I have tried to put this code in my webpage but I have this error :
Parse error: syntax error, unexpected '?' in E:\MyServer\htdocs\...(line 1 from this script)
CODE :
<form action='delete.php?name="<?php echo $contact['name']; ?>"' method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
</form>
this code is in a .php page
Thanks.
Try to format it properly:
<form action="delete.php?name=<?php echo $contact['name']; ?>" method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
</form>
How to get the value you pass through your form:
Welcome <?php echo $_POST["name"]; ?><br>.
EDIT
Also you should add this in delete.php file:
if(isset($_POST['name'])){ $name = $_POST['name']; }
See : http://www.w3schools.com/php/php_forms.asp
You need to drop the double quotes around the variable name and move them to the actual element property.
<form action='delete.php?name="<?php echo $contact['name']; ?>"'
^ ^
It then becomes
<form action="delete.php?name=<?php echo $contact['name']; ?>"
<form action="delete.php?name=<?php echo $contact['name']; ?>" method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
</form>
This should work ..
Do you need to send the data via GET and POST to delete.php?
<form action='delete.php' method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
With this you can then just do $_POST['name'] to get your contact name...
Sorry if I have missed something but cannot see why you would need it passed twice
Related
When I click submit, the data is submitted to the database but the URL id of the book disappears to ----book.php
I want the URL to go back to the id of the page e.g. ----book.php?id=3
Is it possible to keep the first line as action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" and add the value="<?php echo $book_id ?>"?
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<input type="hidden" value="<?php echo $book_id ?>" name="book_id" />
<p>Author: <input type="text" value="<?php echo $_SESSION['author']; ?>" name="author" id="author" readonly /></p>
<p>Summary: <input type="text" name="summary" value="<?php echo $summary;?>" /></p>
<p><input type="submit" name="submit" value="Submit" /></p>
<input type="hidden" name="submitted" value="TRUE" />
</form>
PHP code:
if (isset($_GET['id'])) {
$book_id = $_GET['id'];
}
Please try this code:
// save values in DB
header('Location: book.php?id=' . $book_id);
exit;
It is because $_SERVER["PHP_SELF"] contains only URL . It does not contain get queries . To solve the problem leave your action empty
e.g
<form method="post" action="">.....
You send a POST form but are trying to retrieve a GET value. Additinally, the parameter is named book_id, not id.
Use $book_id = $_POST['book_id'];
if (isset($_GET['id'])) { also won't work, for the same reasons.
There is no name with "id"
If you want to get the book id:
if (isset($_POST['book_id'])) {
$book_id = $_POST['book_id'];
}
OR modify the HTML like this:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<input type="hidden" value="<?php echo $book_id ?>" name="id" />
<p>Author: <input type="text" value="<?php echo $_SESSION['author']; ?>" name="author" id="author" readonly />
</p>
<p>Summary: <input type="text" name="summary" value="<?php echo $summary;?>" /></p>
<p><input type="submit" name="submit" value="Submit" /></p>
<input type="hidden" name="submitted" value="TRUE" />
</form>
On the other hand, if you have problems with POST, just modify the first line of HTML for this one:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]) . "?id=" . echo $book_id; ?>">
You can use anyone of these:
PHP_SELF returns just URL. Use REQUEST_URI that returns URL with query string:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["REQUEST_URI"]);?>">
[you can also omit action values - that will have same behavior]
or if you want just id, then use:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]) . "?id=" . $_GET['id'];?>">
Note: Use validation wherever necessary. I just gave you an idea.
looks like ordinary question but could not find correct solution. lets say I have this form:
<form name="form" action="nextpage.php">
<input type="text" name="input_name" value="<?php echo $_POST['input_name'];?>" />
<input type="submit" name="submit" value="Next"/>
</form>
For example if I add "My input text >" as value of the input the nextpage.php is broken.
I tried to use for:value="<?php echo strip_tags($_POST['input_name']);?>" or
:value="<?php echo htmlspecialchars($_POST['input_name']);?>" but none of them works.. Why is that and how to avoid it? Thanks
First, you should sanitize your posted value for security, but that aside, php provides a function that automatically escapes special characters called addslahes http://php.net/manual/en/function.addslashes.php, save your post value to a variable using the addslashes function, then use the variable as your value.
try this
<?php
$_POST['input_name']="ddd"; ?>
<form name="form" method="POST" action="nextpage.php">
<input type="text" name="input_name" value="<?php echo $_POST['input_name'];?>" />
<input type="submit" name="submit" value="Next"/>
</form>
and in nextpage.php
<?php
$name=$_POST['input_name'];
echo $name;
Try this:
<form name="form" action="nextpage.php" method="POST">
<input type="text" name="input_name" value="<?php echo $_REQUEST['input_name'];?>" />
<input type="submit" value="Next"/>
</form>
can we use $_POST 2 times with different page ?
this example ..
action.php
<form action="next.php" method="post">
<input name="test" value="test" />
<button type="submit" name="test">submit</button>
</form>
next.php
<?php
$test=$_POST['test'];
?>
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="test1">submit</button>
</form>
next1.php
<?php
echo $test2=$_POST['test1']; >> in here i didnt get test1 value . why ?
