Editable Datatables PHP MySQL jQuery - php

I have a table which is fed dynamically from the database, this works as it should, I've then put the datatables functionality on the top which is working well, the sorting, search, the pagination is again working as it should.
I'm now looking at being able to edit a row and update the data back into the db and refresh the table.
My table structure
<table class="table table-striped table-hover table-bordered" id="tobebookedtable">
<thead>
<tr>
<th style="display:none;">PropID</th>
<th>ProjectNo</th>
<th>Householder</th>
<th>HouseNoName</th>
<th>Street Name</th>
<th>Postcode</th>
<th>Telephone</th>
<th>EPCPlanned</th>
<th>TAM</th>
</tr>
</thead>
<tbody>
<tr>
<?php
$planning = db::getInstance()->query('CALL sp_tobebooked()');
foreach ($planning->results() as $planning) {
?>
<td style="display:none;"><?php echo $planning->PropID; ?></td>
<td><?php echo $planning->ProjectNo; ?></td>
<td><?php echo $planning->Householder; ?></td>
<td><?php echo $planning->HouseNoName; ?></td>
<td><?php echo $planning->StreetName; ?></td>
<td><?php echo $planning->Postcode; ?></td>
<td><?php echo $planning->Telephone; ?></td>
<td><?php echo $planning->EPCPlanned; ?></td>
<td><?php echo $planning->TAM; ?></td>
</tr>
<?php }; ?>
</tbody>
</table>
The EPCPlanned is the only field I want to update.
This here is my code for the jQuery side, the edit ability works, I can click into a cell and edit the record.
<script type="text/javascript">
$(document).ready(function() {
$('#tobebookedtable').dataTable( {
//"bProcessing": true,
//"bServerSide": true,
//"bJQueryUI": true,
"bPaginate": true,
"bStateSave": true
} );
/* Init DataTables */
var oTable = $('#tobebookedtable').dataTable();
/* Apply the jEditable handlers to the table */
oTable.$('td').editable( 'tobebooked_edit.php', {
"callback": function( sValue, y ) {
var aPos = oTable.fnGetPosition( this );
oTable.fnUpdate( sValue, aPos[0], aPos[1] );
//window.location.reload();
},
"submitdata": function ( value, settings ) {
console.log(value);
console.log(settings);
return {
"row_id": this.parentNode.getAttribute('id'),
"column": oTable.fnGetPosition( this )[2]
};
},
"height": "26px",
"width": "100%"
} );
} );
</script>
this is the tobebooked_edit.php
<?php
require 'core/init.php';
$table="temp_tobebooked";
$rawdata = $_POST;
$query = "show columns from $table";
$result= mysql_query($query) or die(mysql_error());
$fields = array();
while ( $row = mysql_fetch_assoc($result) )
{
$fieldname = $row['Field'];
array_push($fields, $fieldname);
}
$id = $rawdata['row_id'];
$value = $rawdata['value'];
$column = $rawdata['column'];
$column = $column + 1;
$fieldname = $fields[$column];
$value = utf8_decode($value);
$query = "update $table set $fieldname = '$value' where PropID = '$id'";
$result = mysql_query($query);
if (!$result) { echo "Update failed"; }
else { echo "UPD: $value"; }
?>
When it all runs and I update a record the field Updates on the screen and shows with the "UPD:" and the entered value.
But when I check my database there is no record updated. No errors show either
How can I get the data to update in my db?

First of all, I think that this
<tr>
<?php
$planning = db::getInstance()->query('CALL sp_tobebooked()');
foreach ($planning->results() as $planning) {
?>
should be
<?php
$planning = db::getInstance()->query('CALL sp_tobebooked()');
foreach ($planning->results() as $planning) {
?>
<tr>
Then, with
"row_id": this.parentNode.getAttribute('id'),
for each td element, you select the tr element and search for the id attribute, that doesn't exists

