I need to retrieve the count of a field name called remark corresponding to a particular user.
select count(remark) from attendance where username=_POST['username']
How will I implement this in php? I need to store the count to a variable $totalcount.
This is what i tried out:
$result = mysql_query("select count(1) FROM attendance where stud_id='$_POST['user']'");
$row = mysql_fetch_array($result);
$total = $row[0];
Also quotes are not used properly in the query string. Try this code.
$result = mysql_query("select count(*) FROM attendance where stud_id='".$_POST['user']."'");
$row = mysql_fetch_array($result);
$total = $row[0];
Related
I have a small issue that I can't figure out.
I have to pull data from two different tables, in one loop. I've never done that before, so I have no idea how. I tried two different queries. That looked like this:
$query = "SELECT * FROM colors ";
$color_select = mysqli_query($connection, $query);
$second_query = "SELECT * FROM votes";
$vote_select = mysqli_query($connection, $second_query);
And then put them into a loop:
while($row = mysqli_fetch_assoc($color_select) && $second_row = mysqli_fetch_assoc($vote_select))
{
$color = $row['Colors'];
$votes = $second_row['Votes'];
echo "<tr><td>$color</td><td>$votes</td></tr>";
}
But that didn't work. I didn't expect it to, just wanted to try. :) Maybe someone experienced can help me out. Thanks.
At the end of the day I need a table displayed, that has two columns, one of them contains the color name from one DB table and the other one contains a number of votes.
As requested: table structures.
Table: colors has only one field Colors.
Table: votes has four fields city_id, City, Colors and Votes
*************************EDIT**************************************
So fixed up the query as suggested, but is still shows nothing.
Here is the edited code:
$query = "SELECT * FROM colors,votes WHERE colors.Colors=votes.Colors";
$color_votes_select = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($color_votes_select))
{ $color = $row['Colors'];
$votes = $row['Votes']; }
if table having relation.
try this in single query .
SELECT
`colors`.*,votes.*
FROM
`colors`
INNER JOIN
`votes` ON
`votes`.colorId = `colors`.Id
Most imp *****You should have some relationship between tables
Otherwise workaround
Run query on color, Save it in ArrayA
Run query on vote, Save it in ArrayB
Create New Array ArrayC
$arrayC = array();
Loop array A or C if they both contact same row count
array_push($ArrayC, key and value of color, key and value of votes);
Final loop ArrayC to print tr and td
First Relate These two tables, write color_id in votes table.
$query = "SELECT * FROM colors,votes where colors.id=votes.color_id";
$color_select = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($color_select))
{
$color = $row['Colors'];
$votes = $row['Votes'];
}
Try this:
$query = "SELECT colors FROM colors";
$color_select = mysqli_query($connection, $query) or die (mysqli_error());
$second_query = "SELECT votes FROM votes"; //you only need column votes right?
$vote_select = mysqli_query($connection, $second_query) or die (mysqli_error());;
while( $row = mysqli_fetch_assoc($color_select) && $second_row = mysqli_fetch_assoc($vote_select)){
$color[] = $row['colors'];
$votes[] = $second_row['votes'];
echo "<tr><td>$color</td><td>$votes</td></tr>";
}
Short explanation:
It will fetch the select and store into an array (because what you were doing is selecting multiple rows into one single variable) and then just display with the echo.
I am trying to perform a query inside a while loop that is getting values from a column. I am trying to query first to get all my values from a column in my DB and then get the count of how many times that value is in that column.
Examples of output trying to get
myValue is in the column 3 times
myOtherValue is in the column 10 times
myOtherOtherValue is in the column 22 times
Example of code
$sql = "SELECT DISTINCT id, columnName FROM tableName";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
$id = $row['id'];
function myCount($id)
{
$query = "SELECT COUNT(*) FROM tableName WHERE name = '$id'";
$result = mysql_query($query);
$count = mysql_fetch_array($result);
}
echo "$id is in the column $count[0] times";
}
You can't define a function inside the while loop.
Using COUNT(*) with a GROUP BY name clause, then you could solve the problem with only one query.
I have the following code that fetches a single row:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$row = mysqli_fetch_array($result);
I know this is useful in a while loop, where you can just loop through the results.
But I need to be able to grab specific rows that meet this condition. Something following this pseudo code:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$arrayofrows = mysqli_fetch_arrayofrows($result);
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
and so on...
