Filtering JSON Object and outputting another - php

Question

I'm trying to parse a JSON file which looks like this,
[
{
"id": "539eebdba276db40a4716726",
"name": "Development Task",
"idList": "539eebbb4e9a8d709704b254",
"desc": "",
"url": ""
},
{
"id": "539eebe09b42c971d46b9ba1",
"name": "Design Task",
"idList": "539eebbe50dc4fa2a82474fc",
"desc": "",
"url": ""
}
]
I'm trying to get the desc object from the array with the name Development Task, the system needs to be dynamic so I can't just use json_o[0](desc);
I've tried different methods such as foreaching the data multiple times but I still can't think of a solution, any help would be great, cheers.

Answer 1

Try with this:
$jsonData = '[
{
"id": "539eebdba276db40a4716726",
"name": "Development Task",
"idList": "539eebbb4e9a8d709704b254",
"desc": "",
"url": ""
},
{
"id": "539eebe09b42c971d46b9ba1",
"name": "Design Task",
"idList": "539eebbe50dc4fa2a82474fc",
"desc": "",
"url": ""
}
]';
$encoded = json_decode($jsonData);
foreach($encoded as $data)
{
if('Development Task' == $data->name)
{
echo $data->desc;
}
}

Answer 2

If you search for dynamic fields, i would have gone with :
$jsonData = '[
{
"id": "539eebdba276db40a4716726",
"name": "Development Task",
"idList": "539eebbb4e9a8d709704b254",
"desc": "FirstDescription",
"url": ""
},
{
"id": "539eebe09b42c971d46b9ba1",
"name": "Design Task",
"idList": "539eebbe50dc4fa2a82474fc",
"desc": "SecondDescription",
"url": ""
}
]';
$arrayFromJson = json_decode($jsonData, true);
function searchByKey($keyToSearchIn, $searchName, $array) {
foreach ($array as $key => $val) {
if ($val[$keyToSearchIn] == $searchName) {
return $val['desc'];
}
}
return null;
}
$return = searchByKey("name", "Development Task", $arrayFromJson);
So
var_dump($return);
returns
string(16) "FirstDescription"
Note : If you only need a search by name, you can change the function with :
function searchByName( $searchName, $array) {
foreach ($array as $key => $val) {
if ($val['name'] == $searchName) {
return $val['desc'];
}
}
return null;
}
$return = searchByName("Development Task", $arrayFromJson);
Hope it helps.

Answer 3

The comments in the code explain what happens:
$jsonData = '[
{
"id": "539eebdba276db40a4716726",
"name": "Development Task",
"idList": "539eebbb4e9a8d709704b254",
"desc": "moocow",
"url": ""
},
{
"id": "539eebe09b42c971d46b9ba1",
"name": "Design Task",
"idList": "539eebbe50dc4fa2a82474fc",
"desc": "wowcow",
"url": ""
},
{
"id": "539eebe09rb42c971d46b9ba1",
"name": "Development Task",
"idList": "539eebbe50dc4fa2a82474fc",
"desc": "sowccow",
"url": ""
}
]';
$encoded = json_decode($jsonData, true); //converts the json object to an array
foreach ($encoded as $arrayObject){
if( in_array("Development Task", $arrayObject) ){
print_r($arrayObject['desc'] . "\n");
}
}
-> moocow sowccow
based upon
I'm trying to get the desc object from the array with the name Development Task
This should do what you want and you can easily take the string and make it a variable. There are plenty of built-in functions on PHP.net that are tuned and are probably 10x better than rolling your own code.