How to get currently inserted AUTO_INCREMENT id? - php

Question

I have following table structure.
I want to insert the same value for item_image_name as the value of item_id(this is AUTO_INCREMENT) at the time of inserting a new record.
EDIT
I want this at the time of insertion
INSERT INTO items(user_id, item_image_name) VALUES ('','LAST_INCREMENT_VALUE + 1')

Answer 1

You can achieve this by defining a before insert trigger on the table.
In the body, first you can find next auto increment value to be assigned to primary key field and use the same for image_name field.
Example:
delimiter //
drop trigger if exists bi_on_items //
create trigger bi_on_items before insert on items
for each row
begin
if NEW.item_image_name is null OR length( trim( NEW.item_image_name ) ) = 0 then
set NEW.item_image_name := ( SELECT AUTO_INCREMENT
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = 'items'
AND TABLE_SCHEMA = DATABASE() );
end if;
end;
//
delimiter ;

Answer 2

You can use mysql_insert_id() to get the last inserted id on the current connection.

Answer 3

mysql_insert_id — Get the ID generated in the last query

Answer 4

$id = mysqli_insert_id();
This should be used instead of mysql_insert_id() since on PHP 5.5 native MySQL driver has been deprecated.

Answer 5

Short answer: You can't. The auto increment ID is generated only upon successful insert. So you won't have access to it during the insert process.
The alternative would be to make an insert first and then get the last id by using mysql_insert_id() and then update the same row using the retrieved id.
PS: You should stop using mysql_* functions as are officially deprecated post v5.5. Switch to PDO or mysqli as soon as you can.

Answer 6

You can try like this:
first insert then get last inserted id and update value of item_image_name
$mysqli = new mysqli("localhost", "my_user", "my_password", "db");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "your insert query";// insert with all fields and set item_image_name to empty
if( $mysqli->query($query)){
$id= $mysqli->insert_id;
$query = "UPDATE your_table set item_image_name= '$id' where item_id = $id LIMIT 1 ";//now update the value of item_image_name
$mysqli->query($query);
}
USE MYSQLI_* or PDO do not use mysql_* since mysql_* is deprecated.

Answer 7

use
$sid=mysql_insert_id();
I you insert the first row the $sid should be 1
To insert next use $sid+1
Edit
For your question: write a query to get the last item_id and use that id + 1 to fill the current item_image_name.
Note: for the new item item_id and item_image_name should same.

Answer 8

You can use
SHOW TABLE STATUS LIKE 'tablename' to get the next auto incremented id.
$result = mysql_query("SHOW TABLE STATUS LIKE 'table_name'");
$row = mysql_fetch_array($result);
$nextId = $row['Auto_increment'];
and then use the variable $nextId in your insert query
INSERT INTO items(user_id, item_image_name) VALUES ('',$nextId)

Answer 9

What mysql driver are you using?
If you are using mysql driver then you will get the last inserted id with mysql_insert_id();
for PDO driver: PDO::lastInsertId();
Note: mysql driver is deprecated from PHP 5.5 (http://php.net/manual/en/migration55.deprecated.php)

Answer 10

Get last inserted id first.
select item_id as lastId from items order by id desc limit 0,1
Now use lastId in your query.
INSERT INTO items(user_id, item_image_name) VALUES ('','lastId+1')
Hope this helps.

Answer 11

You can use an insert into select query
INSERT INTO items(user_id, item_image_name) VALUES ('','SELECT MAX(item_id)+1 FROM items')