Is it possible to use models in laravel routes without static? - php

For example I need to return comments. I already have a method for this in my model. Is it possible to do something like this?
Route::get('/comments/{page}', function($page) {
$comments = Comments::get($page);
return Response::json($comments);
});
Or do I need to create a facade for each model?

Typically, comments would be associated with a page via an Eloquent relationship, which would allow something like this:
return Response::json($page->comments);

Check Defining A Query Scope on Laravel website:
// In Comments Model
public function scopeGetMessage($query, $page)
{
// You can use $query->where(...)
// return the query for chaining
// You can use $this->where(...)
// Or just return the thing you want
}
Now you may call it like:
$comments = Comments::getMessage($page);

Related

Dynamic model filter in Laravel's Eloquent

I'm looking for a way to make a dynamic & global model filter in Laravel.
I'm imagining a function like the following in my User.php model:
public function filter() {
return ($someVariable === true);
}
Whenever I do a query using Eloquent's query builder, I only want users to show up in the collection when the filter above returns true. I would have thought a feature like that existed, but a quick look at the documentation suggests otherwise. Or did I miss it?
I believe what you're looking for is Query Scopes.
They are methods that may be defined in a global or local context, that mutate the current query for a given model.
https://laravel.com/docs/5.5/eloquent#query-scopes
For example:
Lets say I have a database table called "Teams" and it has a column on it called "Wins." If I wanted to retrieve all Teams that had a number of Wins between Aand B I could write the following Local scope method on the teams model:
public function scopeWinsBetween($query, int $min, int $max)
{
return $query->whereBetween('wins', $min, $max);
}
And it could be invoked as such:
$teams = Teams::winsBetween(50, 100)->get();
I think you could use Collection macro but you will need to suffix all your eloquent get(); to get()->userDynamicFilter();
Collection::macro('userDynamicFilter', function () {
//$expected = ...
return $this->filter(function ($value) use($expected) {
return $value == $expected;
});
});
Thanks. For now I've simply added a post filter option to the models using the following code:
// Apply a post filter on the model collection
$data = $data->filter(function($modelObject) {
return (method_exists($modelObject, 'postFilter')) ? $modelObject->postFilter($modelObject) : true;
});
in Illuminate/Database/Eloquent/Builder.php's get() function, after creating the collection. This allows me to add a function postFilter($model) into my model which returns either true or false.
Probably not the cleanest solution but a working one for now.

laravel orm: different result from almost same query

I've a very big doubt about how works laravel for a very simple thing:
If I call:
$companies=User::All();
Then I can use statement like this in a forach:
foreach($companies as $company)
$company['new_field']= 'something';
If i'm limiting the output of the query like:
$companies = DB::table('companies')
->select('id','name','email','business_name',...)->get();
The things doesnt work as before,
I try with or without the ->get()
I try to convert with ->toArray() (errors rised)
I try with put() and push() for collections method and agains errors...
How can I add a field in every item of the collection just to pass it to a view?
Try like this, hope it works for you:
$users=User::select('id','name','email','business_name',...)->get()->toArray();
and then use foreach loop like this:
foreach($users as $key => $value ){
$users[$key]['newField'] = "Demo";
}
If you are using Laravel and model in it so there is a better way to add custom attribute or field here is what i do for custom field
For Example :
There is a Model Name User
so in User Model
add a property name appends like :
class User extends Model
{
protected $appends = ['new_field'];
public function getNewFieldAttribute() // defining field logic here
{
return // your code
}
So you no need to use foreach and looping and adding new field
for more have a look on laravel doc : https://laravel.com/docs/5.5/eloquent-mutators#accessors-and-mutators
Suggestion
you can limit your output with Model too.
User::select('id','name','email','business_name',...)->get();
if you are making an array like
User::select('id','name','email','business_name',...)->get()->toArray();
so this will also give you your custom field

Laravel's Eloquent table 'inheritence' with parents

I have a Laravel model acl_groups that has a JSON column inherits. What should I do, the "laravel way" to query the inherited groups when checking if a group can do something? The rights are stored in another JSON column, allow/deny so I can just do a in_array to check a single group if they have access.
On your model you can set a getter
public function getInheritsAttribute($v)
{
return $v ? json_decode($v, true) : [];
}
OR
if you dont want a getter you can try a pseudo getter
public function getPseudoAttribute()
{
return $this->inherits ? json_decode($this->inherits, true) : [];
}
Kind of maybe did mistake on second one.
And on other model the same thing
so when you call $item->inherits = you will get an array
First you may try to prepare the array like removing same keys or values
and after just check
if (array_key_exists('thing_to_check', $item->inherits)) {
return true;
}
This is not a working code, it is just an idea how you can do you.
Take a look at Cartalyst Sentinel how they check the permissions for groups and users.