Firstly as per rsella's comment you nee to move the row inside the loop.
Secondly as suspected you are holding the ID in a hidden cell which is infact a sibling of the editable elements rather than the parent. Try changing the table structure to the following
<tbody>
<?php
$planning = db::getInstance()->query('CALL sp_tobebooked()');
foreach ($planning->results() as $planning) {
?>
<tr id="<?php echo $planning->PropID; ?>" >
<td><?php echo $planning->ProjectNo; ?></td>
<td><?php echo $planning->Householder; ?></td>
<td><?php echo $planning->HouseNoName; ?></td>
<td><?php echo $planning->StreetName; ?></td>
<td><?php echo $planning->Postcode; ?></td>
<td><?php echo $planning->Telephone; ?></td>
<td><?php echo $planning->EPCPlanned; ?></td>
<td><?php echo $planning->TAM; ?></td>
</tr>
<?php };
?>
</tbody>
This should mean that the parent has an ID and thus this.parentNode.getAttribute('id') should be able returning the required value.
As you're only editing the EPCPlanned cell then an alternative would be
<tbody>
<?php
$planning = db::getInstance()->query('CALL sp_tobebooked()');
foreach ($planning->results() as $planning) {
?>
<tr>
<td><?php echo $planning->ProjectNo; ?></td>
<td><?php echo $planning->Householder; ?></td>
<td><?php echo $planning->HouseNoName; ?></td>
<td><?php echo $planning->StreetName; ?></td>
<td><?php echo $planning->Postcode; ?></td>
<td><?php echo $planning->Telephone; ?></td>
<td id="<?php echo $planning->PropID; ?>"><?php echo $planning->EPCPlanned; ?></td>
<td><?php echo $planning->TAM; ?></td>
</tr>
<?php };
?>
</tbody>
and in your JQuery change "row_id": this.parentNode.getAttribute('id') to this.getAttribute('id')

Related

php find a specify word in a specific column from stored proc sql server

I'm kind of new in php and i'm searching a way to get some words from a specific column that i get from a sql server stored proc. These 'words' will me to use them as style for my css
Example :
Column HTML_CODE has sometime 'bold', 'green' or something else. Sometime they are in the same column, not always in the same order. I don't know how to use them in my loop. See what i has until now :
$result = sqlsrv_query($conn, $sql);
while ($row = sqlsrv_fetch_array($result))
{
//print_r( $row ); // debug code
if ($row['HTML_CODE'] == 'BOLD(), Green()'){
$couleur='green';
$font= 'bold';
}
else {
$couleur='black';
$font= 'normal';
}
?>
<tbody>
<tr>
<?php echo "<tr style=\"font-weight:$font; color:$couleur;\">"; ?>
<td><?php echo ($row['Nom']); ?></td>
<td><?php echo ($row['Quantite']); ?></td>
<td><?php echo ($row['Montant']); if (is_numeric($row['Montant'])) {
echo ' $';
}?></td>
<td><?php echo ($row['#GL']); ?></td>
<td><?php echo ($row['Debit']); if (is_numeric($row['Debit'])) {
echo ' $';
} ?></td>
<td><?php echo ($row['Credit']); if (is_numeric($row['Credit'])) {
echo ' $';
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How to retrieve data from database and display it in table