?>
Within next.php and action.php you need to change your input type like as
<input type="text" name="test" value="test" />
<input type="text" name="test1" value="<?php echo $test; ?>" />
Within next.php and action.php you were missing the type attr of input tag
and you have same name attributes for submit and input within next.php need to remove or change the value from respective
<input type="submit" value="submit"/>
Below code i have tried my local server and it executed successfully.
action.php:-
<form action="next.php" method="POST">
<input type="text" name="test"/>
<input type="submit" value="submit"/>
</form>
next.php:-
<?php
$test = $_POST['test'];
echo $test;
?>
<form action="next1.php" method="POST">
<input name="test1" value="<?php echo $test; ?>" />
<input type="submit" value="submit"/>
</form>
next1.php:-
<?php
$test2=$_POST['test1'];
echo "------".$test2;
?>
Hope this will help.I think this is achieved your requirement.
If you want to do it within one file e.g. index.php then here is the code
<?php
if(isset($_POST['test'])){
if(isset($_POST['test_text'])){
echo 'Output from NEXT: '.$_POST['test_text'];
}
}
elseif(isset($_POST['test1'])){
if(isset($_POST['test_text1'])){
echo 'Output from NEXT1: '.$_POST['test_text1'];
}
}
?>
<table style="width:100%;">
<tr >
<td style="width:50%;">
<form action="" method="post" name="next">
<input type="text" name="test_text" value="<?php echo isset($_POST['test_text']) ? $_POST['test_text']:''; ?>" />
<button type="submit" name="test">submit test1</button>
</form>
</td>
<td style="width:50%;">
<form action="" method="post" name="next1">
<input type="text1" name="test_text1" value="<?php echo isset($_POST['test_text1']) ? $_POST['test_text1']:''; ?>" />
<button type="submit" name="test1">submit test1</button>
</form>
</td>
</tr>
</table>
I hope this will help.
You need to send the POST value with the second form again, e.g. in a hidden field, otherwise the value won't be sent.
Furthermore your submit button shouldn't have the same name as the input field you want the content from. So change the name of your submit button, e.g.:
action.php
<form action="next.php" method="post"> <input name="test" value="test" /> <button type="submit" name="submit">submit</button> </form>
next.php
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="submit">submit</button>
</form>
I have 4 different pages both with one form each.
I want to gather all the entries on each of the pages and submit once.
Here is code.
Page 1
<form action="page2" method="POST">
<input type="text" name="sex">
<input type="submit" value="Submit">
</form>
Page 2
<form action="page3" method="POST">
<input type="text" name="size">
<input type="hidden" name="sex" value="<?php echo $_POST['sex'] ?>" >
<input type="submit" value="Submit">
</form>
Page 3
<form action="page4" method="POST">
<input type="text" name="colors">
<input type="hidden" name="size" value="<?php echo $_POST['size'] ?>" >
<input type="submit" value="Submit">
</form>
Page 4
<form action="verNote.php" method="POST">
<input type="text" name="likes">
<input type="hidden" name="colors" value="<?php echo $_POST['colors'] ?>" > <input type="submit" value="Submit">
</form>
Then i will like to get all the infos on verNote.php
<?php
echo $_POST['sex'];
echo '<br>';
echo $_POST['size'];
echo '<br>';
echo $_POST['color'];
echo '<br>';
echo $_POST['likes'];
?>
This code above dont seem to post entries from both pages 1 and 2, just for 3 and 4 alone gets submitted.
Will appreciate immediate assistance form anyone who understands my question.
Regards!
You need to load the hidden fields again each time
Page 3
<form action="B.php" method="POST">
<input type="text" name="colors">
<input type="hidden" name="size" value="<?php echo $_POST['size'] ?>" >
<input type="hidden" name="sex" value="<?php echo $_POST['sex'] ?>" >
<input type="submit" value="Submit">
</form>
Page 4
<form action="B.php" method="POST">
<input type="text" name="likes">
<input type="hidden" name="colors" value="<?php echo $_POST['colors'] ?>" >
<input type="hidden" name="sex" value="<?php echo $_POST['sex'] ?>" >
<input type="hidden" name="size" value="<?php echo $_POST['size'] ?>" >
<input type="submit" value="Submit">
</form>
I didn't understand 100% what you're trying to achieve, but have you tried using sessions?
Do this in B.php:
<?php
session_start();
if( isset($_POST['sex']))
$_SESSION['sex'] = $_POST['sex'];
if( isset($_POST['size']))
$_SESSION['size'] = $_POST['size'];
if( isset($_POST['color']))
$_SESSION['color'] = $_POST['color'];
if( isset($_POST['likes']))
$_SESSION['likes'] = $_POST['likes'];
?>
Then you can retrieve the values from any other file, just call session_start(); and use the $_SESSION superglobal.
EDIT
Using sessions, you verNote.php file could be something like this:
<?php
session_start();
echo $_SESSION['sex'];
echo '<br />';
echo $_SESSION['size'];
echo '<br />';
echo $_SESSION['color'];
echo '<br />';
echo $_SESSION['likes'];
echo '<br />';
?>
<form method="POST" name="send"
<input type="hidden" name="title" value="<?php echo ($pro->title;?)">
</form>
I dont want people to see the hidden informations , Is this the best way to pass the variable over to my controller?
This the code in my controller
$this->email->subject('subject '.$_POST['title'].' ' );
Thank you!
<form method="POST" name="send"
<input type="hidden" name="title" value="<?php echo ($pro->title;?)">
should be
<form method="POST" name="send">
<input type="hidden" name="title" value="<?php echo $pro->title; ?>" />
For this i will suggest you to use SESSION because hidden fields can be changed.