php ajax search does not display results - php

I'm trying to make a php ajax search for the articles posted in database, but it gives me only : No results message. I've tested the connection to database and the select query, and it works.
This is the code:
<?php
require_once('dbconn.php');
$s = $_GET["s"];
$livesearch = '';
if (strlen($s) > 0)
{
$result = mysql_query("select * from articles where art_sts='1' ORDER BY title");
if ($result != FALSE)
{
foreach($result as $row)
{
if (stristr($row['title'], $s))
{
if ($livesearch == '')
{
$livesearch = ' '.htmlentities($row["title"], ENT_QUOTES, "UTF-8").'';
}
}
}
}
}
if ($livesearch == '')
{
$respond="No results...";
}
else
{
$respond = $livesearch;
}
echo $respond;
?>

You havent actually fetched the data that you are trying to output. You will need to add something like this...
while($row = mysql_fetch_assoc($result)) {
if (stristr($row['title'], $s))
{
if ($livesearch == '')
{
$livesearch = ' '.htmlentities($row["title"], ENT_QUOTES, "UTF-8").'';
}
}
}

Related

Why it only reads the first row?

i'm trying to use if condition in a href. my problem is why it only reads the first row in database. I've also tried to use while. Here is my code...
<?php
include 'dbconfig/config.php';
$select = "SELECT * FROM schedule_tbl";
$select_result = mysqli_query($con, $select);
if(mysqli_num_rows($select_result)> 0) {
$row = mysqli_fetch_assoc($select_result);
if($row['status'] == "close") { ?>
<li>Enroll Now Here!</li>
<?php } else { ?>
<li>Enroll Now Here!</li>
<?php }
}
?>
schedule.tbl
Using a while loop...
Try to use
if (mysqli_num_rows($select_result) > 0)
{
while ($row = mysqli_fetch_array($select_result))
{
if ($row['status'] == "close")
{
//
}
else
{
//
}
}
}

PHP API returning wrong response for android app

I am creating a API for android developer in PHP in which he want to delete some values from database and want to show a message after that.
Now the problem is this data is deleting successfully but this API always shows else part message after complete the process. If I remove the else part its return the null which crash the android app. So I just want to give a proper json message to the android developer
Here is the code which I am trying
if($clear_my_property == "yes" && $clear_my_requirement == "yes" && $all_of_these == "yes" && $user_name_id == $user_name_id1)
{
$tables_count = array("property_for_sale","property_for_rent","cpo_post_requirements");
foreach($tables_count as $table_count)
{
$user_count = mysql_query("select * from $table_count where user_name = '$user_name'");
$total_user_count = mysql_num_rows($user_count);
if($total_user_count > 0)
{
$tables_data = array("property_for_sale","property_for_rent","cpo_post_requirements");
foreach($tables_data as $table_data)
{
$user_sql = mysql_query("delete from $table_data where user_name='$user_name'");
if($user_sql)
{
$response['success'] = 1;
$response['user']['error_msg'] = 'Clear Successfully All History!';
}
}
}
else
{
$response['success'] = 0;
$response['user']['error_msg'] = 'Record Not Found!';
}
}
}
I know there is something wrong with this logic. But I need expert advise where my logic is wrong and what I have to do make it success
Problem with your original code, is that you are setting success/failure inside the loop. One of the four table may/may not contain the username. And if the last table don't have that, then as per your logic you are getting "record not found" even if previous iteration of the loop deleted data from the tables where username exists.
<?php
$conn = mysqli_connect(.....);
if($clear_my_property == "yes" && $clear_my_requirement == "yes" && $all_of_these == "yes" && $user_name_id == $user_name_id1) {
$tables_count = array("property_for_sale","property_for_rent","cpo_post_requirements");
$userHistoryDeleted = 0;
foreach($tables_count as $table_count) {
//if history is found, then it will be deleted otherwise not
mysql_query("delete from $table_count where user_name = '$user_name'");
if(mysqli_affected_rows($conn)) {
$userHistoryDeleted = 1;
}
}
$msg = 'Record Not Found!';
if($userHistoryDeleted) {
$msg = 'Clear Successfully All History!';
}
$response['success'] = $userHistoryDeleted;
$response['user']['error_msg'] = $msg;
}
Change your code :
if($total_user_count > 0)
{
$tables_data = array("property_for_sale","property_for_rent","cpo_post_requirements");
foreach($tables_data as $table_data)
{
$user_sql = mysql_query("delete from $table_data where user_name='$user_name'");
if($user_sql)
{
$response['success'] = 1;
$response['user']['error_msg'] = 'Clear Successfully All History!';
}
}
}
else
{
$response['success'] = 0;
$response['user']['error_msg'] = 'Record Not Found!';
}
to this one
if($total_user_count > 0)
{
$tables_data = array("property_for_sale","property_for_rent","cpo_post_requirements");
foreach($tables_data as $table_data)
{
$user_sql = mysql_query("delete from $table_data where user_name='$user_name'");
}
$response['success'] = 1;
$response['user']['error_msg'] = 'Clear Successfully All History!';
}

