I will provide a example
i want the directory list to be written to a file
so i did this
<?php
$command="dir";
exec($command,$output);
//i want the directory list to be written to a file
// so i did this
$fp=fopen("file.txt","w");
fwrite($fp, $output);
//its actually writing the 0(return value for exec is int) to the file
// but i want the list of directories to be written to file
?>
its actually writing the 0(return value for exec is int) to the file
but i want the list of directories to be written to file
Please tell me a way to do that
You can simply use shell_exec:
<?php
$output = shell_exec('dir');
$fp=fopen("file.txt","w");
fwrite($fp, $output);
?>
i think that for your needle you should use the command "passthru".
Here an example:
<?php
$command = exec('dir', $outpout);
$data = "";
foreach($output AS $key=>$val){
$data .= $val . "\n";
}
$fp = fopen('file.txt', 'w') or die("i cant write...permission ?");
fwrite($fp, $data);
fclose($fp);
?>
Let me know if it works
Have a nice day
Antonio
P.S. Thanks Kevin
You can do it directly in the exec call (it's shorter) :
exec("dir > file.txt")
Anyway, your code is wrong because $output is an array.
Fixed code :
$command="dir";
exec($command,$output);
$fp=fopen("file.txt","w");
fwrite($fp, join("\n",$output))
And a shorter code :
exec("dir",$output);
file_get_contents("file.txt",join("\n",$output));
Related
I'm trying to make a download counter in a website for a video game in PHP, but for some reason, instead of incrementing the contents of the downloadcount.txt file by 1, it takes the number, increments it, and appends it to the end of the file. How could I just make it replace the file contents instead of appending it?
Here's the source:
<?php
ob_start();
$newURL = 'versions/v1.0.0aplha/Dungeon1UP.zip';
//header('Location: '.$newURL);
//increment download counter
$file = fopen("downloadcount.txt", "w+") or die("Unable to open file!");
$content = fread($file,filesize("downloadcount.txt"));
echo $content;
$output = (int) $content + 1;
//$output = 'test';
fwrite($file, $output);
fclose($file);
ob_end_flush();
?>
The number in the file is supposed to increase by one every time, but instead, it gives me numbers like this: 101110121011101310111012101110149.2233720368548E+189.2233720368548E+189.2233720368548E+18
As correctly pointed out in one of the comments, for your specific case you can use fseek ( $file, 0 ) right before writing, such as:
fseek ( $file, 0 );
fwrite($file, $output);
Or even simpler you can rewind($file) before writing, this will ensure that the next write happens at byte 0 - ie the start of the file.
The reason why the file gets appended it is because you're opening the file in append and truncate mode, that is "w+". You have to open it in readwrite mode in case you do not want to reset the contents, just "r+" on your fopen, such as:
fopen("downloadcount.txt", "r+")
Just make sure the file exists before writing!
Please see fopen modes here:
https://www.php.net/manual/en/function.fopen.php
And working code here:
https://bpaste.net/show/iasj
It will be much simpler to use file_get_contents/file_put_contents:
// update with more precise path to file:
$content = file_get_contents(__DIR__ . "/downloadcount.txt");
echo $content;
$output = (int) $content + 1;
// by default `file_put_contents` overwrites file content
file_put_contents(__DIR__ . "/downloadcount.txt", $output);
That appending should just be a typecasting problem, but I would not encourage you to handle counts the file way. In order to count the number of downloads for a file, it's better to make a database update of a row using transactions to handle concurrency properly, as doing it the file way could compromise accuracy.
You can get the content, check if the file has data. If not initialise to 0 and then just replace the content.
$fileContent = file_get_contents("downloadcount.txt");
$content = (!empty($fileContent) ? $fileContent : 0);
$content++;
file_put_contents('downloadcount.txt', $content);
Check $str or directly content inside the file
I have a huge txt file that have 475254 lines and with php I want to read the first line of the my txt file and save it into the Variable and then when I save it the php delete that line.
my txt file is about 2.3 MB is it possible to do this?
yes it is /.................................
