I am trying to store an Base64 string to my MySql database using PHP. Here is my code.
<?PHP
//Store Image
$photoData = $_POST['PhotoData'];
//Database connection details
$db_url = "192.168.1.140";
$db_user_name = "easyblogadmin";
$db_password = "admin";
$db_name = "easyblog";
$con = mysqli_connect($db_url, $db_user_name, $db_password);
$sql = "insert into temptable (photodata) values('$photoData')";
if(mysqli_connect_errno()){
echo "Failed to Connect Database";
echo mysqli_connect_errno();
die();
} else {
//Connecting to Application Database
$db_selected = mysqli_select_db($con, $db_name);
if(!$db_selected){
echo "Failed to Connect Application Database";
die();
} else {
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
echo "Successfully Added photo".strlen($photoData);
}
}?>
Here the $photoData is my Base64 encoded string and I am storing this in my DB. When i am trying to retrieve this data from DB some data in my string is missing. I don't understand why this is happening. Can any one help me out.
regards.
chnage the sql query as below mentioned
$sql = "insert into databasename.temptable (photodata) values('$photoData')";
also please make sure if the encoded value has any single quotes,if it is then replace the data as mentioned below .
$photoData =str_replace("'","\'",$_POST['PhotoData']);
Related
Here is the code
<?php
$servername = "localhost";
$usrname = "root";
$pwd = "";
$db = "test_db";
// connect to the database
$conn= mysqli_connect($servername, $usrname, $pwd,$db);
if (!$conn){
die('connection failed' . mysqli_connect_error());
}
// Create database
$sql = "CREATE DATABASE IF NOT EXISTS test_db";
if (mysqli_query($conn, $sql)) {
echo "Database created successfully<br>";
} else {
echo "Error creating database: " . mysqli_error($conn);
}
?>
I am not sure what is going on as I am sure i made no errors while typing. As it keeps showing me that there is an unknown database despite the fact i made a CREATE DATABASE statement.
I do not know if there is something else i need to do but by all measures the code should work.
It is supposed to echo the "Database created successfully" or the error message.
`<?php
$servername = "localhost";
$usrname = "root";
$pwd = "";
//$db = "test_db";
// connect to the database
$conn= mysqli_connect($servername, $usrname, $pwd);
if (!$conn){
die('connection failed' . mysqli_connect_error());
}
// Create database
$sql = "CREATE DATABASE IF NOT EXISTS test_db";
if (mysqli_query($conn, $sql)) {
echo "Database created successfully<br>";
} else {
echo "Error creating database: " . mysqli_error($conn);
}
?>`
Your code is fine, You just have to remove $db from mysqli_connect().
Because you are requesting to connect "test_db" to this database which already not exists.
<?php
// Connect to MySQL
$link = mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
// Make my_db the current database
$db_selected = mysql_select_db('my_db', $link);
if (!$db_selected) {
// If we couldn't, then it either doesn't exist, or we can't see it.
$sql = 'CREATE DATABASE my_db';
if (mysql_query($sql, $link)) {
echo "Database my_db created successfully\n";
} else {
echo 'Error creating database: ' . mysql_error() . "\n";
}
}
mysql_close($link);
?>
Reference
How do I create a database if it doesn't exist, using PHP?
$conn= mysqli_connect($servername, $usrname, $pwd,$db);
You are trying to connect to a database that did not initially exist, so you get a fatal error.
Try creating new database using try catch blocks
try{
$conn= mysqli_connect($servername, $usrname, $pwd,$db);
}cath(Exception $e){
//your code
}
Hello anyone who can help (or having the same issue).
I have a form on my website I need to store the data in a database.
I have no problems when using any other database service but when using an Amazon RDS Database I have no luck.
This php file is used to send the data to the database.
<?php
$dbhost = "xxxx.xxxx.ap-southeast-2.rds.amazonaws.com";
$dbuser = "username";
$dbpass = "pasword";
$userid = $_GET['UniqueID'];
$username = $_GET['name'];
$useremail = $_GET['email'];
$userphone = $_GET['phone'];
$userref = $_GET['refid'];
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = "INSERT INTO landing_post (`useid`, `name`, `email`, `phone`, `refid`) VALUES ('$userid', '$username', '$useremail', '$userphone', '$userref')";
mysql_select_db('bunker');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not enter data: ' . mysql_error());
}
echo "Entered data successfully\n";
mysql_close($conn);
?>
After the form is submitted to the original post action, it opens the below url.
https://example.com.au/test/post.php?&UniqueID=10020&name=burger&email=test%40mvmedia.com&phone=1800+000+000&refid=28383
The $_GET functions fill out the data using the variables in the url.
