How do I concatenate html and php? - php

Question

I currently have this:
$output .= '
<tr>
<th style="text-align: left">'.(__("Item", "WSPSC")).'</th><th>'.(__("Quantity", "WSPSC")).'</th><th>'.(__("Price", "WSPSC")).'</th><th></th>
</tr>';
But I need to replace Item with a piece of php like:
$output .= '
<tr>
<th style="text-align: left">'.(__("
<?php if(ICL_LANGUAGE_CODE=='en'); ?>
Item
<?php elseif(ICL_LANGUAGE_CODE=='it'); ?>
Products
<?php endif; ?>
", "WSPSC")).'</th><th>'.(__("Quantity", "WSPSC")).'</th><th>'.(__("Price", "WSPSC")).'</th><th></th>
</tr>';
The issue I am having is that this is obviously wrong but I can't get my head around the correct concatenation of html and php

Answer 1

If I right understand you need something like this:
$output .= '
<tr>
<th style="text-align: left">'.
(
(ICL_LANGUAGE_CODE=='en')?
'Item':
( (ICL_LANGUAGE_CODE=='it')? 'Products': '' ),
"WSPSC"
)
.'</th><th>'.(__("Quantity", "WSPSC")).'</th><th>'.(__("Price", "WSPSC")).'</th><th></th>
</tr>';

Answer 2

You should not use it in that way. Look at this pseudo code:
$output .= '
<tr>
<th style="text-align: left">';
if (something...) {
$output.= 'sss';
}
elseif (something...) {
$output.= 'ddd';
}
That's the way you should do it.

Answer 3

Your replies helped me thanks, this worked:
$output .= '
<tr>
<th style="text-align: left">';
if (ICL_LANGUAGE_CODE=='en') {
$output .= (__("Item", "WSPSC"));
} elseif (ICL_LANGUAGE_CODE=='it') {
$output .= (__("PRODOTTO", "WSPSC"));
}
$output .= '</th><th>'.(__("Quantity", "WSPSC")).'</th><th>'.(__("Price", "WSPSC")).'</th><th></th>
</tr>';