Suppose my Form codes look like this
URL : localhost/my-url.php
<form action="hello.php">
...bla bla bla
</form>
I will process the data in hello.php and i want to redirect to user to same url after processing (according to above example)
localhost/my-url.php
I know we can use header but i don't know how to get that url from which form was submited :(
Googled but didn't found any use full.
Thanks.
Add a hidden value in your form:
<input type="hidden" name="lastUrl" value="<?php echo $_SERVER['REQUEST_URI'] ?>" />
You now have the URL in $_POST['lastUrl'] data. You need to do it that complicated because $_SERVER["HTTP_REFERER"]; is send by the browser, and not all of them do this reliable.
You should put a hidden field in your form and set its value to current page url.
Then you submit the form and get the value of hidden field.
Then you can redirect user to hidden field (which is actually a URL of the page where you are submitting form) by using javascript or php.
You can use the
$_SERVER["HTTP_REFERER"];
to get the original URL where the form was posted from.
Remember to escape it, if you use it however. ]
Alternatively, you can process the form using AJAX, send process things (redirection) client-side.
Note that form data can be changed and intercepted if you wish to send the URL of the page as form data.
Related
I am writing PHP code for my hosting web page.
I create a search domain filled on page with $_GET to check if domain was available. I need to protect my $GET function in code.
The $GET code to process searching of a domain:
if(isset($_GET['search'])){
$domena = ($_GET['search']);
}
HTML CODE
I have a submit button with FORM POST ACTION and I get the URL:
www.domain.com/index.php?search=domain.com
I need know if I can hide the URL search=domain.com
Note - I don't want to use AJAX or other language, just PHP.
If you want to hide search parameter, then send it by POST method and accept it by $_POST instead of $_GET.
if(isset($_POST['search'])){
$domena = ($_POST['search']);
}
Have you thought about using the $_POST method? The data sent from the user will be in the HTTP request and not in the url. The $_GET method would be posted in the url.
Mozilla does a good job explaining this.
Make sure to specify method $_POST in your form. For example:
<form action="http://foo.com" method="post">
<input name="say" value="Hi">
<input name="to" value="Mom">
<button>Send my greetings</button>
</form>
Then to retrieve your data, use the same code you posted in your question but change $_GET to $_POST
So I have a form that requires a user to submit their website to a form. Here is the html line:
<input type='url' name='link'>
And I'm using <input type="submit" value="submit" formmethod="post"> to submit the form to a php
And I'm trying to retrieve the values in my php file with:
$link = $_POST['link'];
Why isn't this working? At first I thought it was because I had htmlspecialchars() but it's not coming through without it either. I can't find anything in any google search that even mentions anything related to this kind of problem (with a type="url" form)
What do I need to do to process form data with type of "url" in PHP with a $_POST?
Get your form method to be set to post e.g
<form method=post>,
if you submit the form and in the url in your browser u can see some more inf then be sure 2 check your form method
I think this is wrong,
method="post"
Its only method, not formmethod
Also make sure, you dont have one more for element name with link.
I have html page and I have taken one form in it and other link outside the form .Form is Submitted by POST method,when I submitting form first time its ok and when I click link it pass data by GET method and when I again submit form then it send both GET and POST variable i.e form data and link data both.so what is the reason for that and how can I solve it.My html page is below
<html>
<body>
<form method='post'>
<input type=input name='name'/>
<input type=submit name='submit' value='submit'/>
</form>
<a href='check_global.php?page_number=6'>Page Number</a>
</body>
</html>
Because the form hasn't the action attribute, so it simply reload the page. When you submit it the first time it's all fine, but when you do it after clicking the link, the url is 'dirty' due to the data of the link, so you have both GET and POST values.
You can check wether the POST attribute is set ( if(isset($_POST['name'])) with php), in this case it has been submitted with the form
When you submit the form the second time you see the form parameters + the url parameter of the page (remember you clicked the link with the relative URL 'check_global.php?page_number=6').
