Capture user input from Form - php

Question

I'm a beginner in PHP, I'm trying to add Google PR tool in my blog. but i don't know how to make a user input based PHP url.
<?
require("PRclass.php");
$url='http://www.digitcrop.com/';
$pr = new PR();
echo "$url has Google PageRank: ".$pr->get_google_pagerank($url) ;
?>
Exactly what I want.
$url='http://www.digitcrop.com/';
Change to user input url with like below html
<p>
<input name="url[]" type="text" id="url[]" value="http://" size="80" /><br />
</p>
<p>
<input name="findpr" type="submit" value="Find Google PageRank" />
</p>

Answer 1

Depending on your Form method you get it via $_GET['yourinput'] or $_POST['yourinput']

Answer 2

You Need to Submit the form( weather GET or POST Method ) and then Putting the Input Values on correct Locations.
<?php
require("PRclass.php");
if(isset($_POST['sample']))
{
$url=urlencode($_POST['url']);
$pr = new PR();
echo "$url has Google PageRank: ".$pr->get_google_pagerank($url) ;
}
?>
<form name="sampleform" method="post" action="">
<p>
<input name="url" type="text" id="url" value="" size="80" /><br />
</p>
<p>
<input name="findpr" type="submit" value="Find Google PageRank" />
</p>
<input type="submit" name="sample" value="submit" />
</form>

Answer 3

To elaborate on #mfsymb's answer, you should put your input elements inside of a form element. Set the following attributes within the form element tag:
<form action='yourfile.php' method='post'>
Then, you can set your $url variable like so:
$url=$_POST["url[]"];
Read more about it here: http://www.w3schools.com/php/php_forms.asp

Answer 4

Try this
<?php
require("PRclass.php");
if($_POST['sample']!="")
{
$url=urlencode($_POST['url']);
$pr = new PR();
echo "$url has Google PageRank: ".$pr->get_google_pagerank($url) ;
}
?>
<form name="sampleform" method="post" action="">
<p>
<input name="url" type="text" id="url" value="" size="80" /><br />
</p>
<p>
<input name="findpr" type="submit" value="Find Google PageRank" />
</p>
<input type="submit" name="sample" value="submit" />
</form>

Answer 5

First of all, you don't need to use a named array for your input box (name="url[]") since a textbox will be holding a single value only.
The second thing to make note of is that you will need a <form> tag in order to let PHP know that you're submitting some information to work with.
HTML
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<p>
<input name="url" type="text" id="url" value="http://" size="80" /><br />
</p>
<p>
<input name="findpr" type="submit" value="Find Google PageRank" />
</p>
</form>
<?php echo $_SERVER['PHP_SELF']; ?> tells the form to post the data to the same page.
PHP
// run the below code only if the form was submitted
if(isset($_POST['findpr'])) {
$url = $_POST['url']; // this is where we capture the user input
// making sure the user enters a valid URL
if(!filter_var($url, FILTER_VALIDATE_URL))
{
echo 'The entered URL is not valid. Please try again';
}
else
{
require("PRclass.php");
$pr = new PR();
echo "$url has Google PageRank: ".$pr->get_google_pagerank($url) ;
}
}