This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 8 years ago.
I am trying to put this line of code:
echo $row['url'];
between the quotations in this line of code:
$data = file_get_contents ("");
I have a link saved in my database which I want to be displayed between those brackets, but I keep getting syntax errors whatever way I try it. Is this possible or am I being stupid?
try that :
$data = file_get_contents ($row['url']);
Related
This question already has answers here:
How do I pass variables and data from PHP to JavaScript?
(19 answers)
Send PHP variable to JavaScript function [duplicate]
(6 answers)
How to pass php variable to JavaScript function as parameter
(4 answers)
how to pass php variable to javascript?
(2 answers)
Closed 12 months ago.
I am having one onclick event with some paramters with it. But in some
cases i am getting double quaotes or space between strings. so getting
error of Uncaught SyntaxError: missing ) after argument list or
invalid token.
How to overcome with this issue. I tried to use array and trim the
variables but it wont work for me.
$stringArray = ['string 1', 'string'2','001'];
$concatenated = trim(implode(',',$stringArray));
E.g: I am getting 3 string like :
$data1 = 'surgery';
$data2 = 'Cardio'c';
$data3 = 'hopsital ab"cc';
<a id='changeState' onclick=editModal(\"". $data1 ."\",\"". $data2 ."\",\"".$data3."\");>Click Here</a>
Please help to resolve this issue.
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 2 years ago.
I have 2 php files inside joomla and I want to make a variable from php-file 1 available in php-file 2.
php-file_1.php
$a_variable = $input->getString('text');
php-file_2.php
include(php-file_1.php);
echo $a_variable;
I get Notice: Undefined variable: a_variable in /var/www/vhosts/a_domain.de/httpdocs/php-file_2.php on line 2
what's wrong here?
include and require are not functions, they are language constructs. Therefore they need to be used without brackets.
Either way, you missed quotes around php-file_1.php.
include 'php-file_1.php'; should work fine.
This question already has answers here:
Reference - What does this error mean in PHP?
(38 answers)
Closed 3 years ago.
So I have this url:
Api.php?action=signup&name=Kalle&email=kalle#hiof.no&password=kalle&studieretning=IT&year=2000
To get the name out is it correct to have
echo $_POST['name'];
Cause in my case this ain't working
If you are using the querystring (which you are) then data arrives to PHP in the $_GET array not the $_POST array
So that would be
echo $_GET['name'];
This question already has answers here:
What is the use of the # symbol in PHP?
(11 answers)
Closed 7 years ago.
$block_header = #unpack('Sc_size/Su_size/Lchecksum', fread($this->fp, 8));
What does this mean ?
PHP Error Control Operators.
it avoids showing the error returned by the function. more info in the link:
http://www.php.net/manual/en/language.operators.errorcontrol.php
This question already has answers here:
'Why' doesn't the script print anything? [duplicate]
(5 answers)
Closed 9 years ago.
This is a weird issue.
I just trying to print/create a string like below :
sort="name<string>"
so I just do
echo 'sort="name<string>"';
however, it seems that PHP store it as :
sort="name"
What do I miss?
Try this...
echo htmlspecialchars('sort="name<string>"', ENT_QUOTES, 'UTF-8');
Try this:
echo 'sort="name<String>"';