failed to insert multiple data in mysqli using loop - php

Question

I want to store one's friends of facebook into a table. The result of below code shows only a single record is inserted. It wasn't the problem of my loop because I echo the name, it all appeared.
foreach($user_friends['data'] as $friend){
//echo $friend['name'] . "</br>";
$userImg = "https://graph.facebook.com/".$friend['id']."/picture?width=200&height=200";
$friendsName = $friend['name'];
$stmt3 = $db->prepare("INSERT INTO allfriend(`uId`,`name`,`img`,`friendOf`) VALUES (?,?,?,?)");
$stmt3->bind_param('ssss', $user_fbid, $friendsName, $userImg, $user_fbid);
$stmt3->execute();
}

Answer 1

You're misusing the prepare / bind feature slightly. You only need to prepare once, but you do need to reset the statement after each use.
Also, you should check for failure of your statements. If you do that you may find out why things might work differently from what you expect.
Is it possible your column friend.uID is in fact a primary key? The code you've shown tries to insert the same value into multiple rows. That could be your problem.
Try this:
$stmt3 = $db->prepare
("INSERT INTO allfriend(`uId`,`name`,`img`,`friendOf`) VALUES (?,?,?,?)")
|| die "prepare failed: ". $db->error;
foreach($user_friends['data'] as $friend) {
//echo $friend['name'] . "</br>";
$userImg = "https://graph.facebook.com/".$friend['id']."/picture?width=200&height=200";
$friendsName = $friend['name'];
$stmt3->bind_param('ssss', $user_fbid, $friendsName, $userImg, $user_fbid)
|| die "bind_param failed " . $db->error;
$stmt3->execute()
|| die "execute failed " . $db->error;
$stmt3->reset()
|| die "reset failed " . $db->error;
}