When running the php from a cpanel based server I get this error.
Could not connect: Can't connect to MySQL server on 'xxxxx.xxxxxxx.ap-southeast-2.rds.amazonaws.com' (111)
When running the php from a AWS EC2 instance I don't even get a error readout.
Any assistance or insight would be greatly appreciated.
Cheers,
Andy
Shout out to JeanPaul98 who put me on the right path. After trial and many errors, i found the below code solved the issue.
<?php
$userid = $_GET['UniqueID'];
$username = $_GET['name'];
$useremail = $_GET['email'];
$userphone = $_GET['phone'];
$userref = $_GET['refid'];
$link = mysqli_connect('xxxxx.xxxxxx.ap-southeast-2.rds.amazonaws.com', 'User', 'password','database');
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Check if server is alive
if (mysqli_ping($link))
{
echo "Connection is ok!";
}
else
{
echo "Error: ". mysqli_error($link);
}
mysqli_query($link,"INSERT INTO table (`useid`, `name`, `email`, `phone`, `refid`) VALUES ('$userid', '$username', '$useremail', '$userphone', '$userref')")
or die(mysqli_error($link));
echo "Entered data successfully\n";
mysqli_close($link);
?>
The main change was I stopped using mysql and rather used mysqli. There are also some structural changes to make the code to work with mysqli. For others having a similar issues here are a few things to check.
You have opened a inbound port for the IP in the security group of the RDS Database.
The Database is publicly accessible.
That your php version has PDO_MYSQL installed, or compatible driver (more details here
https://docs.aws.amazon.com/elasticbeanstalk/latest/dg/create_deploy_PHP.rds.html)
I use the hosting company aPlus.net, and I can't seem to get past a connection error I'm getting when trying to process some php to write database content to a webpage, and I am curious as to if this is because my database appears to not be on the same server as the entire rest of my hosting account, and if there is a way to resolve this in my code? This is my first attempt at writing PHP, and it would be good to know if my code is wrong, or if my hosting company is messing me up. (and either way, how to fix it)
Here's the code that's failing to pull from the database:
{
$con = mysql_connect("localhost","2p5dq9vxmy240651","MY_PASSWORD");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("felineasthma_2p5dq9vxmy240651", $con);
$users_name = $_POST['name'];
$users_comment = $_POST['requests'];
$users_name = mysql_real_escape_string($users_name);
$users_comment = mysql_real_escape_string($users_comment);
$inputid = $_GET['id'];
$query = "
INSERT INTO `felineasthma_2p5dq9vxmy240651`.`submissions` (`id`,
`name`, `requests`, `inputid`) VALUES (NULL,
'$users_name', '$users_comment', '$inputid');";
mysql_query($query);
echo "<h2>Your request has been processed, reload page.</h2>";
mysql_close($con);
}
and here's some screen captures from inside my hosting account (links because I don't have enough posts here yet to upload images, sorry):
felineasthma_2p5dq9vxmy240651 doesn't appear in my hosting account
yet it clearly exists in MySQL Manager, but on a different server
I was even more confused while making the user for this database, as the control panel didn't allow me to make a username, it just randomly assigned one. Help? Advice?
I found a more modern tutorial to learn PHP with, and now everything works, I just need to add security measures now. Here's the working code snippets, if anyone ever comes here asking the same questions.
here's the form action that places the entries into the database:
<?php
$servername = "sql5c40n.carrierzone.com";
$username = "my_username";
$password = "my_password";
$dbname = "my_database";
$users_name = $_POST['name'];
$users_request = $_POST['requests'];
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO submissions (name, requests)
VALUES ('$users_name', '$users_request')";
if (mysqli_query($conn, $sql)) {
header("Location: clv.php");
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
?>
here's the include that puts the database entries onto the page:
<?php
$servername = "sql5c40n.carrierzone.com";
$username = "my_username";
$password = "my_password";
$dbname = "my_database";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT id, requests, name FROM submissions";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "" . $row["requests"]. " - by " . $row["name"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
My PHP file need to save the image in a server and store the image path in a MYSQL database.
My database imageid contains table image_table as below :
create table image_table
(
ID INT not null AUTO_INCREMENT,
path varchar(256),
primary key (ID)
)
My PHP Code is as below. Image saving in the server is working fine, but throws few errors storing the image path in DB.
