I'm trying to insert in res.users with this code:
$values= array(
"name"=>new xmlrpcval($name,"string"),
"login"=>new xmlrpcval($login,"string"),
"password"=>new xmlrpcval($psw,"string"),
"lang"=>new xmlrpcval("it_IT","string"),
"company_id"= new xmlrpcval($company,"many2one");
);
echo $id= $this->create($values,"res.users");
I'm using a user with all the possible privileges.
The function returns a -1 state that means that I've no permission or the format is not corrected.
It works if I remove the company_id field.
try this,
Many2one is store int id of record created. So in company_id pass int in format.
$values= array(
"name"=>new xmlrpcval($name,"string"),
"login"=>new xmlrpcval($login,"string"),
"password"=>new xmlrpcval($psw,"string"),
"lang"=>new xmlrpcval("it_IT","string"),
"company_id"= new xmlrpcval($company,"int");
);
echo $id= $this->create($values,"res.users");
Related
I am creating a script for PrestaShop 1.6 that inserts data into a table.
My table is made in this way:
id: int AUTO INCREMENT
desc: string
As I enter a description I would get back the ID value.
On can not use the standard because it blocked by PrestaShop.
I find this a situation:
$sql = "INSERT INTO `"._DB_PREFIX_."table`(`desc`) VALUES ('".$this->desc."')";
$restpo = Db::getInstance()->execute($sql);
var_dump($restpo);
But I have an answer only a boolean.
Can you suggest something?
You can use the:
$id = (int)Db::getInstance()->Insert_ID();
For example, in the Cart class:
$last_id = (int)Db::getInstance()->Insert_ID();
I also recommend the use of the function insert, for example in the Carrier class:
$values = array();
foreach ($shops as $id_shop) {
$values[] = array(
'id_carrier' => (int)$this->id,
'id_tax_rules_group' => (int)$id_tax_rules_group,
'id_shop' => (int)$id_shop,
);
}
$res = Db::getInstance()->insert('carrier_tax_rules_group_shop', $values);
Then use the Insert_ID to get the last one.
Use $id = Db::getInstance()->Insert_ID(); after executing your SQL.
PrestaShop's DB class provides the last inserted id via
Db::getInstance()->Insert_ID();
method.
i have a code like this ,
$request = Yii::$app->request;
$post = $request->post();
$filesettingid = $post['filesettingid'];
$checkboxValue = $post['selection'];
for($i=0;$i<sizeof($checkboxValue);$i++) {
$store = Yii::$app->db->createCommand('SELECT id FROM store WHERE port='.$checkboxValue[$i])->queryAll();
$storeid = $store[$i]['id'];
Yii::$app->db->createCommand()->insert('tes',
[
'id' => $i+1,
'filesetting_id' => $filesettingid,
'store_id' => $storeid
])->execute();
}
what i want is, each i insert the new data, id will generate automaticly like 1,2,3,4.
the problem in above code is, the ID always be 1.
is it possible to make it real?
so what i want is :
First time insert, id = 1, second is id = 2 , and that is happen automatically.
Have you considered setting database engine to auto increment values with each insert?
Take as an example Yii2 default user table. ID filed is auto incremented, and you don't have to worry about setting it problematically. Every time you send a new insert engine increments ID filed by itself.
See default migration under "advanced template"\console\migrations\m130524_201442_int. (your file name might be different depending on the Yii2 version)
$this->createTable('{{%user}}', [
'id' => $this->primaryKey(),
'username' => $this->string()->notNull()->unique(),
'auth_key' => $this->string(32)->notNull(),
'password_hash' => $this->string()->notNull(),
'password_reset_token' => $this->string()->unique(),
'email' => $this->string()->notNull()->unique(),
'status' => $this->smallInteger()->notNull()->defaultValue(0),
.........
], $tableOptions);
When setting 'id' to primary key database automatically knows to auto increment it. If you already have a table the ID field is not primary key you can use the followign migration:
$this->alterColumn('{{%databaseName}}', 'columnName', $this->integer()->notNull().' AUTO_INCREMENT');
You can also set it from management console, or run a SQL query. Depending on database engine you are using this might look a little different but the concept is the same.