To verify the above try this:
<?php
echo 'GET param ' . $_GET["page_number"];
echo 'POST param ' . $_POST["name"];
?>
As you can see you can access both types of parameters during a POST request.
Hope that helps.
Just to make the point, the OP did not indicate that the form was supposed to submit to anywhere but the current page. So just for funsies, here is the same basic idea, but with an action attribute value:
<form method="post" action="">
<input type="text" name="name"/>
<input type="submit" name="submit" value="submit"/>
</form>
Page Number
Notice that I've set it up so that, for whatever reason, the link points back to this same page and so does the form. The result:
First Load: form submit makes request with POST data to blah.php
Second Load: link follow makes request with GET (thanks to the query string) to blah.php?page_number=6
Third Load: form submit, using blank action to indicate that current page is where to post, makes request with POST form data to blah.php?page_number=6, thus having both POST form data and GET URL data.
So your options are to either set the action attribute value to blah.php so that it does not include the query string, or to accept that if you want to avoid the various ways of doing this in favor of having a more modular form (drop it in any page and you know it will post to that address), then to simply have the PHP backend check if $_POST['submit'] is set and if so, handle it like a form post and don't use any of the $_GET logic that might be screwing things up.
The link is never sending the form data as POST, and the POST data is not part of the GET array, so you know that when there is no POST, it's just get and if there is POST, it was a form submit, even if there is a GET array.
Or just use separate scripts so you don't get mixed up.
I have a https page named user.php that gets data and posts it to another receiving.php https page. My problems is whenever I submit my data for posting the receiving.php displays server error. I have read articles about cURL but I don't have a clear picture of the syntax.
user.php
<form action="https://www.mydomain.com/ssl/receiving.php">
<input type="text" name="variable" />
<input type="submit" name="buttonName" />
</form>
receving.php
if(isset($_POST["buttonName"]))
{
$variable=$_POST['variable'];
}
You want to add method="POST" to your form tag. By default it'll submit through GET. If that doesn't work, try var_dump($_POST) in receiving.php to see exactly what's coming through. cURL is mainly for when you want a script to make a request to a server on its own. A form submit shouldn't need to worry about cURL.
What error are you receiving though? This shouldn't display an error as your isset() should just return false.
you need to use the $_GET method instead of $_POST because $_GET is a method that displays your request in the form in URL. while $_POST for security reason is just getting data from the form and not displaying the actions you've requested.
<form action="https://www.mydomain.com/ssl/receiving.php">
if you want to use $_POST you need to make your form method set to method="POST" or by default your method form is using "GET".
So you instead of using $_POST , you need to use $_GET in your case.
I have a <form> with an action attribute.
I would like to change the value of action based on the value of an <input>.
The value is provided by the user. If the value is page1.php, the form will be submitted to page1.php. If the value is page2.php, the form will be submitted to page2.php, and so on.
Right now I'm achieving this using JavaScript, however it doesn't work on a browser with JavaScript disabled.
Is there any way to make the action non-static without JavaScript?
You can do this without invoking any javascript at all.
PHP example;
<?php
/*if no destination was set previously the form will post back to itself*/
$action=isset($_Request['destination'])?$_Request['destination']:'';
?>
<form name='a-form-name' action="<?php echo $action;?>">
/*include other inputs etc as required.
Include a 'destination' input in _all_ forms involved.
You can of course name it whatever you like. But should always be the same name in all forms involved.
*/
<input type='hidden' name='destination' value='the-desired-destination-of-next-action'>
<input type='submit' name='whatever' value='Click here'>
</form>
When you press the submit button it will go to whatever destination you set in the previous submission or 'destination' in the url query string.
You can even make the destination hidden input's value dynamic by using a variable instead if need be. Branching can be quite easy and extensive using this method.
HTH
If you just want to receive the value on the server side, than using get as the form's method will work (you end up with page.php?my_var_name=my_var_value).
If, however, you want to direct the form to a completely different page based on the value of your input, you'll either have to use JS, or have a "catchall" page on the server side that gets the form and redirects to the final page based on the value.