Error running the below PHP code :
Parse error: syntax error, unexpected '$conn' (T_VARIABLE) in C:\xampp\htdocs\appinventor\postfile.php on line 7
The PHP Code with above error:
<?PHP
$servername = "localhost";
$username = "root";
$password = "basis123";
$database = "imageid"
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
#mysqli_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO image_table (path) VALUES('$_GET['filename']')");
//mysql_query($query);
//File Transfer Logic
$data = file_get_contents('php://input');
if (!(file_put_contents($_GET['filename'],$data) === FALSE)) echo "File xfer completed."; // file could be empty, though
else echo "File xfer failed.";
// $_GET['filename'] has the file name . and C:\xampp\htdocs\myapp is the file path
echo $_GET['filename']
//mysql_close();
?>
When i remove the database connection and SQLQuery in php code the connection is successful.
Removed lines of code for successful connection and log as "Connected successful"
#mysqli_select_db($database) or die( "Unable to select database");
$query = "INSERT INTO image_table (path) VALUES('$_GET['filename']')");
//mysql_query($query);
Where did i go wrong ?Any suggestions ?
You forgot semicolon after $database = "imageid"
$database = "imageid";
And you have extraneous parenthesis here:
$query = "INSERT INTO image_table (path) VALUES('$_GET['filename']')");
Try this:
<?php
$servername = "localhost";
$username = "root";
$password = "basis123";
$database = "imageid";
// Create connection
$conn = new mysqli($servername, $username, $password,$database);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
mysqli_select_db($conn,$database);
$query = "INSERT INTO image_table (path) VALUES('".$_GET['filename']."')";//also this is unsafe
//mysql_query($query);
//File Transfer Logic
$data = file_get_contents('php://input');
if (!(file_put_contents($_GET['filename'],$data) === FALSE)) echo "File xfer completed."; // file could be empty, though
else echo "File xfer failed.";
// $_GET['filename'] has the file name . and C:\xampp\htdocs\myapp is the file path
echo $_GET['filename']
//mysql_close();
?>
Main problem:
$database = "imageid"
^----missing ;
$conn = new m
PHP strings+arrays 101: You cannot use quoted array keys within a double-quoted string, unless you use the {}-extended syntax:
$foo = "$arr['key']"; // bad
$foo = "$arr[key]"; // ok
$foo = "{$arr['key']}"; // ok
So:
$query = "INSERT INTO image_table (path) VALUES('$_GET['filename']')");
^--------^
is wrong, as well as being vulnerable to SQL injection attacks.
You need a semi colon after
$database = "imageid"
so it should be
$database = "imageid";
You also don't want to be putting user input directly into your SQL. http://en.wikipedia.org/wiki/SQL_injection
I am a PHP newbie and have been trying for sometime now to connect to MySQL database using PHP so I can insert data into a table I have created but I am unable to do this.
I suspect the problem is coming from my PHP .ini file,but that's just me.
Would be grateful if anyone can help me configure my PHP .ini file so I can connect to MySQL and insert data into my table. Here is my PHP script in case you are wondering.
Any help will be gratefully appreciated.
<?php
$host ="localhost";
$username = "username";
$password = "password";
$database = "database1";
$table ="users";
$con = mysql_connect("localhost","username","password");
if (!$con)
{
die('Could not connect:'.mysql_error());
}
mysql_select_db("database1",$con);
$mysql = "INSERT INTO $table(name,email,password)
VALUES('$_POST[name]','$_POST[email]','$_POST[password]";
if(mysql_query($mysql)) die(mysql_error());
echo"Data inserted";
mysql_close();
?>
I revised some of your code this should work. You had a bunch of little errors. I suggest you read a couple tutorials on just connecting and the syntax of php.
Here is some really basic examples of connecting to a database:
http://www.w3schools.com/php/php_mysql_connect.asp
Also once you get the hang of it here is a really good tutorial to teach you the OOP way of creating a class for a database:
http://net.tutsplus.com/tutorials/php/real-world-oop-with-php-and-mysql/
As far as I see this is not an ini issue. I hope this helps.
<?php
//Set your variables
$host = "127.0.0.1";
$username = "username";
$password = "password";
$database = "database1";
$table = "users";
//Make your connection to database
$con = mysql_connect($host,$username,$password);
//Check your connection
if (!$con) {
die("Could not connect: " . mysql_error());
}
//Select your database
$db_selected = mysql_select_db($database, $con);
//Check to make sure the database is there
if (!$db_selected) {
die ('Can\'t use the db : ' . mysql_error());
}
//Run query
$result = mysql_query("INSERT INTO $table(name,email,password) VALUES('$_POST[name]','$_POST[email]','$_POST[password]'");
//Check Query
if (!$result) {
die("lid query: " . mysql_error());
}
echo "Data inserted";
mysql_close($con);
?>
First, why do you have <br/> in your PHP statements? Remove all those.
Also, you have to use PDO or mysqli_ instead of the mysql_ library, mysql_ is deprecated.