OK less trolling..
You want fopen and fgets will grab a line. REF : fgets Manual PHP
$file = "file.txt"
$f = fopen($file, 'r');
$line = fgets($f);
fclose($f); // You close because you only want the first one.
There are so many examples how to do this i feel embarrassed answering. You should show some of what you have tried first!
Now you want to remove it: use file_get_contents REF : PHP file_get_contents
//Get your file contents
$newDoc = file_get_contents($file, true);
$newFileContents = substr( $line, strpos($newDoc, "\n")+1 );
//then you want to save it
file_put_contents($newFileContents, $file);
I might be wrong but you get the idea!~ ;)
Process :
Get Contents of file
Get First Line
Replace content of all file with your First Line as New Line
Save File
Im sure there is a more efficient way to do this, im just winging!
NOTE: You may need to configure your php.ini to work with larger files!
yes, Mark is probably too lazy to even try bulid a code, but i have already a working code so.. copypasta
$file = "mydata.txt";
$f = fopen($file, 'r');
$line = fgets($f);
fclose($f);
//do smth
$contents = file($file, FILE_IGNORE_NEW_LINES);
$first_line = array_shift($contents);
file_put_contents($file, implode("\r\n", $contents));
//sleep(1);
This question already has answers here:
Need to write at beginning of file with PHP
(10 answers)
Closed 9 years ago.
Hi I want to append a row at the beginning of the file using php.
Lets say for example the file is containing the following contnet:
Hello Stack Overflow, you are really helping me a lot.
And now i Want to add a row on top of the repvious one like this:
www.stackoverflow.com
Hello Stack Overflow, you are really helping me a lot.
This is the code that I am having at the moment in a script.
$fp = fopen($file, 'a+') or die("can't open file");
$theOldData = fread($fp, filesize($file));
fclose($fp);
$fp = fopen($file, 'w+') or die("can't open file");
$toBeWriteToFile = $insertNewRow.$theOldData;
fwrite($fp, $toBeWriteToFile);
fclose($fp);
I want some optimal solution for it, as I am using it in a php script. Here are some solutions i found on here:
Need to write at beginning of file with PHP
which says the following to append at the beginning:
<?php
$file_data = "Stuff you want to add\n";
$file_data .= file_get_contents('database.txt');
file_put_contents('database.txt', $file_data);
?>
And other one here:
Using php, how to insert text without overwriting to the beginning of a text file
says the following:
$old_content = file_get_contents($file);
fwrite($file, $new_content."\n".$old_content);
So my final question is, which is the best method to use (I mean optimal) among all the above methods. Is there any better possibly than above?
Looking for your thoughts on this!!!.
function file_prepend ($string, $filename) {
$fileContent = file_get_contents ($filename);
file_put_contents ($filename, $string . "\n" . $fileContent);
}
usage :
file_prepend("couldn't connect to the database", 'database.logs');
My personal preference when writing to a file is to use file_put_contents
From the manual:
This function is identical to calling fopen(), fwrite() and fclose()
successively to write data to a file.
Because the function automatically handles those three functions for me I do not have to remember to close the resource after I'm done with it.
There is no really efficient way to write before the first line in a file. Both solutions mentioned in your questions create a new file from copying everything from the old one then write new data (and there is no much difference between the two methods).
If you are really after efficiency, ie avoiding the whole copy of the existing file, and you need to have the last inserted line being the first in the file, it all depends how you plan on using the file after it is created.
three files
Per you comment, you could create three files header, content and footer and output each of them in sequence ; that would avoid the copy even if header is created after content.
work reverse in one file
This method puts the file in memory (array).
Since you know you create the content before the header, always write lines in reverse order, footer, content, then header:
function write_reverse($lines, $file) { // $lines is an array
for($i=count($lines)-1 ; $i>=0 ; $i--) fwrite($file, $lines[$i]);
}
then you call write_reverse() first with footer, then content and finally header. Each time you want to add something at the beginning of the file, just write at the end...
