codeigniter - display data from data base in dropdown [duplicate] - php

Question

This question already has answers here:
Ajax drop down for Country State & City in Codeigniter?
(3 answers)
Closed 8 years ago.
i am creating an application in codeigniter for the form we want country and state in drop down on change selection of country
Controller is like
public function user()
{
$data = array();
$this->load->model('enquiry');
$this->load->helper('url');
$data['result'] = $this->enquiry->get_reqtutor();
$data['countries'] = $this -> country_model -> get_countries();
$this->load->view('Table\DemoHistory',$data);
}
function get_states($country) {
$this->load->helper('url');
$this->load->model('state_model');
header('Content-Type: application/x-json; charset=utf-8');
echo(json_encode($this->state_model->get_states($country)));
}
and model is like
state_model`
<?php
class State_model extends CI_Model {
public function __construct() {
$this -> load -> database();
}
function get_states($country = null){
$this->db->select('state_id, state_name');
if($country != NULL){
$this->db->where('country_id', $country);
}
$query = $this->db->get('state_master');
$states = array();
if($query->result()){
foreach ($query->result() as $state) {
$cities[$state->state_id] = $state->state_name;
}
return $states;
} else {
return FALSE;
}
}
}
?>
country_model
<?php
class Country_model extends CI_Model {
public function __construct() {
$this -> load -> database();
}
function get_countries() {
$this -> db -> select('country_id, country_name');
$query = $this -> db -> get('country_master');
$countries = array();
if ($query -> result()) {
foreach ($query->result() as $country) {
$countries[$country -> country_id] = $country -> country_name;
}
return $countries;
} else {
return FALSE;
}
}
}
?>
Ajax is like
<script type="text/javascript">// <![CDATA[
$(document).ready(function(){
$('#country').change(function(){ //any select change on the dropdown with id country trigger this code
$("#cities > option").remove(); //first of all clear select items
var country_id = $('#country').val(); // here we are taking country id of the selected one.
$.ajax({
type: "POST",
url: /mtb/Schedule/get_states/"+country_id, //here we are calling our user controller and get_cities method with the country_id
success: function(cities) //we're calling the response json array 'cities'
{
$.each(cities,function(state_id,state_name) //here we're doing a foeach loop round each city with id as the key and city as the value
{
var opt = $('<option />'); // here we're creating a new select option with for each city
opt.val(state_id);
opt.text(state_name);
$('#cities').append(opt); //here we will append these new select options to a dropdown with the id 'cities'
});
}
});
});
});
// ]]>
</script>
and view is
<?php $countries['#'] = 'Please Select'; ?>
<label for="country">Country: </label><?php echo form_dropdown('country_id', $countries, '#', 'id="country"'); ?>
<?php $cities['#'] = 'Please Select'; ?>
<label for="city">State: </label><?php echo form_dropdown('state_id', $cities, '#', 'id="cities"'); ?>
i am getting country name while my state value is not comming in dropdown please help........

Answer 1

Things to consider about your code:
You have an error here url: /mtb/Schedule/get_states/"+country_id, missing double quote at the beggining. Always use a debugging tool, like firebug, it will show you the javascript errors.
Another thing, the code
if($country != NULL){
should be
if(!is_null($country)){
take a look at is_null function.
Another thing, instead of application/x-json json header you should use application/json.
Another thing, the code
echo(json_encode($this->state_model->get_states($country)));
should be
echo(json_encode($this->state_model->get_states($country)));
exit;
otherwise unexpected result might be appended to the final json. Example: CodeIgniter profiling.
Another thing, the code
$countries = array();
if ($query -> result()) {
foreach ($query->result() as $country) {
$countries[$country -> country_id] = $country -> country_name;
}
return $countries;
} else {
return FALSE;
}
should be
$countries = array();
foreach ($query->result() as $country) {
$countries[$country -> country_id] = $country -> country_name;
}
return $countries;
because having no countries and returning FALSE will give you an error in form_dropdown function, take a look inside it. The same goes for get_states function.
This is how much I see in a preliminary look of your code.