"No data supplied for parameters in prepared statement" global insert function - php

Question

I wrote an global function that getting array with keys and values, and inserting it to mysql db. something like this:
function insert_to_db($table, $data, $is_using_id) {
// I'm connecting to db before this code.
global $mysqli;
// .. Checking for errors ..
// .. if using id, remove the id from the values like this:
$columns = array_keys($data);
$values = array_values($data);
if ($is_using_id == true) {
unset($values[0]);
// Reorder the array after unset()
$values = array_merge($values);
}
// ..
// Generating text for use at the mysqli::prepare
$columns_text = "";
$i = 0;
while ($i < count($columns)) {
$column = $columns[$i];
if ($i == 0) {
$columns_text = $column;
} else {
$columns_text = $columns_text.", ".$column;
}
$i++;
}
unset($i);
unset($column);
$values_text = "";
// b_p_f is the $types string for mysqli-stmt::bind_param
$b_p_f = "";
// Generating text for use at the mysqli::prepare
$i = -1;
while ($i < count($values)) {
echo "\$i equals to {$i}<br>";
if ($is_using_id == true && $i == -1) {
// Null because id is calculated automatically by mysql
$values_text = "NULL";
} else if ($is_using_id == false && $i == 0) {
$value = $values[$i];
$values_text = "?";
if (is_numeric($value))
{
$b_p_f = 'i';
} else {
$b_p_f = 's';
}
} else {
$value = $values[$i];
$values_text = $values_text.", ?";
if (is_numeric($value))
{
echo "Value: {$value} Found as numberic<br>";
$b_p_f = $b_p_f.'i';
} else {
echo "Value: {$value} Found as non-numberic<br>";
$b_p_f = $b_p_f.'s';
}
}
$i++;
}
unset($i);
unset($value);
echo "b_p_f:";
var_dump($b_p_f);
echo " values:";
var_dump($values);
$stmt = $mysqli->prepare("INSERT INTO ".$table." (".$columns_text.") VALUES (".$values_text.")");
if (!$stmt) {
return array("error"=>"true", "error_mysqli"=>$mysqli->error, "MORE"=>"INSERT INTO ".$table." (".$columns_text.") VALUES (".$values_text.")");
}
$stmt->bind_param($b_p_f, $values);
if ($stmt->execute()) {
return array("error"=>"false", "inserted_id"=>$mysqli->insert_id);
} else {
return array("error"=>"true", "error_stmt"=>$stmt->error, "MORE"=>"INSERT INTO ".$table." (".$columns_text.") VALUES (".$values_text.")");
}
}
Then I am calling to the function:
function hash_password($password) {
$options = [ 'cost' => 12 ];
return password_hash($password, PASSWORD_BCRYPT,$options);
}
$data = array(
"ID" => NULL,
"first_name" => "Alexander",
"last_name" => "Margolis",
"email" => "shay24590#gmail.com",
"username" => "smartDonkey",
"password" => "Incorrect",
"birthday" => "12-12",
"date_added" => time(),
"total_points" => 0,
"cafe_added" => 0,
"review_placed"=> 0);
$data["password"] = hash_password($data["password"]);
var_dump ( insert_to_db("user", $data, true) );
And I see on the screen
array(3) {
["error"]=> string(4) "true"
["error_stmt"]=> string(53) "No data supplied for parameters in prepared statement" ["MORE"]=> string(178) "..."
}
Why am I getting this? What is the problem?
Also, If I pass the value instead of ? to the mysql::prepare, it works! So - it means that the problem is with mysqli stmt bind_param..
I know that this question similar to others, but I didn't found one that helps my problem. and sorry for my english and for the long function. thank you!

Answer 1

I've moved to PDO, and instead of calling $stmt->bind_param($b_p_f, $values); you can call $pdo_stmt->execute($values) where $values is an Array.