php else statement for empty search

I have a search function which matches keywords from a database and echo's out some html but I'm missing how to enable the handling of empty searches. Can I use an else statement or do I have to redefine the same parameters and use !isset for if not set?
<?php
$con = mysqli_connect("localhost", "database", "password", "table");
if (isset($_GET['search'])) {
$search_query = $_GET['search_query'];
global $con;
$get_item = "select * from database where keywords like '%$search_query%'";
$run_item = mysqli_query($con, $get_item);
while ($row_item = mysqli_fetch_array($run_item)) {
$item_keywords = $row_item['item_keywords'];
echo "Search found for $search_query";
} // working fine up to here
} else {
echo "Search not found for $search_query";
}
?>
You can use isset() and mysqli_num_rows() to check empty result. ANd use mysqli_real_escape_string for fire your query
if (isset($_GET['search'])) {
if (isset($_GET['search_query']) && $_GET['search_query'] != "") {/// check variable is set or not
$search_query = $_GET['search_query'];
$$search_query = mysqli_real_escape_string($con, $search_query);//
$get_item = "select * from `database` where `keywords` like '%$search_query%'";
$run_item = mysqli_query($con, $get_item);
$row_cnt = mysqli_num_rows($run_item); // count number of rows
if ($row_cnt > 0) {
while ($row_item = mysqli_fetch_array($run_item)) {
$item_keywords = $row_item['item_keywords'];
echo "Search found for $item_keywords";
}
} else {
echo "Search not found for $item_keywords";
}
} else {
echo "Search not found for $item_keywords";
}
}
Change your condition to:
if (isset($_GET['search']) && trim($_GET['search_query']) != '') {
}
You can set condition for empty search like this.
if (isset($_GET['search']) && trim($_GET['search']) !='') { ... }
Modify your if condition
if (isset($_GET['search']) && !empty($_GET['search_query'])) {
}
You can do it by using the empty function:
if (!empty($_GET['search'])) {
//your code
}

Comparing stored data in a column to an existing value

I have a column called favid. I am trying to pull and compare the data in that column to an existing value:
<?php $query = mysql_query("SELECT * FROM ajaxfavourites WHERE favid=$favid");
while ($row = mysql_fetch_assoc($query)) {
echo $row['favid']; };?>
I also have an existing value:
$x
But when I do something like this it doesn't work:
<?php if($row['favid'] == $x){?>
Do this...
<?php } else { ?>
Do nothing...
<?php}?>
I realize the data in the column somehow isn't pulled out. What should be done for this to work?
Try this, I assume you already connected to DB.
<?php
$x = 1;
$query = mysql_query("SELECT * FROM ajaxfavourites WHERE favid='$favid'") or die(mysql_error());
if (mysql_num_rows($query) > 0)
{
while ($row = mysql_fetch_assoc($query))
{
if ($row["existing_column_name"] == $x)
{
echo "Yes";
} else
{
echo "No";
}
}
} else
{
echo "Nothing was found";
}
?>
<?php
$x = 100500; // integer for example
$CID = mysql_connect("host","user","pass") or die(mysql_error());
mysql_select_db("db_name");
$query = mysql_query("SELECT * FROM ajaxfavourites WHERE favid='{$favid}'", $CID);
while ($row = mysql_fetch_assoc($query)) {
if (intval($row["some_existing_column_name"])==$x){
print "Is equals!";
} else {
print "Is different!";
}
}
?>
Please be informed that mysql_connect and other functions with the prefix of mysql_ is deprecated and can be removed in the next versions of PHP.

Not able to get proper value and print respective msg

Below is my code , I am trying to append values of $vid ,and than next time when my file loads i am trying to find currently passed value of $vid in array $ids, but every time i am getting success msg ,where i am going wrong, am i not able to append values properly ?
process.php
session_start();
if(isset($_POST)) {
$reason_data = trim($_POST['abuse_data']);
if($reason_data == "Video is offensive")
{
$reason = 'a:1:{i:0;s:18:"' . $reason_data .'";}';
}
else
{
$reason = 'a:1:{i:0;s:19:"' . $reason_data .'";}';
}
$motive = trim($_POST['remark_data']);
$uid = trim($_POST['abuse_uid']);
$vid = trim($_POST['abuse_vid']);
if(trim($_SESSION['abuse_vdo_id']) == '')
{
$_SESSION['abuse_vdo_id'] = $vid;
$str = $_SESSION['abuse_vdo_id'];
}
else {
$str = $str."," .$vid;
$_SESSION['abuse_vdo_id'] = $str;
}
print_r($_SESSION['abuse_vdo_id']);
echo "break";
print_r($str);
$ids = explode(',',$_SESSION['abuse_vdo_id']);
echo "break 2";
print_r($ids);
if(in_array($vid, $ids))
{
echo "already abused";
}
else
{
echo "success";
$query = "INSERT INTO ".DB_PREFIX."reports ( reason, motive, uid, vid ) VALUES ( '{$reason}','{$motive}', '{$uid}', '{$vid}' )";
$result = mysql_query($query);
}
}

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