I am using WordPress and the global class $wpdb in order to retrieve data from MySQL database and display the results in a table.
I have 4 dropdown list that allow the user to select the required inputs then based on the selected inputs the system display all the related data for the user selection.
When I try to run the code it display error:
Notice: Array to string conversion
first part of code :
<?php
/*
Template Name: search info
*/
get_header();
?>
<?php
// code for submit button ation
global $wpdb,$_POST;
//variables that handle the retrieved data from mysql database
if(isset($_POST['site_name']))
{
$site_name=$_POST['site_name'];
}
else { $site_name=""; }
if(isset($_POST['owner_name']))
{
$owner_name=$_POST['owner_name'];
}
else { $owner_name=""; }
if(isset($_POST['Company_name']))
{
$company_name=$_POST['Company_name'];
}
else { $company_name=""; }
if(isset($_POST['Subcontractor_name']))
{
$Subcontractor_name=$_POST['Subcontractor_name'];
}
else { $Subcontractor_name="";}
$site_id = ['siteID'];
$equipment_type = ['equipmentTYPE'];
$lat=['latitude'];
$long=['longitude'];
$height = ['height'];
$owner_contact = ['ownerCONTACT'];
$sub_contact = ['subcontractorCONTACT'];
$sub_company = ['subcontractorCOMPANY'];
if(isset($_POST['query_submit']))
{
//query to retrieve all related info of the selected data from the dropdown list
$query_submit =$wpdb->get_results ("select
site_info.siteID,site_info.siteNAME ,site_info.equipmentTYPE,site_coordinates.latitude,site_coordinates.longitude,site_coordinates.height ,owner_info.ownerNAME,owner_info.ownerCONTACT,company_info.companyNAME,subcontractor_info.subcontractorCOMPANY,subcontractor_info.subcontractorNAME,subcontractor_info.subcontractorCONTACT from `site_info`
LEFT JOIN `owner_info`
on site_info.ownerID = owner_info.ownerID
LEFT JOIN `company_info`
on site_info.companyID = company_info.companyID
LEFT JOIN `subcontractor_info`
on site_info.subcontractorID = subcontractor_info.subcontractorID
LEFT JOIN `site_coordinates`
on site_info.siteID=site_coordinates.siteID
where
site_info.siteNAME = `$site_name`
AND
owner_info.ownerNAME = `$owner_name`
AND
company_info.companyNAME = `$company_name`
AND
subcontractor_info.subcontractorNAME = `$Subcontractor_name`
");
?>
<table width="30%" >
<tr>
<td>Site Name</td>
<td>Owner Name</td>
<td>Company Name</td>
<td>Subcontractor Name</td>
</tr>
<tr>
<td><?php echo $site_name ; ?></td>
<td><?php echo $owner_name ; ?></td>
<td><?php echo $company_name ; ?></td>
<td><?php echo $Subcontractor_name ; ?></td>
<td><?php echo $site_id ; ?></td>
<td><?php echo $equipment_type ; ?></td>
<td><?php echo $lat ; ?></td>
<td><?php echo $long ; ?></td>
<td><?php echo $height ; ?></td>
<td><?php echo $owner_contact ; ?></td>
<td><?php echo $sub_contact ; ?></td>
<td><?php echo $sub_company ; ?></td>
</tr>
</table>
<?php } ?>
The second part of code is for retrieve data from database and includes it in the dropdown list.
I will appreciate any help.
You can get rid of the "Array to string conversion" error quite easy.
In these lines, you are creating arrays:
$site_id = ['siteID'];
$equipment_type = ['equipmentTYPE'];
$lat=['latitude'];
...
$sub_company = ['subcontractorCOMPANY'];
...which you later are trying to echo. You simply can't echo arrays.
Just change the above to be strings instead:
$site_id = 'siteID';
$equipment_type = 'equipmentTYPE';
$lat = 'latitude';
...
$sub_company = 'subcontractorCOMPANY';
Note: As others already pointed out, your code is wide open to SQL Injections. You should really escape your data, before using it in any queries.
<table border="1">
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Points</th>
</tr>
<?php
global $wpdb;
$result = $wpdb->get_results ( "SELECT * FROM myTable" );
foreach ( $result as $print ) {
?>
<tr>
<td><?php echo $print->firstname;?></td>
</tr>
<?php }

