storing and appending array in file in php - php

I have an app_id and a current date. actually I want to update my database if the current date and the stored date is greater than 4.
I'm doing this:
$app_id = $_GET['ap'];
$current_date=date('d');
$a = array($app_id => $current_date);
$fp = fopen("time.txt",'r');
$last_run = unserialize(file_get_contents("time.txt"))[$app_id];
if(abs($last_run-$current_date) > 2)
{
$fp = fopen("time.txt", 'w');
fwrite($fp, serialize($a));
}
But the problem in this is when i switch the app it will again update the database because I'm using writing mode which is over writing the text file. I can use append mode. then how can i search in the array stored in the file and get that particular date corresponding that app_id and then append that date suitably.
Thanks in advance

You need to read the file and unserialize the whole array into a variable, then you can test and update any part of the array and then write the whole array back to your file.
Also file_get_contents() and file_put_contents() do not need you to open a file handle it does it all internally.
$app_id = $_GET['ap'];
$current_date = date('d');
$last_run = unserialize(file_get_contents("time.txt"));
if(abs($last_run[$app_id] - $current_date ) > 2 ) {
// change the last run date for this app
$last_run[$app_id] = $current_date;
file_put_contents('time.txt', serialize($last_run));
}
You really ought to be doing some checking in here as well.
That 'ap' is being passed to the script in the $_GET array
That the $last_run array actually contains a $app_id occurance

Related

Getting all from json api array using php

I wanna improve on how to fetch data from an API. In this case I want to fetch every app-id from the Steam API, and list them one per line in a .txt file. Do I need an infinite (or a very high-number) loop (with ++ after every iteration) to fetch everyone? I mean, counting up from id 0 with for example a foreach-loop? I'm thinking it will take ages and sounds very much like bad practice.
How do I get every appid {"appid:" n} from the response of http://api.steampowered.com/ISteamApps/GetAppList/v0001?
<?php
//API-URL
$url = "http://api.steampowered.com/ISteamApps/GetAppList/v0001";
//Fetch content and decode
$game_json = json_decode(curl_get_contents($url), true);
//Define file
$file = 'steam.txt';
//This is where I'm lost. One massive array {"app": []} with lots of {"appid": n}.
//I know how to get one specific targeted line, but how do I get them all?
$line = $game_json['applist']['apps']['app']['appid'][every single line, one at a time]
//Write to file, one id per line.
//Like:
//5
//7
//8
//and so on
file_put_contents($file, $line, FILE_APPEND);
?>
Any pointing just in the right direction will be MUCH appreciated. Thanks!
You don't need to worry about counters with foreach loops, they are designed to go through and work with each item in the object.
$file = "steam.txt";
$game_list = "";
$url = "http://api.steampowered.com/ISteamApps/GetAppList/v0001";
$game_json = file_get_contents($url);
$games = json_decode($game_json);
foreach($games->applist->apps->app as $game) {
// now $game is a single entry, e.g. {"appid":5,"name":"Dedicated server"}
$game_list .= "$game->appid\n";
}
file_put_contents($file, $game_list);
Now you have a text file with 28000 numbers in it. Congratulations?

php save image with specific file name not overwriting each other

I hope someone can help me with this php code.
At the moment its just saving an image with the file name "img.png" to the server but with every time a new canvas screenshot is taken the image is just overwritten.
My aim is to create a new unique (like numbered chronological by time taken) file name for the images with every new screenshot and save it on the server.
Here the php code so far:
$data = $_REQUEST['base64data'];
echo $data;
$image = explode('base64,',$data);
file_put_contents('img.png', base64_decode($image[1]));
Thank you.
regards
Try
$filename = 'img_'.date('Y-m-d-H-s').'.png';
file_put_contents($filename, base64_decode($image[1]));
This will save your file with a filename containing the current date and time, e.g.
img_2013-09-19-21-50.png
Try using a session variable to increment a counter like so:
<?php
session_start();
if(!isset($_SESSION['counter'])){
$_SESSION['counter'] = 0;
}
$_SESSION['counter']++;
$data = $_REQUEST['base64data'];
echo $data;
$image = explode('base64,',$data);
file_put_contents('img'.$_SESSION['counter'].'.png', base64_decode($image[1]));
?>
There's several ways to do it, but the easiest is just to add a timestamp/datestamp to the image name. Format the name as you want.
$img_name = 'img'.date('YmdHisu').'.png'; // Date & time with microseconds
$img_name = 'img'.time().'.png'; // unix timestamp
Leave the base64data structure use this one it will work fine.
$fileName = preg_replace('#[^a-z.0-9]#i', '', $fileName);
$image = explode(".", $fileName);
It will give a random number to each image file.
either create a UID using uniqid() function for the filename or create a folder with the name of the username who is uploading the file and leave the original filename. The disadvantage of the first one is that you will have to save the original filename somewhere to show to the user.
https://stackoverflow.com/a/4371988/2701758
**
/* simply for local time first give your continent then '/' then your country's
capital.
*/
date_default_timezone_set('Asia/Dhaka');
$now = new DateTime();
$now = $now->format("Y-m-d H:i:s.u");
$new_name = $now.$image;
/*what you want to add just write with dot,such
$new_name = 'img'.$now.$image;
*/
**

