CSV file displays content in browser instead of downloading from browser - php

Question

I want to create a csv file from some results in my database. But it display the content instead of prompting the download.
I know there are alot of questions about this, but no luck for me.
if(isset($_POST['export'])){
$resultExport = mysql_query("SELECT question.id, question.question, answer, A, B, C, D, question.publish
FROM question
INNER JOIN packagequestion
ON question.id = packagequestion.questionid
WHERE packagequestion.packageid = '".$packageID."' AND question.publish = 1
ORDER BY question.id DESC");
if (!$resultExport) die('Couldn\'t fetch records');
$num_fields = mysql_num_fields($resultExport);
$headers = array();
for ($i = 0; $i < $num_fields; $i++)
{
$headers[] = mysql_field_name($resultExport , $i);
}
$fp = fopen('php://output', 'w');
if ($fp && $resultExport)
{
// name the file by current category and package
$filename = $categorie."".$packageName;
header('Content-Type: text/csv');
header('Content-Disposition: attachment; filename='.$filename.".csv");
header('Pragma: no-cache');
header('Expires: 0');
fputcsv($fp, $headers);
while ($row = mysql_fetch_row($resultExport))
{
fputcsv($fp, array_values($row));
}
die;
}
}

Answer 1

hope this will help you
<?php
include 'connection.php';
// Fetch Record from Database
$output = "";
$sql = mysql_query("select* from tablename");//your query
$columns_total = mysql_num_fields($sql);
// Get The Field Name
for ($i = 0; $i < $columns_total; $i++) {
$heading = mysql_field_name($sql, $i);
$output .= '"'.$heading.'",';
}
$output .="\n";
// Get Records from the table
while ($row = mysql_fetch_array($sql)) {
for ($i = 0; $i < $columns_total; $i++) {
$output .='"'.$row["$i"].'",';
}
$output .="\n";
}
// Download the file
$filename = "myFile.csv";
header('Content-type: application/csv');
header('Content-Disposition: attachment; filename='.$filename);
echo $output;
exit;
?>

Answer 2

for that you just have to remove following line from your code.
header('Content-Type: text/csv');