Unable to fetch correct data. Invalid argument supplied for foreach() warning

The query isn;t running, not sure where Iam going wrong
Input from previous page was doctor's licence number and date from javascript calender
Posting the values using fetchApponitment function to next page->
if(isset($_POST['BookAppointment']))
{ $DOCTOR_LICENSE_NO = $_POST['DOCTOR_LICENSE_NO'];
$APPOINTMENT_DATE = $_POST['APPOINTMENT_DATE'];
}
$appointmentdetails = fetchAppointments($DOCTOR_LICENSE_NO,$APPOINTMENT_DATE);
?>
<table class="table-style-three">
<thead>
<!-- display Doctor details header -->
<th>DOCTOR_LICENSE_NO</th>
<th>DOCTOR_FNAME</th>
<th>DOCTOR_LNAME</th>
<th>DOCTOR_EMAIL_ID</th>
<th>DOCTOR_PHONE</th>
<th>APPOINTMENT_DATE</th>
<th>APPOINTMENT_TIME</th>
<th>APPOINTMENT_STATUS</th>
</thead>
<tbody>
<?php
foreach($appointmentdetails as $displayAppointment) { ?> <!-- foreach is very important -->
<tr>
<td><?php print $displayAppointment['DOCTOR_LICENSE_NO']; ?></td>
<td><?php print $displayAppointment['DOCTOR_FNAME']; ?></td>
<td><?php print $displayAppointment['DOCTOR_LNAME']; ?></td>
<td><?php print $displayAppointment['DOCTOR_EMAIL_ID']; ?></td>
<td><?php print $displayAppointment['DOCTOR_PHONE']; ?></td>
<td><?php print $displayAppointment['APPOINTMENT_DATE']; ?></td>
<td><?php print $displayAppointment['APPOINTMENT_TIME']; ?></td>
<td><?php print $displayAppointment['APPOINTMENT_STATUS']; ?></td>
</tr>
<?php } ?>
</tbody>
</table>
</body>
</html>
<?php require_once("footer.php");?>
The function looks like this -->
function fetchAppointments($DOCTOR_LICENSE_NO,$APPOINTMENT_DATE) {
global $mysqli,$DOCTOR_LICENSE_NO, $APPOINTMENT_DATE, $db_table_prefix,$row;
$args = array($DOCTOR_LICENSE_NO, $APPOINTMENT_DATE);
//echo $DOCTOR_LICENSE_NO;
//echo $APPOINTMENT_DATE;
echo $args[0];
echo $args[1];
$stmt = $mysqli->prepare(
"SELECT doctor.DOCTOR_LICENSE_NO,
doctor.DOCTOR_FNAME,
doctor.DOCTOR_LNAME,
doctor.DOCTOR_EMAIL_ID,
doctor.DOCTOR_PHONE,
appointment.APPOINTMENT_DATE,
appointment.APPOINTMENT_TIME,
appointment.APPOINTMENT_STATUS
FROM doctor INNER JOIN appointment ON (doctor.DOCTOR_LICENSE_NO = appointment.DOCTOR_LICENSE_NO)
WHERE doctor.DOCTOR_LICENSE_NO= ?
AND appointment.APPOINTMENT_DATE= ? ");
$stmt->bind_param("ss",$args[0], $args[1]);
$stmt->execute();
$stmt->bind_result($DOCTOR_LICENSE_NO,$DOCTOR_FNAME, $DOCTOR_LNAME, $DOCTOR_EMAIL_ID, $DOCTOR_PHONE,$APPOINTMENT_DATE , $APPOINTMENT_TIME, $APPOINTMENT_STATUS);
while ($stmt->fetch()){
$row[] = array(
'DOCTOR_LICENSE_NO' => $DOCTOR_LICENSE_NO,
'DOCTOR_FNAME' => $DOCTOR_FNAME,
'DOCTOR_LNAME' => $DOCTOR_LNAME,
'DOCTOR_EMAIL_ID' => $DOCTOR_EMAIL_ID,
'DOCTOR_PHONE' => $DOCTOR_PHONE,
'APPOINTMENT_DATE' => $APPOINTMENT_DATE ,
'APPOINTMENT_TIME' => $APPOINTMENT_TIME,
'APPOINTMENT_STATUS' => $APPOINTMENT_STATUS
);
}
$stmt->close();
return ($row);
}

php code to break page after 6th row

I try to display 2 table side by side with php code....
but i need to display only 6 table on single page ......and rest on another page......
so plz can any one help me to break page or break loop after 6th iteration..... 7th table display on another page like wise...
plz see my image attached below....i am facing problem on print preview...
page breaks my table during print...like below image...
I attached croped imaged here...
my page actuaally display 8 tables on single page...but i need is only 6 on one page.
below is my code..
<?php if (is_array($data)) { foreach($data as $row) { ?>
<table border="1px solid #666" summary="" width="48%" class="pos_fixed1">
<thead>
<tr>
<td colspan="4">Dainik Bhaskar Nagpur</td>
</tr>
<tr>
<td>Receipt</td>
<td><?php echo htmlspecialchars($row['receipt_no']); ?></td>
<td>Coupon</td>
<td><?php echo htmlspecialchars($row['coupon']); ?></td>
</tr>
<tr>
<td>Receipt Date</td>
<td><?php echo htmlspecialchars($row['bookingdate']); ?></td>
<td>Coupon Date</td>
<td><?php echo htmlspecialchars($row['coupondate']); ?></td>
</tr>
<tr>
<td>Copy Start Date</td>
<td><?php echo htmlspecialchars($row['startingdate']); ?></td>
<td>HawkerName</td>
<td><?php echo htmlspecialchars($row['hawkername']); ?></td>
</tr>
<tr>
<td>SubagentName</td>
<td><?php echo htmlspecialchars($row['subagentname']); ?></td>
<td>CenterName</td>
<td><?php echo htmlspecialchars($row['ward']); ?></td>
</tr>
<tr>
<td>customer</td>
<td><?php echo htmlspecialchars($row['customer_name']); ?></td>
<td>Address</td>
<td><?php echo htmlspecialchars($row['society']); ?></td>
</tr>
</thead>
</table>
<?php } }?>
Try using CSS:
<style>
#media print {
.pageBreak {
page-break-after: always;
}
}
</style>
And at every 6 table, add a pageBreak:
<?php
$lineCounter = 0;
if (is_array($data)) {
foreach($data as $row) {
$lineCounter++;
?>
<!-- output a table... -->
<?php
if($lineCounter % 6 == 0) {
echo '<span class="pageBreak"></span>' . PHP_EOL;
}
}
}
?>
<?php
// get total records
TotalNoOfRecords = count($data);
$Count = 1;
foreach($data as $row) {
// write here your content
// break page after 6 rows
if($Count % 6 == 0 && $Count != $TotalNoOfRecords)
{
echo "<p style='page-break-after:always'></p>";
}
$Count++;
}
?>
try this is code or visit link
<?php
$q = "SELECT * FROM your_table ";
$myq = mysqli_query($link, $q);
$fixtures ='';
$i=0;
while($row=mysqli_fetch_assoc($myq)) {
$r[]=$row;
}
foreach ($r as $val) {
$i++;
?>
<!-- your value from database -->
<table>
<tr>
<td><?php echo $val['your_column']; ?></td>
</tr>
</table>
<!-- your value from database -->
<?php
if($i % 6==0){
echo '<div style="page-break-after: always;">[------ break ------]</div>' . PHP_EOL;
$i=0;
}
}
?>

