Rotate an image on same page - php

Question

I want to rotate an uploaded and retrieved image from one location. Yes i am almost done. But the problem is, due to header("content-type: image/jpeg") the page redirected to another/or image format. I want to display it in same page as original image in. Here my code..
$imgnames="upload/".$_SESSION["img"];
header("content-type: image/jpeg");
$source=imagecreatefromjpeg($imgnames);
$rotate=imagerotate($source,$degree,0);
imagejpeg($rotate);
i also did with css property.
echo "<img src='$imgnames' style='image-orientation:".$degree."deg;' />";
But anyway my task is to done only with php. Please guide me, or give any reference you have
thanks advance.

Answer 1

<?php
// Okay, so in your upload page
$imgName = "upload/".$_SESSION["img"];
$source=imagecreatefromjpeg($imgName);
$rotate=imagerotate($source, $degree,0);
// you generate a PHP uniqid,
$uniqid = uniqid();
// and use it to store the image
$rotImage = "upload/".$uniqid.".jpg";
// using imagejpeg to save to a file;
imagejpeg($rotate, $rotImage, $quality = 75);
// then just output a html containing ` <img src="UniqueId.000.jpg" />`
// and another img tag with the other file.
print <<<IMAGES
<img src="$imgName" />
<img src="$rotName" />
IMAGES;
// The browser will do the rest.
?>
UPDATE
Actually, while uniqid() usually works, we want to use uniqid() to create a file. That's a specialized usage for which there exists a better function, tempnam().
Yet, tempnam() does not allow a custom extension to be specified, and many browsers would balk at downloading a JPEG file called "foo" instead of "foo.jpg".
To be more sure that there will not be two identical unique names we can use
$uniqid = uniqid('', true);
adding the "true" parameter to have a longer name with more entropy.
Otherwise we need a more flexible function that will check if a unique name already exists and, if so, generate another: instead of
$uniqid = uniqid();
$rotImage = "upload/".$uniqid.".jpg";
we use
$rotImage = uniqueFile("upload/*.jpg");
where uniqueFile() is
function uniqueFile($template, $more = false) {
for ($retries = 0; $retries < 3; $retries++) {
$testfile = preg_replace_callback(
'#\\*#', // replace asterisks
function() use($more) {
return uniqid('', $more); // with unique strings
},
$template // throughout the template
);
if (file_exists($testfile)) {
continue;
}
// We don't want to return a filename if it has few chances of being usable
if (!is_writeable($dir = dirname($testfile))) {
trigger_error("Cannot create unique files in {$dir}", E_USER_ERROR);
}
return $testfile;
}
// If it doesn't work after three retries, something is seriously broken.
trigger_error("Cannot create unique file {$template}", E_USER_ERROR);
}

Answer 2

You need to generate the image separately - something like <img src="path/to/image.php?id=123">. Trying to use it as a variable like that isn't going to work.