select query issue in mysql - php

I have a mysql table below
ID Name
1 AAA
2 BBB
3 CCC
Now I have a variable containing a random value of column Name.
$name = "BBB"; //Now this value can be changed that means it can be CCC or AAA
I want the output to be
ID Name
2 BBB
1 AAA
3 CCC
If the value is CCC then the output should be like below. The row containing the value should be at the top and then rest of the rows.
ID Name
3 CCC
1 AAA
2 BBB
And as usual I am stuck with the select query. The normal select query doesn't work as it selects only one item.
$sql = "select * from table where name='".$name."'";


You can combine ORDER BY with CASE.
Something like:
SELECT * FROM your_table
ORDER BY
CASE WHEN name=? THEN 0
ELSE 1
END
Note that I have replaced injecting your php variable directly with a prepared statement (the question mark, PDO or mysqli).
In mysql it would be something like:
CASE WHEN name="' . mysql_real_escape_string($name) . '" THEN 0


Maybe you could try something like this:
SELECT * FROM table WHERE name='".$name."'
UNION (SELECT * FROM table WHERE name!='".$name."')


Using the FIELD( ) function in the ORDER BY clause you can achieve this. It works by specifying the column to sort by and then the values to sort in order. For example:
SELECT * FROM tablename ORDER BY FIELD(Name, 'CCC') DESC;

Related

How to check value in column which has comma separated value in Mysql? [duplicate]

I have a field COLORS (varchar(50)) in a my table SHIRTS that contains a comma delimited string such as 1,2,5,12,15,. Each number representing the available colors.
When running the query select * from shirts where colors like '%1%' to get all the red shirts (color=1), I also get the shirts whose color is grey (=12) and orange (=15).
How should I rewrite the query so that is selects ONLY the color 1 and not all colors containing the number 1?

The classic way would be to add commas to the left and right:
select * from shirts where CONCAT(',', colors, ',') like '%,1,%'
But find_in_set also works:
select * from shirts where find_in_set('1',colors) <> 0

FIND_IN_SET is your friend in this case
select * from shirts where FIND_IN_SET(1,colors)

Take a look at the FIND_IN_SET function for MySQL.
SELECT *
FROM shirts
WHERE FIND_IN_SET('1',colors) > 0

This will work for sure, and I actually tried it out:
lwdba#localhost (DB test) :: DROP TABLE IF EXISTS shirts;
Query OK, 0 rows affected (0.08 sec)
lwdba#localhost (DB test) :: CREATE TABLE shirts
-> (<BR>
-> id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
-> ticketnumber INT,
-> colors VARCHAR(30)
-> );<BR>
Query OK, 0 rows affected (0.19 sec)
lwdba#localhost (DB test) :: INSERT INTO shirts (ticketnumber,colors) VALUES
-> (32423,'1,2,5,12,15'),
-> (32424,'1,5,12,15,30'),
-> (32425,'2,5,11,15,28'),
-> (32426,'1,2,7,12,15'),
-> (32427,'2,4,8,12,15');
Query OK, 5 rows affected (0.06 sec)
Records: 5 Duplicates: 0 Warnings: 0
lwdba#localhost (DB test) :: SELECT * FROM shirts WHERE LOCATE(CONCAT(',', 1 ,','),CONCAT(',',colors,',')) > 0;
+----+--------------+--------------+
| id | ticketnumber | colors |
+----+--------------+--------------+
| 1 | 32423 | 1,2,5,12,15 |
| 2 | 32424 | 1,5,12,15,30 |
| 4 | 32426 | 1,2,7,12,15 |
+----+--------------+--------------+
3 rows in set (0.00 sec)
Give it a Try !!!

If the set of colors is more or less fixed, the most efficient and also most readable way would be to use string constants in your app and then use MySQL's SET type with FIND_IN_SET('red',colors) in your queries. When using the SET type with FIND_IN_SET, MySQL uses one integer to store all values and uses binary "and" operation to check for presence of values which is way more efficient than scanning a comma-separated string.
In SET('red','blue','green'), 'red' would be stored internally as 1, 'blue' would be stored internally as 2 and 'green' would be stored internally as 4. The value 'red,blue' would be stored as 3 (1|2) and 'red,green' as 5 (1|4).

select * from shirts where find_in_set('1',colors) <> 0
Works for me

If you're using MySQL, there is a method REGEXP that you can use...
http://dev.mysql.com/doc/refman/5.1/en/regexp.html#operator_regexp
So then you would use:
SELECT * FROM `shirts` WHERE `colors` REGEXP '\b1\b'

You should actually fix your database schema so that you have three tables:
shirt: shirt_id, shirt_name
color: color_id, color_name
shirtcolor: shirt_id, color_id
Then if you want to find all of the shirts that are red, you'd do a query like:
SELECT *
FROM shirt, color
WHERE color.color_name = 'red'
AND shirt.shirt_id = shirtcolor.shirt_id
AND color.color_id = shirtcolor.color_id