Nothing on my page with an exception of the header after SQL query and table

I've been troubleshooting for a while now, and I really can't find any answer. Basically this is what it looks like:
When I type the name of a real user: Nothing posted on the page with an exception of the header
When I type a fake user: User has not been found (direct translation from Norwegian in the code)
<?php
include_once("moduler/head.php");
$user = $_GET['user'];
$query1 = $con->query("SELECT * FROM players WHERE name='$user'");
echo $con->error;
if ($query1->num_rows == 0) {
echo "<h1>Ingen spiller funnet med: $user.</h1>";
return;
}
while ($row == mysqli_fetch_array($query1)) {
$styrkeLvl = $row['styrke'];
$beskyttelseLvl = $row['beskyttelse'];
$bueskytingLvl = $row['bueskyting'];
$trehuggingLvl = $row['trehugging'];
$gruvedriftLvl = $row['gruvedrift'];
$fiskingLvl = $row['fisking'];
$kills = $row['kills'];
$deaths = $row['deaths'];
$rank = $row['rank'];
$money = $row['money'];
$donstatus = $row['donationstatus'];
$lastlogin = $row['lastlogin'];
$regtime = $row['registrationtime'];
$rankName = getRankString($rank);
?>
<h1><?php echo $user; ?></h1>
<table class=\"userView\">
<tbody>
<tr><td>Brukerstatus</td>
<td><?php echo $rankName; ?></td>
</tr>
<tr><td>Donasjon status</td>
<td>D<?php echo $donstatus; ?></td>
</tr>
<tr><td>Styrke level</td>
<td><?php echo $styrkeLvl; ?></td>
</tr>
<tr><td>Beskyttelse level</td>
<td><?php echo $beskyttelseLvl; ?></td>
</tr>
<tr><td>Bueskyting level</td>
<td><?php echo $bueskytingLvl; ?></td>
</tr>
<tr><td>Trehugging level</td>
<td><?php echo $trehuggingLvl; ?></td>
</tr>
<tr><td>Fisking level</td>
<td><?php echo $fiskingLvl; ?></td>
</tr>
<tr><td>Drap</td>
<td><?php echo $kills; ?></td>
</tr>
<tr><td>Dødsfall</td>
<td><?php echo $deaths; ?></td>
</tr>
<tr><td>Sist pålogget</td>
<td><?php echo $lastlogin; ?></td>
</tr>
<tr><td>Registreringsdato</td>
<td><?php echo $regtime; ?></td>
</tr>
</tbody>
</table>
<?php
}
?>
Any ideas? I've also tried running the entire thing in an echo with no result
Thanks
All your variables inside the while loop are only available inside the while loop. so you cannot echo them in the tables. so <td><?php echo $rankName; ?></td> will give you an undefined variable error. The same applies for the other variables you are trying to display.
To avoid this you should try to declare your variables globally, or put your table inside the loop.
Also the other issue is that as it is the code inside the loop will never execute because of the double equal (==). You should use double equal (==) for comparison and single equal (=) for assignment.
So you have to change while ($row == mysqli_fetch_array($query1)) to while ($row = mysqli_fetch_array($query1))

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