Php search query with range filter - php

Question

I am trying to do a search query, but not sure how to put everything together. I am having problem with the range filter part.
What i am trying to achieve:
A search form that
1.) If field A,B(not empty) then put in the search query
2.) search through price column with (price lower range, price higher range)
include the results if it matches Field A,B(if it is not empty) and price(if it is in range).
(if search Fields A, B are empty then display all results that exist between range).
Thanks for your time.
The codes that i have now.
<?php
ini_set('display_errors', 1); error_reporting(E_ALL);
session_start();
include 'connect.php';
if($_POST)
{
$A = ($_POST['A']);
$B = ($_POST['B']);
$C = ($_POST['C']);
$pricelow = ($_POST['pricelow']);
$pricehigh = ($_POST['pricehigh']);
$sql = array();
if (!empty($A)) {
$sql[] = "A='$A'";
}
if (!empty($B)) {
$sql[] = "B='$B'";
}
if (!empty($C)) {
$sql[] = "C='$C'";
}
if (!empty($price)) {
for($i = pricelow; $i<pricehigh; $i++){
$price = $i;
}
$sql[] = "price='$price'";
$sql = implode(' AND ', $sql);
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . $sql: '');
$result = mysqli_query($con,$sql);
$output = array();
// fetch your results
while( $row = mysqli_fetch_assoc($result) )
{
// add result row to your output's next index
$output[] = $row;
}
// echo the json encoded object
echo json_encode( $output );
}
?>
Edit:
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . $sql: '') . ("AND" 'price' BETWEEN "$pricelow" AND "$pricehigh");
Edit:
if (!empty($pricelow) || !empty($pricehigh)) {
$sql[] = $pricehigh>= 'price' and 'price'>=$pricelow ;
}
$sql = array();
$sql = implode(' AND ', $sql);
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . implode(" AND ", $sql): '');

Answer 1

<?php
ini_set('display_errors', 1); error_reporting(E_ALL);
session_start();
include 'connect.php';
if($_POST)
{
$A = ($_POST['A']);
$B = ($_POST['B']);
$C = ($_POST['C']);
$pricelow = ($_POST['pricelow']);
$pricehigh = ($_POST['pricehigh']);
$query = "SELECT * FROM Listing WHERE ";
$flag = 0;
if (!empty($A)) {
$query .= $flag==0?" A='$A' ":" AND A = '$A'";
$flag = 1;
}
if (!empty($B)) {
$query .= $flag==0?" B = '$B' ":" AND B = '$B'";
$flag = 1;
}
if (!empty($C)) {
$query .= $flag==0?" C='$C' ":" AND C= '$C'";
$flag = 1;
}
if ($flag == 0) {
$query .= " price > $pricelow AND price > $pricehigh"
}
$result = mysqli_query($con,$query);
$output = array();
// fetch your results
while( $row = mysqli_fetch_assoc($result) )
{
// add result row to your output's next index
$output[] = $row;
}
//your rest of the code
>?
I can't test it so, try and report the result!

Answer 2

You are creating an array of conditions and later you try to use that array as a string. This will not work, as the generated query is invalid. Take a look here, implode is a function which implodes an array using a separator. If you use " AND " as separator, then you will get the string you have desired. So, instead of:
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . $sql: '');
do the following:
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . implode(" AND ", $sql): '');
and your problem should be solved.
EDIT:
I have read your edit and I mean this code in particular:
if (!empty($pricelow) || !empty($pricehigh)) {
$sql[] = $pricehigh>= 'price' and 'price'>=$pricelow ;
}
$sql = array();
$sql = implode(' AND ', $sql);
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . implode(" AND ", $sql): '');
After you build your array you are initializing it again, thus you lose all information you have processed earlier. Then you implode it twice, which is not needed. Try this way:
if (!empty($pricelow) || !empty($pricehigh)) {
$sql[] = $pricehigh>= 'price' and 'price'>=$pricelow ;
}
$sql = "SELECT * FROM Listing" . (!empty($sql)? " WHERE " . implode(" AND ", $sql): '');