You can achieve this by following function.
Run following query to create function.
DELIMITER ||
CREATE FUNCTION `TOTAL_OCCURANCE`(`commastring` TEXT, `findme` VARCHAR(255)) RETURNS int(11)
NO SQL
-- SANI: First param is for comma separated string and 2nd for string to find.
return ROUND (
(
LENGTH(commastring)
- LENGTH( REPLACE ( commastring, findme, "") )
) / LENGTH(findme)
);
And call this function like this
msyql> select TOTAL_OCCURANCE('A,B,C,A,D,X,B,AB', 'A');

1. For MySQL:
SELECT FIND_IN_SET(5, columnname) AS result
FROM table
2.For Postgres SQL :
SELECT *
FROM TABLENAME f
WHERE 'searchvalue' = ANY (string_to_array(COLUMNNAME, ','))
Example
select *
from customer f
where '11' = ANY (string_to_array(customerids, ','))

All the answers are not really correct, try this:
select * from shirts where 1 IN (colors);

I can not get expected output by like operator, where field store multiple integer value [duplicate]

I have a field COLORS (varchar(50)) in a my table SHIRTS that contains a comma delimited string such as 1,2,5,12,15,. Each number representing the available colors.
When running the query select * from shirts where colors like '%1%' to get all the red shirts (color=1), I also get the shirts whose color is grey (=12) and orange (=15).
How should I rewrite the query so that is selects ONLY the color 1 and not all colors containing the number 1?

The classic way would be to add commas to the left and right:
select * from shirts where CONCAT(',', colors, ',') like '%,1,%'
But find_in_set also works:
select * from shirts where find_in_set('1',colors) <> 0

FIND_IN_SET is your friend in this case
select * from shirts where FIND_IN_SET(1,colors)

Take a look at the FIND_IN_SET function for MySQL.
SELECT *
FROM shirts
WHERE FIND_IN_SET('1',colors) > 0

This will work for sure, and I actually tried it out:
lwdba#localhost (DB test) :: DROP TABLE IF EXISTS shirts;
Query OK, 0 rows affected (0.08 sec)
lwdba#localhost (DB test) :: CREATE TABLE shirts
-> (<BR>
-> id INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
-> ticketnumber INT,
-> colors VARCHAR(30)
-> );<BR>
Query OK, 0 rows affected (0.19 sec)
lwdba#localhost (DB test) :: INSERT INTO shirts (ticketnumber,colors) VALUES
-> (32423,'1,2,5,12,15'),
-> (32424,'1,5,12,15,30'),
-> (32425,'2,5,11,15,28'),
-> (32426,'1,2,7,12,15'),
-> (32427,'2,4,8,12,15');
Query OK, 5 rows affected (0.06 sec)
Records: 5 Duplicates: 0 Warnings: 0
lwdba#localhost (DB test) :: SELECT * FROM shirts WHERE LOCATE(CONCAT(',', 1 ,','),CONCAT(',',colors,',')) > 0;
+----+--------------+--------------+
| id | ticketnumber | colors |
+----+--------------+--------------+
| 1 | 32423 | 1,2,5,12,15 |
| 2 | 32424 | 1,5,12,15,30 |
| 4 | 32426 | 1,2,7,12,15 |
+----+--------------+--------------+
3 rows in set (0.00 sec)
Give it a Try !!!

If the set of colors is more or less fixed, the most efficient and also most readable way would be to use string constants in your app and then use MySQL's SET type with FIND_IN_SET('red',colors) in your queries. When using the SET type with FIND_IN_SET, MySQL uses one integer to store all values and uses binary "and" operation to check for presence of values which is way more efficient than scanning a comma-separated string.
In SET('red','blue','green'), 'red' would be stored internally as 1, 'blue' would be stored internally as 2 and 'green' would be stored internally as 4. The value 'red,blue' would be stored as 3 (1|2) and 'red,green' as 5 (1|4).

select * from shirts where find_in_set('1',colors) <> 0
Works for me

If you're using MySQL, there is a method REGEXP that you can use...
http://dev.mysql.com/doc/refman/5.1/en/regexp.html#operator_regexp
So then you would use:
SELECT * FROM `shirts` WHERE `colors` REGEXP '\b1\b'

You should actually fix your database schema so that you have three tables:
shirt: shirt_id, shirt_name
color: color_id, color_name
shirtcolor: shirt_id, color_id
Then if you want to find all of the shirts that are red, you'd do a query like:
SELECT *
FROM shirt, color
WHERE color.color_name = 'red'
AND shirt.shirt_id = shirtcolor.shirt_id
AND color.color_id = shirtcolor.color_id