How can I do this?
You can try something like this
$arrayofrows = array();
while($row = mysqli_fetch_array($result))
{
$arrayofrows = $row;
}
You can now have
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
I think the function you are looking for is mysqli_fetch_all as shown below. This avoids the need to create an extra looping structure or a function to do something already provided.
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1;";
$result = mysqli_query($query);
$arrayofrows = mysqli_fetch_all($result);
$arrayofrows[0] //(to get the first row)
$arrayofrows[1] //(2nd row)
It depends on whether you require the entire result set back or not but I think the LIMIT could be used like:
$query = "SELECT *
FROM translations
WHERE iddoc = '$id'
AND submitted = 1 LIMIT 200,200;";
Otherwise as others say you will need to convert to an array (which is what fetch_all does) and then get the element from that array.
How would i add the sum of a column in mysql?
Here's my code:
$add = mysql_query("SELECT SUM(rsvp) FROM TABLE_NAME WHERE rsvp > 0;")or die(mysql_error());
when i echo it, it gives me a Resource id #
try this instead
$q = mysql_query("SELECT SUM(rsvp) as sum FROM TABLE_NAME WHERE rsvp > 0") or die(mysql_error());
$row = mysql_fetch_assoc($q);
echo $row['sum'];
I recommend looking up more on how to use PHP and MySQL together possibly from one of these sites:
- http://php.net/manual/en/book.mysql.php
- http://www.youtube.com/user/phpacademy - this one is pretty nooby but it does cover everything from pagination to image uploads and beyond. a good place to start I guess.
mysql_query returns a resource, not a value. You need to use another function, such as mysql_fetch_row to access the value it contained:
$result = mysql_query("SELECT SUM(rsvp) FROM TABLE_NAME WHERE rsvp > 0;") or die(mysql_error());
$row = mysql_fetch_row($result); // get an array containing the value of the first row of the above query
$sum = (int) $row[0]; // get an integer containing the value of the first (and, here, only) item in that row
Yes, and you use mysql_fetch_array to fetch a row from that resource.
$resource = mysql_query( ... );
if ($row = mysql_fetch_array($resource))
{
$add = $row[0];
}
I've found the problem,
Note: Undefined index: sum in D:\xampp\htdocs\demo-shop\cart.php on line 9
$sum_query= "SELECT sum(Prod_Tot) as sum FROM cart WHERE Prod_Tot > 0";
$sum_query_res = mysql_query($sum_query);
$row = mysql_fetch_row($sum_query_res);
echo $row['sum'];
If I put echo $row['0']; instead of echo $row['sum']; then it is ok.
ended up figuring it out.
$add = mysql_query("SELECT SUM(rsvp) FROM TABLE_NAME WHERE rsvp >= 1;")or die(mysql_error());
list ( $rsvp_total ) = mysql_fetch_array($add);
echo $rsvp_total;
This is short and simple try it
$sql = mysql_query("SELECT SUM(rsvp) as sum FROM TABLE_NAME WHERE rsvp > 0") or die(mysql_error());
$record = mysql_fetch_assoc($sql);
echo $record['sum'];
I want to get the number of rows in my MySQL table and store that number in a php variable. This is the code I'm using:
$size = #mysql_query("SELECT COUNT(*) FROM News");
$size ends up being "Resource ID #7." How do I put the number of rows directly into $size?
mysql_query returns a query resource id. In order to get values from it you need to use mysql_fetch_assoc on the resource id to fetch a row into an array.
$result = mysql_query("SELECT COUNT(*) FROM News");
$row = mysql_fetch_assoc($result);
$size = $row['COUNT(*)'];
You need to call mysql_fetch_row or one of its sister functions.
<?php
// untested
$result = #mysql_query("SELECT COUNT(*) FROM News");
// error handling
$row = mysql_fetch_row($result);
$count = $row[0];
?>
try the following:
$size = #mysql_query("SELECT COUNT(*) AS `total` FROM News");
$query = mysql_fetch_array($size);
echo $query['total'];
On a related note you can use the mysql_num_rows() function to obtain the number of rows from a given query. This is handy if you need to grab the data but also know the number of rows.
<?php
$result = #mysql_query("SELECT * FROM news");
$count = #mysql_num_rows($result);
?>