MYSQL:
In MySQL workbench right click on table in question, select Alter Table and check NNm and AI next to column you want auto increment. See Screenshot
Or run command:
ALTER TABLE `dbName`.`nameOfTheTable` MODIFY `columnName` INT AUTO_INCREMENT NOT NULL;
I am a bit rusty on my SQL, so if it does not work let me know I will get you right command.
Hope this helps. Good luck.
this is my code for updating:
PS: empid is a foreign key but i think that shouldnt be the reason and the code is in CakePHP
if($this->request->is('post'))
{
$this->request->data["Leave"]["empid"] = $this->request->data["id"];
$this->Leave->empid = $this->request->data["Leave"]["empid"];
$this->request->data["Leave"]["leave_start"] = $this->request->data["start_date"];
$this->request->data["Leave"]["leave_end"] = $this->request->data["end_date"];
$this->request->data["Leave"]["leave_taken"] = $this->request->data["leave_taken"];
if($this->Leave->save($this->request->data['Leave']))
{
return $this->redirect(array('action' => 'manage_leave'));
}
}
// This code is inserting a new row instead of updating and also not adding any value in the new row
May be your trying to update the foreign table data using simple save.
Update multiple records for foreign key
Model::updateAll(array $fields, mixed $conditions)
Example
$this->Ticket->updateAll(
array('Ticket.status' => "'closed'"),
array('Ticket.customer_id' => 453)
);
Simple save for the primary key
Make sure that your HTML has empid
echo $this->Form->input('Leave.empid', array('type' => 'hidden'));
Save Model
$this->Leave->empid = $this->request->data["Leave"]["empid"]; //2
$this->Leave->save($this->request->data);
In between, you can also try to set the model data and check the $this->Leave->validates() and $this->Leave->validationError if they are giving any validation errors.
// Create: id isn't set or is null
$this->Recipe->create();
$this->Recipe->save($this->request->data);
// Update: id is set to a numerical value
$this->Recipe->id = 2;
$this->Recipe->save($this->request->data);
You can find more information about all Saving your data
Hope this helps you :)
And in case if $empid is primary key of corresponding table of Leave model (e.g leaves), Just replace:
$this->Leave->empid = $this->request->data["Leave"]["empid"];
By
$this->Leave->id = $this->request->data["Leave"]["empid"];
I have this function to update a record, but i cannot it fails and send me a "Primary key ID missing from row or is null" message, how can I fix it?
public static function update_child($data)
{
try
{
$update= ORM::for_table("dm_child",DM_TAG)
->where_equal($data["id_child"]);
$update -> set(array(
"gender" => $data["gender"]
"age_year" =>$data["year"]
"age_month" => $data["month"]
));
$update -> save();
}
catch(PDOException $ex)
{
ORM::get_db()->rollBack();
throw $ex;
}
}
Idiorm assumes that the name of the primary key is 'id', which is not that, in your case.
Therefore you have to explicitly specify it to Idiorm:
<?php
ORM::configure('id_column_overrides', array(
'dm_child' => 'id_child',
'other_table' => 'id_table',
));
See Docs>Configuration.
The answer is indeed the one provided by #iNpwd for changing the default 'id' column name for queries on a per table basis:
ORM::configure('id_column_overrides', array(
'table_name' => 'column_name_used_as_id',
'other_table' => array('pk_1', 'pk_2') // a compound primary key
));
The thing that was biting me on getting it to recognize my query was WHERE I was changing the ORM::configure values. I was not in the correct file.
A deeper link to specifically the ID Column configuration: http://idiorm.readthedocs.org/en/latest/configuration.html#id-column
I just met this problem 2 minutes ago. The real reason is, you forgot select id field in querying.
demo:
$demo = ORM::for_table('demo')->select('field_test')->find_one($id);
$demo->field_test = 'do';
$demo->save();
You will get the error.
change to :
$demo = ORM::for_table('demo')->select('field_test')->select('id')->find_one($id);
It will fix the problem.
Some tips in documents:
https://github.com/j4mie/idiorm/blob/master/test/ORMTest.php
/**
* These next two tests are needed because if you have select()ed some fields,
* but not the primary key, then the primary key is not available for the
* update/delete query - see issue #203.
* We need to change the primary key here to something other than id
* becuase MockPDOStatement->fetch() always returns an id.
*/
I've never used idiorm, so cannot guarantee that my answer will work for you, but from this page and under "Updating records", we have an example which is similar but slightly different to yours.