How to distinguish data from CSV files

I have two csv files, and both have same data structure.
ID - Join_date - Last_Login
I want to compare and get the exactly matching records numbers based on this example:
the first files has 100 records, of which 20 are not included in the 2nd file.
the 2nd file has 120 records.
I want a script in PHP to compare these two files and build two separate CSV files.
And I want to remove all extra records from the 2nd file which are not included in the first file.
And remove all records from the first file which are not included in the 2nd file.
Thanks
There is a GNU utility comm that will do this really easily. You could exec that through php or just do it directly. If you don't have access to comm, the easiest thing to do would be to store both files in an array (probably via file()) and use array_intersect().
You an try this for limited number of CSV file .. if you have a very large CSV i would advice you import it directly into MySQL
function csvToArray($csvFile, $full = false) {
$handle = fopen ( $csvFile, "r" );
$array = array ();
while ( ($data = fgetcsv ( $handle )) !== FALSE ) {
$array [] = ($full === true) ? $data : $data[0]; // Full array or only ID
}
return $array;
}
$file1 = "file1.csv" ;
$file2 = "file2.csv" ;
$fileData1 = csvToArray($file1);
$fileData2 = csvToArray($file2);
var_dump(array_diff($fileData1,$fileData2));
var_dump(array_intersect($fileData1,$fileData2));

Create Files Automatically using PHP script

I have a project that needs to create files using the fwrite in php. What I want to do is to make it generic, I want to make each file unique and dont overwrite on the others.
I am creating a project that will record the text from a php form and save it as html, so I want to output to have generated-file1.html and generated-file2.html, etc.. Thank you.
This will give you a count of the number of html files in a given directory
$filecount = count(glob("/Path/to/your/files/*.html"));
and then your new filename will be something like:
$generated_file_name = "generated-file".($filecount+1).".html";
and then fwrite using $generated_file_name
Although I've had to do a similar thing recently and used uniq instead. Like this:
$generated_file_name = md5(uniqid(mt_rand(), true)).".html";
I would suggest using the time as the first part of the filename (as that should then result in files being listed in chronological/alphabetic order, and then borrow from #TomcatExodus to improve the chances of the filename being unique (incase of two submissions being simultaneous).
<?php
$data = $_POST;
$md5 = md5( $data );
$time = time();
$filename_prefix = 'generated_file';
$filename_extn = 'htm';
$filename = $filename_prefix.'-'.$time.'-'.$md5.'.'.$filename_extn;
if( file_exists( $filename ) ){
# EXTREMELY UNLIKELY, unless two forms with the same content and at the same time are submitted
$filename = $filename_prefix.'-'.$time.'-'.$md5.'-'.uniqid().'.'.$filename_extn;
# IMPROBABLE that this will clash now...
}
if( file_exists( $filename ) ){
# Handle the Error Condition
}else{
file_put_contents( $filename , 'Whatever the File Content Should Be...' );
}
This would produce filenames like:
generated_file-1300080525-46ea0d5b246d2841744c26f72a86fc29.htm
generated_file-1300092315-5d350416626ab6bd2868aa84fe10f70c.htm
generated_file-1300109456-77eae508ae79df1ba5e2b2ada645e2ee.htm
If you want to make absolutely sure that you will not overwrite an existing file you could append a uniqid() to the filename. If you want it to be sequential you'll have to read existing files from your filesystem and calculate the next increment which can result in an IO overhead.
I'd go with the uniqid() method :)
If your implementation should result in unique form results every time (therefore unique files) you could hash form data into a filename, giving you unique paths, as well as the opportunity to quickly sort out duplicates;
// capture all posted form data into an array
// validate and sanitize as necessary
$data = $_POST;
// hash data for filename
$fname = md5(serialize($data));
$fpath = 'path/to/dir/' . $fname . '.html';
if(!file_exists($fpath)){
//write data to $fpath
}
Do something like this:
$i = 0;
while (file_exists("file-".$i.".html")) {
$i++;
}
$file = fopen("file-".$i.".html");

how to insert value in a particular location in csv file using php

Is it possible to write at a particular location in a CSV file using PHP?
I don't want to append data at the end of the CSV file. But I want to add data at the end of a row already having values in the CSV.
thanks in advance
No, it s not possible to insert new data in the middle of a file, due to filesystem nature.
Only append at the end is possible.
So, the only solution is to make another file, write a beginning part of source, append a new value, and then append the rest of the source file. And finally rename a resulting file to original name.
There you go. Complete working code:
<?php
//A helping function to insert data at any position in array.
function array_insert($array, $pos, $val)
{
$array2 = array_splice($array, $pos);
$array[] = $val;
$array = array_merge($array, $array2);
return $array;
}
//What and where you want to insert
$DataToInsert = '11,Shamit,Male';
$PositionToInsert = 3;
//Full path & Name of the CSV File
$FileName = 'data.csv';
//Read the file and get is as a array of lines.
$arrLines = file($FileName);
//Insert data into this array.
$Result = array_insert($arrLines, $PositionToInsert, $DataToInsert);
//Convert result array to string.
$ResultStr = implode("\n", $Result);
//Write to the file.
file_put_contents($FileName, $ResultStr);
?>
Technically Col. Shrapnel's answer is absolutely right.
Your problem is that you don't want to deal with all these file operations just to change some data. I agree with you. But you're looking for the solution in a wrong level. Put this problem in a higher level. Create a model that represents an entity in your CSV database. Modify the model's state and call its save() method. The method should be responsible to write your model's state in CSV format.
Still, you can use a CSV library that abstracts low level operations for you. For instance, parsecsv-for-php allows you to target a specific cell:
$csv = new parseCSV();
$csv->sort_by = 'id';
$csv->parse('data.csv');
# "4" is the value of the "id" column of the CSV row
$csv->data[4]['firstname'] = 'John';
$csv->save();

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