PHP class method call not displaying all errors - php

Question

<?php
class Validator {
public $errors = array(
'password' => '',
'email' => '');
const PASSWORD_MINCHARS = 8;
public function checkEmail($email) {
if ($this->checkEmpty($email)) {
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
$this->errors['email'] = "Please provide a valid email";
return FALSE;
} else {
return TRUE;
}
} else {
$this->errors['email'] = "Please provide a value for the email";
return FALSE;
}
}
public function checkPassword($string) {
if ($this->checkEmpty($string)) {
if (strlen($string) < self::PASSWORD_MINCHARS) {
$this->errors['password'] = "The password should be atleast ".self::PASSWORD_MINCHARS." characters long.";
return FALSE;
} else {
return TRUE;
}
} else {
$this->errors['password'] = "Please provide a value for the password";
return FALSE;
}
}
private function checkEmpty($string) {
if (!empty($string)) {
return TRUE;
}
return FALSE;
}
public function displayErrors() {
$output = '';
foreach ($this->errors as $error) {
if (!empty($error)) {
$output .= '<p>'.$error.'</p>';
}
}
return $output;
}
}
?>
<?php
require 'Validator.php';
$validator = new Validator();
$email = '';
$password = '';
if ($validator->checkPassword($password) && $validator->checkEmail($email)) {
echo 'You have entered a valid password and email.';
} else {
echo $validator->displayErrors();
}
?>
The above code comes from two separate files. The one that comes begins with class Validator comes from Validator.php while the one that begins with the require function comes from index.php. So am just wondering why the method call that is $validator->displayErrors() in index.php only displays one error at a time instead of displaying them all at once.

Answer 1

There is only one error displayed because of your condition:
if ($validator->checkPassword($password) && $validator->checkEmail($email))
It executes your checkPassword method first, it returns false and so the second condition (which should execute the second validation method) is never checked.
You can avoid this by executing the validation methods first:
$validPassword = $validator->checkPassword($password);
$validEmail = $validator->checkEmail($email);
if ($validPassword && $validEmail) {
echo 'You have entered a valid password and email.';
} else {
echo $validator->displayErrors();
}

Answer 2

Replace
if ($validator->checkPassword($password) && $validator->checkEmail($email))
with
if ($validator->checkPassword($password) || $validator->checkEmail($email)) {