// The 5 means the value of 5 in the primary-key column
$person = ORM::for_table('person')->find_one(5);
// The following two forms are equivalent
$person->set('name', 'Bob Smith');
$person->age = 20;
// This is equivalent to the above two assignments
$person->set(array(
'name' => 'Bob Smith',
'age' => 20
));
// Syncronise the object with the database
$person->save();
I'm sure I'll learn the reason behind this, but let me tell you all I understand at the moment, and how I "fixed" it.
Here is the beginning of idiorm's save function:
public function save() {
$query = array();
// remove any expression fields as they are already baked into the query
$values = array_values(array_diff_key($this->_dirty_fields, $this->_expr_fields));
if (!$this->_is_new) { // UPDATE
// If there are no dirty values, do nothing
if (empty($values) && empty($this->_expr_fields)) {
return true;
}
$query = $this->_build_update();
$id = $this->id(true);
Right there, on that last line, when trying to access the $this->id, you are getting an exception thrown:
throw new Exception('Primary key ID missing from row or is null');
$this does not contain an id property. I'm not really sure how it could. The example given both on their homepage and in the docs doesn't do anything special to address this. In fact I am copying them 1:1 and still yielding the same error as you.
So, all that said, I fixed this error by just adding in my own id:
$crop = ORM::for_table('SCS_Crop')->find_one($id);
$crop->id = $id;
$crop->Name = "Foo";
$crop->save();
This also happens when the id field name is ambiguous, e.g. when joining two tables both having an id column. This is the case with referenced tables
Model::factory('tableOne')
->left_outer_join('tableTwo', array('tableOne.tableTwo_id', '=', 'tableTwo.id'))
->find_one($id);
In these cases set an alias to the ID column of the parent tableOne to later access it while saving. Make sure that you also select other columns you need - e.g. by ->select('*'):
Model::factory('tableOne')
->select('*')
->select('tableOne.id', 'id')
->left_outer_join('tableTwo', array('tableOne.tableTwo_id', '=', 'tableTwo.id'))
->find_one($id);
if in table primary key/ field name not id then following id column overrides required
default id (primary_key) to replace with other id name (primary_key)
ORM::configure('id_column_overrides', array(
'user' => 'user_id',
));
$update = ORM::for_table('user')->find_one(1);
$update->name = "dev";
try{
$update->save();
}catch(Exception $e){
echo $e;
}
print_r($update);
I would like to insert an array into a MYSQL database, preferably using Yii's active record.
For example, I have a an array:
User = array(
fname => "Joe"
lname => "Schmidt"
)
with a User table in my database with columns id, fname and lname. One of the options is creating an object and doing:
$user = new User;
$user->fname = User['fname'];
$user->lname = User['lname'];
$user->save();
However, this seems like so much code for such common functionality. Is there a way to insert an array into the database where array keys match corresponding columns without me writing my own function or doing some SQL query hack? Ideally it uses the already present Active record of Yii.
What you want to do is handled by the framework itself.
You can mass assign like:
$user->attributes=$_POST['User'];
Read more about Mass Assignment
I have never worked with Yii before, so I can't offer a solution using that, but you can serialize the array and store it in the single cell in your database, like so:
$user = array("fname" => "Joe", "lname" => "Schmidt");
$serialized = serialize($user);
//Store the $serialized variable in the database
When you are ready to access it:
//Get your data from the database
$unserialized = unserialize($usersFromDB);
$fname = $unserialized['fname']; //Joe
Hope that helps.
the function is pretty straightforward, try this:
function insert($table, $fields_values = array())
{
$q1 = join(",", array_keys($fields_values));
$q2 = "'".join("','", array_values($fields_values))."'";
$query = "INSERT INTO $table($q1) VALUES($q2)";
// do your DB insert here
}
The main trick is the array to query conversion using join and array_keys / array_values.
Depending the amount of data in array you can write you own function e.g
a) check this backUpdate , modify it to insert /remove render view option
b) Follow this thread
c) Possible traps when inserting multiple records
d) check this associated SOQ
If you know what you are doing its easy to do , you just need to take care of
validations
records exists in associated tables ( if there is FKey involved )
option d). will be a posssible answer if you have simple inserts ( with no associated tables)