<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = "";
$name=$_POST['user'];
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT * FROM `usertable` WHERE `username`='$name'' ;
mysql_select_db('myxiv');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
echo "Name :{$row['username']} .<br> ";
}
mysql_close($conn);
?>
Here is my code and i'm getting this error.
Syntax error, unexpected '$name' (T_VARIABLE)
I m trying to retrive data from a table to display in the profile page
$sql = 'SELECT * FROM usertable WHERE username='$name'' ;
Replace Your above query by bellow code and check it.
$sql = "SELECT * FROM usertable WHERE username=' ".$name." ' ";
Try this
Change
$sql = 'SELECT * FROM usertable WHERE username`='$name'' ;
TO
$sql = "SELECT * FROM usertable WHERE username='".$name."';
You make a few mistakes. mysql (which is depracted (take a look at PDO or mysqli)) doesn't need a connection.
You could have a double single quote error but the following should fix some of it:
if($_POST) {
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$name = mysql_real_escape_string(strip_tags($_POST['user']));
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db('myxiv');
$retval = mysql_query("SELECT * FROM `usertable` WHERE `username` = '$name'");
if(! $retval ) {
die('Could not get data: ' . mysql_error());
} else {
while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) {
echo "Name :{$row['username']} .<br> ";
}
}
}
Related
I have a problem with this code. It has syntax error and I don't know what is it.
<?php
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'id1381007_accounts';
$conn = new mysqli($host,$user,$pass,$db) or die($mysqli->error);
if (!$conn) {
die('Could not connect: ' . mysql_error());
$sql = 'SELECT id FROM users WHERE email=\"donat12#icloud.com\"';
echo $sql;
?>
There are some issue with the code. First you forgot to close the if condition over here
if (!$conn) {
And then you forgot to execute the sql query
the complete code would be like
<?php
$host = 'localhost';
$user = 'root';
$pass = '';
$db = 'id1381007_accounts';
$conn = new mysqli($host,$user,$pass,$db) or die($mysqli->error);
if (!$conn) {
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT id FROM users WHERE email=\"donat12#icloud.com\"';
if ($result = $conn->query($sql)) {
while ( $row = $result->fetch_assoc()) {
$data[] = $row;
}
echo "<pre>";
print_r($data);
echo "</pre>";
}
$conn->close();
?>
There are two errors
You are missing } closing bracket after die
Mysql query is wrong.
So the code should be
if (!$conn) {
die('Could not connect: ' . mysql_error());
}
$sql = 'SELECT id FROM users WHERE email="donat12#icloud.com"';
echo $sql;
I am trying to backup mysql database using php.
I tried the code below:
<?php
$dbhost = 'my_host';
$dbuser = 'my_user';
$dbpass = 'my_pass';
$db = 'my_dbname';
$conn = mysql_connect($dbhost, $dbuser, $dbpass, $db);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
$table_name = "my_table";
$backup_file = "/tmp/my_table.sql";
$sql = "SELECT * INTO OUTFILE '$backup_file' FROM $table_name";
mysql_select_db($db);
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not take data backup: ' . mysql_error());
}
echo "Backedup data successfully\n";
mysql_close($conn);
?>
but I got this error:
"Could not take data backup: Access denied for user 'my_user'#'%' (using password: YES)"
Could you help me, please? Thanks!
Try
<?php
$dbhost = 'my_host';
$dbuser = 'my_user';
$dbpass = 'my_pass';
$db = 'my_dbname';
$conn = mysql_connect($dbhost, $dbuser, $dbpass, $db);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
$table_name = "my_table";
$backup_file = "/tmp/my_table.sql";
$sql = "SELECT * INTO OUTFILE '$backup_file' FROM $table_name";
// set current db with connection resource
mysql_select_db(db, $conn);
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not take data backup: ' . mysql_error());
}
echo "Backedup data successfully\n";
mysql_close($conn);
$query = "SELECT * FROM Student WHERE student_id = $child AND school_id = $college";
$result = mysqli_query($conic, $query);
if(!$result){
die(" query failed");
echo 'error here';
} else {
i am trying to retrieve some information from the SQL database but the query seems to fail any ideas?
You must learn more : how to retrieve data from database using select in php
so try out following example to display all the records from Student table
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = 'rootpassword';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$sql = "SELECT * FROM student WHERE student_id = '"$child"' AND school_id = '"$college"' ";
mysql_select_db('test_db');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
// some code here
}
echo "Fetched data successfully\n";
mysql_close($conn);
?>
NOTE
The mysql extension is deprecated and will be removed in the future:
use mysqli or PDO
im getting the following syntax error can someone please help!
im guessing it something soooo easy but i have been looking at it for ages and can see what im doing wrong
<?php
if(isset($_POST['delete']))
{
$dbhost = '';
$dbuser = '';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
$CourseId = $_POST['CourseId'];
$sql = "DELETE course ".
" WHERE CourseId = $CourseId" ;
mysql_select_db('d11os_projectdb');
$retval = mysql_query( $sql, $conn );
if(! $retval )
{
die('Could not delete data: ' . mysql_error());
}
echo "Deleted data successfully\n";
mysql_close($conn);
}
else
{
?>`enter code here`
$sql = "DELETE FROM course ". --<-- Missing key word FROM
" WHERE CourseId = $CourseId"
You are missing the table name from the sql query
$sql = "DELETE course FROM **table_name**".
" WHERE CourseId = $CourseId" ;
I am working with a MLM company where com has to register the member, if it detects any mistake in data, it has to update the data of member again.
I have the right code which works well when all fields has to update but problem is it does not work for individual input boxes. Please give me solution of this problem.
<?php
if(isset($_POST['update'])) {
$dbhost = 'localhost';
$dbuser = 'vvvv';
$dbpass = 'xxxx';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
$usrid = $_POST['uid'];
$pwrd = $_POST['pwd'];
$nm = $_POST['noe'];
$fnm = $_POST['fn'];
$addrs = $_POST['adrs'];
$cntn = $_POST['cnt_no'];
$cty = $_POST['ct'];
$sql = "UPDATE office_user ".
"SET
password = '$pwrd',
name='$nm',
father_name='$fnm',
address='$addrs',
contact_no='$cntn',
city='$cty' ".
"WHERE user_id = '$usrid'" ;
mysql_select_db('my_db');
$retval = mysql_query( $sql, $conn );
if(! $retval ) {
die('Could not update data: ' . mysql_error());
}
echo "Updated data successfully\n";
mysql_close($conn);
}
?>