Then to read the file for output
$lines = array();
while (($line = fgets($file)) !== false) $lines[] = $line;
// then print from last one
for ($i=count($lines)-1 ; $i>=0 ; $i--) echo $lines[$i];
Then there is another consideration: could you avoid using files at all - eg via PHP APC
You mean prepending. I suggest you read the line and replace it with next line without losing data.
<?php
$dataToBeAdded = "www.stackoverflow.com";
$file = "database.txt";
$handle = fopen($file, "r+");
$final_length = filesize($file) + strlen($dataToBeAdded );
$existingData = fread($handle, strlen($dataToBeAdded ));
rewind($handle);
$i = 1;
while (ftell($handle) < $final_length)
{
fwrite($handle, $dataToBeAdded );
$dataToBeAdded = $existingData ;
$existingData = fread($handle, strlen($dataToBeAdded ));
fseek($handle, $i * strlen($dataToBeAdded ));
$i++;
}
?>
I'm experimenting with fopen for the first time and was wondering if it was possible to search for a particular section within a file before adding or replacing that content with data?
Ideally, I'd like to:
Use fopen to get the file
Search for a comment called <!-- test -->
Replace that comment with new data.
This possible? (for the record - Appending data to the end of the file or adding new data to a specific line number would not work for what I'm working on as the file is constantly changing).
Thanks!
<?php
// make sure radio is set
if( isset($_POST['enableSocialIcons']) )
{
// Open file for read and string modification
$file = "/test";
$fh = fopen($file, 'r+');
$contents = fread($fh, filesize($file));
$new_contents = str_replace("hello world", "hello", $contents);
fclose($fh);
// Open file to write
$fh = fopen($file, 'r+');
fwrite($fh, $new_contents);
fclose($fh);
}
?>
From: http://www.php.net/manual/en/function.fopen.php#81325
EDIT: To see what exactly is getting sent by your form do this at the top of the PHP file you're posting to:
<?php
echo '<pre>';
print_r($_POST);
echo '</pre>';
exit;
?>
If you read the entire file in then use something str_replace to make the change, you should be able to get what you want.
I've got a php file echoing hashes from a MySQL database. This is necessary for a remote program I'm using, but at the same time I need my other php script opening and checking it for specified strings POST parsing. If it checks for the string pre-parsing, it'll just get the MySQL query rather than the strings to look for.
I'm not sure if any functions do this. Does fopen() read the file prior to parsing? or file_get_contents()?
If so, is there a function that'll read the file after the php and mysql code runs?
The file with the hashes query and echo is in the same directory as the php file reading it, if that makes a difference.
Perhaps fopen reads it post-parse, and I've done something wrong, but at first I was storing the hashes directly in the file, and it was working fine. After I changed it to echo the contents of the MySQL table, it bugged out.
The MySQL Query script:
$query="SELECT * FROM list";
$result=mysql_query($query);
while($row=mysql_fetch_array($result, MYSQL_ASSOC)){
echo $row['hash']."<br>";
}
What I was using to get the hash from this script before, when it was just a list of hashes:
$myFile = "hashes.php";
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
fclose($fh);
$mystring = $theData;
$findme = $hash;
$pos = strpos($mystring, $findme);
The easiest thing to do would be to modify your first php file which echoes everything, along these lines:
change every instance of echo to e.g. $data[] =
at the bottom, do foreach($data as $d) echo $d (this will produce the same result as you have right now)
you now still have your $data array which you can loop through and do whatever you like with it.
To provide working code examples, it would be great if you could post the current code of your file.
EDIT
If you change your script like so:
$query="SELECT * FROM list";
$result=mysql_query($query);
while($row=mysql_fetch_array($result, MYSQL_ASSOC)){
$data[] = $row['hash']."<br />";
}
foreach($data as $d) {
echo $d;
}
...you'll have the array $data that contains each hash in a key. You can then loop through this array like so:
foreach($data as $d) {
//do something
}