for php >=5.3
Use the following code.
<?php echo date('Y-m-d', strtotime(' + 5 days')); ?>
Reference has found from here - How to Add Days to Current Date in PHP
Even though this is an old question, this way of doing it would take of many situations and seems to be robust. You need to have PHP 5.3.0 or above.
$EndDateTime = DateTime::createFromFormat('d/m/Y', "16/07/2017");
$EndDateTime->modify('+6 days');
echo $EndDateTime->format('d/m/Y');
You can have any type of format for the date string and this would work.
//Set time zone
date_default_timezone_set("asia/kolkata");
$pastdate='2016-07-20';
$addYear=1;
$addMonth=3;
$addWeek=2;
$addDays=5;
$newdate=date('Y-m-d', strtotime($pastdate.' +'.$addYear.' years +'.$addMonth. ' months +'.$addWeek.' weeks +'.$addDays.' days'));
echo $newdate;
Do not use php's date() function, it's not as accurate as the below solution and furthermore it is unreliable in the future.
Use the DateTime class
<?php
$date = new DateTime('2016-06-06'); // Y-m-d
$date->add(new DateInterval('P30D'));
echo $date->format('Y-m-d') . "\n";
?>
The reason you should avoid anything to do with UNIX timestamps (time(), date(), strtotime() etc) is that they will inevitably break in the year 2038 due to integer limitations.
The maximum value of an integer is 2147483647 which converts to Tuesday, 19 January 2038 03:14:07 so come this time; this minute; this second; everything breaks
Source
Another example of why I stick to using DateTime is that it's actually able to calculate months correctly regardless of what the current date is:
$now = strtotime('31 December 2019');
for ($i = 1; $i <= 6; $i++) {
echo date('d M y', strtotime('-' . $i .' month', $now)) . PHP_EOL;
}
You'd get the following sequence of dates:
31 December
31 November
31 October
31 September
31 August
31 July
31 June
PHP conveniently recognises that three of these dates are illegal and converts them into its best guess, leaving you with:
01 Dec 19
31 Oct 19
01 Oct 19
31 Aug 19
31 Jul 19
01 Jul 19