You can achieve this by following function.
Run following query to create function.
DELIMITER ||
CREATE FUNCTION `TOTAL_OCCURANCE`(`commastring` TEXT, `findme` VARCHAR(255)) RETURNS int(11)
NO SQL
-- SANI: First param is for comma separated string and 2nd for string to find.
return ROUND (
(
LENGTH(commastring)
- LENGTH( REPLACE ( commastring, findme, "") )
) / LENGTH(findme)
);
And call this function like this
msyql> select TOTAL_OCCURANCE('A,B,C,A,D,X,B,AB', 'A');

1. For MySQL:
SELECT FIND_IN_SET(5, columnname) AS result
FROM table
2.For Postgres SQL :
SELECT *
FROM TABLENAME f
WHERE 'searchvalue' = ANY (string_to_array(COLUMNNAME, ','))
Example
select *
from customer f
where '11' = ANY (string_to_array(customerids, ','))

All the answers are not really correct, try this:
select * from shirts where 1 IN (colors);

How to get the next row in sql

I have a table that is something like this
id | names | value
1 Vicky 43
2 Erica 23
3 Rueben 33
4 Bob 54
5 Chris 60
Then I set them in order according to their value. Now the table looks like this.
id | names | value
5 Chris 60
4 Bob 54
1 Vicky 43
3 Rueben 33
2 Erica 23
Now the starting point is id 5 which has a name of Chris and a value of 60. My goal is, to get the next row which has an id of 4 and name of Bob and a value of 54.

You just need to limit the resultset:
SELECT * from table
ORDER BY value DESC
LIMIT 1, 1
Output:
| ID | NAMES | VALUE |
|----|-------|-------|
| 4 | Bob | 54 |
Fiddle here.
The LIMIT basically works this way: the first number sets the starting point (being 0 the minimal value) and the second number the amount of items to fetch (in this case only one).
Edit:
A different way of understanding the question would be: Given a value for a particular field (EG: id field with value of 5)... what would be the previous record? As we have the id 4 in the data we should return that one.
That could be accomplished this way:
SELECT * from t
WHERE id < 5
ORDER BY id DESC
LIMIT 1
Fiddle here.
This way you can traverse the results in both orders (ASC and DESC) and also get both the next or previous (> or <) rows.

If your current ID is for example 4 then
Next:
select * from foo where id = (select min(id) from foo where id > 4)
previous:
select * from foo where id = (select max(id) from foo where id < 4)

sql server:
with temp as
(
SELECT ROW_NUMBER() OVER (ORDER BY value desc) AS ROWID, * FROM table_name
)
SELECT * from temp where ROWID=2
mysql:
SELECT * from table
ORDER BY value DESC
LIMIT 1, 1

I get the feeling that this is a PHP related question?
If that's so, then you can use PHP's mysql or mysqli_fetch functions to get what you want... along with a loop
This is your basic loop-through-a-mysql-query
$sql = mysql_query( "SELECT * from table ORDER BY value DESC" );
while ( $r = mysql_fetch_array( $sql ) ) {
echo $r['value'] . "<br />\n";
}
If you want to have them all at your disposal and be able to call either one of them at will, you will need to store the data in an accessible array, like so
$sql = mysql_query( "SELECT * from table ORDER BY value DESC" );
$theData = array();
while ( $r = mysql_fetch_array( $sql ) ) {
$theData[] = $r['value'];
}
Then, to access the SECOND value, use this
echo $theData[1];

How to sort mysql result but show specific result first

I have table like this one
id name
1 John
2 Mike
3 Zed
4 Teacher
5 Aaron
...........
How to make mysql query to get rows in ASC order by name but put "Teacher" at the top or something that starts with "Teacher"?

select * from your_table
order by case when name = 'Teacher' then 1 else 2 end,
name
and for MySQL the following works since it returns 0 for false and 1 for true
select * from your_table
order by name <> 'Teacher',
name

Use FIELD function
SELECT * FROM table ORDER BY FIELD(`name`,'Teacher') ASC

select * from table order by case when name like "Teacher%" then 1 else 2 end,name
Names starting with Teacher will be on top sorted alphabetically, then the rest.
Example
Teacher
Teacher Aaron
Teacher Zed
Aaron
Zed

MYSQL returning duplicate rows

I have a Database table in MYSQL, it looks like this:
Project_ID user_ID name
11 1 fred
11 2 rick
11 1 fred
I want to get the names in the table, but when I display it I get the same name twice because the user_ID 1 appears twice in the table. I tried to display it with GROUP BY and SUM, but I don't want to do it this way. How do I get it not to return duplicate rows?

Use DISTINCT
SELECT DISTINCT user_ID
, verschil_ma
FROM project_uren
WHERE project_ID = 11
GROUP BY user_ID

Point 1 is that should the user be assigned to the project twice?
Point 2 - Use the DISTINCT keyword to return only unique records - http://dev.mysql.com/doc/refman/5.0/en/distinct-optimization.html
SELECT DISTINCT user_ID
FROM TABLE
WHERE Project_id = 11
That will return you 1 and 2 (You won't get 1 twice)
Thanks

$results = // query
$results = array_unique($results);

Categories