How to check if row is soft-deleted in Eloquent?

In Laravel 5.1 is there a nice way to check if an eloquent model object has been soft-deleted? I'm not talking about selecting data but once I have the object e.g. Thing::withTrashed()->find($id)
So far the only way I can see is
if ($thing->deleted_at !== null) { ... }
I do not see any relevant method in the API that would allow for example
if ($thing->isDeleted()) { ... }
Just realised I was looking in the wrong API. The Model class doesn't have this, but the SoftDelete trait that my models use has a trashed() method.
So I can write
if ($thing->trashed()) { ... }
In laravel6, you can use followings.
To check the Eloquent Model is using soft delete:
if( method_exists($thing, 'trashed') ) {
// do something
}
To check the Eloquent Model is using soft delete in resource (when using resource to response):
if( method_exists($this->resource, 'trashed') ) {
// do something
}
And finally to check if the model is trashed:
if ($thing->trashed()) {
// do something
}
Hope, this will be helpful!
For those seeking an answer on testing environment, within laravel's test case
you can assert as:
$this->assertSoftDeleted($user);
or in case it's just deleted (without soft deleting)
$this->assertDeleted($user);
This is the best way
$model = 'App\\Models\\ModelName';
$uses_soft_delete = in_array('Illuminate\Database\Eloquent\SoftDeletes', class_uses($model));
if($usesSoftDeletes) {
// write code...
}
This worked for me
$checkDomain = Domain::where('tenant_id', $subdomain)->withTrashed()->first();
if($checkDomain->trashed()){
return redirect()->route('domain.not.found');
}else{
return view('frontend.' . theme() . '.index');
}

Laravel 4: How to apply a WHERE condition to all queries of an Eloquent class?

I'm trying to implement an "approved' state for a table I have, it's pretty straightforward, basically, if the row's approve column equals 1; that row should be retrieved, otherwise it shouldn't.
The problem is, now I have to go through the whole codebase and add a WHERE statement(i.e., function call) which is not only time consuming but also inefficient(if I ever want to remove that feature, etc.)
How can I do that? Is it as easy as adding $this->where(..) inside the Eloquent child class' constructor? Wouldn't that affect other CRUD operations? such as not updating an unapproved row?
The answer was given when there was no query scope feature available.
You can override the main query, only for the Post model, like
class Post extends Eloquent
{
protected static $_allowUnapprovedPosts = false;
public function newQuery()
{
$query = parent::newQuery();
if (!static::$_allowUnapprovedPosts) {
$query->where('approved', '=', 1);
} else {
static::$_allowUnapprovedPosts = false;
}
return $query;
}
// call this if you need unapproved posts as well
public static function allowUnapprovedPosts()
{
static::$_allowUnapprovedPosts = true;
return new static;
}
}
Now, simply use anything, but unapproved users won't appear in the result.
$approvedPosts = Post::where('title', 'like', '%Hello%');
Now, if you need to retrieve all posts even unapproved ones then you can use
$approvedPosts = Post::allowUnapprovedPosts()->where('title', 'like', '%Hello%');
Update (Using the query scope):
Since, Laravel now provides Global Query Scopes, leverage that instead of this hacky solution, notice the date of this answer, it's too old and so much things changed by now.
// Using a local query scope
class Post extends Eloquent
{
public function scopeApproved($query)
{
return $query->where('approved', 1);
}
}
You can use it like:
$approvedPosts = Post::approved()->get();
The closest thing I found is Eloquent query scope.
Even though it requires a minor change in my code(prefixing queries) it still gives me what I'm looking with great flexibility.
Here's an example:
Create a function within the Eloquent child class:
class Post extends Eloquent {
public function scopeApproved($query)
{
return $query->where('approved', '=', 1/*true*/);
}
}
Then simply use it like this:
$approvedPosts = Post::approved()-><whatever_queries_you_have_here>;
Works perfectly. No ugly repeated WHERE function calls. easy to modify. Much easier to read(approved() makes much more sense than where('approved', '=', 1) )
You can use global scope for your need, docs for that are here : https://laravel.com/docs/5.6/eloquent#query-scopes
Good example is SoftDeletingScope which is applied to all queries by default on models which use SoftDeletes trait.

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