MySQL nested resources (pivot tables) permission to view/update/manage - php

users transactions tasks
+----+--------+ +----+---------------+ +----+--------+
| id | name | | id | name | | id | name |
+----+--------+ +----+---------------+ +----+--------+
| 1 | User 1 | | 1 | Transaction 1 | | 1 | Task 1 |
| 2 | User 2 | | 2 | Transaction 2 | | 2 | Task 2 |
+----+--------+ +----+---------------+ +----+--------+
templates transaction_user task_transaction
+----+---------------+ +---------+----------------+ +---------+----------------+
| id | name | | user_id | transaction_id | | task_id | transaction_id |
+----+---------------+ +---------+----------------+ +---------+----------------+
| 1 | Template 1 | | 1 | 1 | | 1 | 1 |
| 2 | Template 2 | | 2 | 2 | +---------+----------------+
+----+---------------+ +---------+----------------+
task_template
+---------+-------------+
| task_id | template_id |
+---------+-------------+
| 2 | 2 |
+---------+-------------+
Motive:
If there is a logged in user, say user with the ID 1, and he/she wants to see a task (say task with the ID 1) then i want to make sure that the task with ID 1 Belongs to the user before i let him view it. Also i need someway to show user all tasks that belong to him. Task is just one model.. i need to handle this for all models. I have shared my code below, am i trying too hard?
I may have omitted some details here so please feel free to ask questions.
Thanks.
Code
<?php namespace SomeProject\Repositories;
use User;
use Account;
use Task;
use Document;
use Transaction;
use Property;
use DB;
use Respond;
abstract class DbRepository
{
/**
* The many to many relationships are handeled using pivot tables
* We will use this array to figure out relationships and then get
* a particular resource's owner / account
*/
public $pivot_models = array(
'Task' => array(
'Transaction' => 'task_transaction'
),
'Transaction' => array(
'User' => 'transaction_user'
),
'Document' => array(
'Property' => 'document_property',
'Task' => 'document_task',
'Message' => 'document_message'
)
);
public $entity_ids;
public function getOwnersByEntity(array $ids, $entity)
{
$this->entity_ids = [];
$user_ids = [];
$entity = ucfirst(strtolower($entity)); // arrays keys are case sensitive
if( $this->getPivotIds($ids, $entity) )
{
foreach ($this->entity_ids as $entity_name => $entity_ids_arr)
{
$entity_name_lowercase = strtolower($entity_name);
if($entity_name_lowercase != 'user')
{
$user_ids_from_entity = $entity_name::whereIn('id', $entity_ids_arr)
->lists('user_id');
}
else
{
// We already have the IDs if the entity is User
$user_ids_from_entity = $entity_ids_arr;
}
array_push($user_ids, $user_ids_from_entity);
}
$merged_user_ids = call_user_func_array('array_merge', $user_ids);
return array_unique($merged_user_ids);
}
else
{
return $entity::whereIn('id', $ids)->lists('user_id');
}
}
public function getPivotIds(array $ids, $entity)
{
$entity_lowercase = strtolower($entity);
if( array_key_exists($entity, $this->pivot_models) )
{
// Its a pivot model
foreach ($this->pivot_models[$entity] as $related_model => $table) // Transaction, Template
{
$related_model_lowercase = strtolower($related_model);
$this->entity_ids[$related_model] = DB::table($table)
->whereIn($entity_lowercase . '_id', $ids)
->lists($related_model_lowercase . '_id');
if( $this->getPivotIds($this->entity_ids[$related_model], $related_model) )
{
unset($this->entity_ids[$related_model]);
}
}
return true;
}
return false;
}
}

To check if given model is related to another one, which is what you want if I get you right, all you need is this tiny method making the most of Eloquent:
(Implement it in BaseModel, Entity or a scope, whatever suits you)
// usage
$task->isRelatedTo('transactions.users', $id);
// or
$template->isRelatedTo('tasks.transactions.users', Auth::user());
// or any kind of relation:
// imagine this: User m-m Transaction 1-m Item m-1 Group
$group->isRelatedTo('items.transaction.users', $id);
The magic happens here:
/**
* Check if it is related to any given model through dot nested relations
*
* #param string $relations
* #param int|\Illuminate\Database\Eloquent\Model $id
* #return boolean
*/
public function isRelatedTo($relations, $id)
{
$relations = explode('.', $relations);
if ($id instanceof Model)
{
$related = $id;
$id = $related->getKey();
}
else
{
$related = $this->getNestedRelated($relations);
}
// recursive closure
$callback = function ($q) use (&$callback, &$relations, $related, $id)
{
if (count($relations))
{
$q->whereHas(array_shift($relations), $callback);
}
else
{
$q->where($related->getQualifiedKeyName(), $id);
}
};
return (bool) $this->whereHas(array_shift($relations), $callback)->find($this->getKey());
}
protected function getNestedRelated(array $relations)
{
$models = [];
foreach ($relations as $key => $relation)
{
$parent = ($key) ? $models[$key-1] : $this;
$models[] = $parent->{$relation}()->getRelated();
}
return end($models);
}
Hey, but what's going on there?
isRelatedTo() works like this:
check if passed $id is a model or just an id, and prepares $related model and its $id for use in the callback. If you don't pass an object then Eloquent needs to instantiate all the related models on the $relations (relation1.relation2.relation3...) chain to get the one we are interested in - that's what happens in getNestedRelated(), pretty straightforward.
then we need to do something like this:
// assuming relations 'relation1.relation2.relation3'
$this->whereHas('relation1', function ($q) use ($id) {
$q->whereHas('relation2', function ($q) use ($id) {
$q->whereHas('relation3', function ($q) use ($id) {
$q->where('id', $id);
});
});
})->find($this->getKey());
// returns new instance of current model or null, thus cast to (bool)
since we don't know how deeply the relation is nested, we need to use recurrency. However we pass a Closure to the whereHas, so we need to use little trick in order to call itself inside its body (in fact we don't call it, but rather pass it as $callback to the whereHas method, since the latter expects a Closure as 2nd param) - this might be useful for those unfamiliar Anonymous recursive PHP functions:
// save it to the variable and pass it by reference
$callback = function () use (&$callback) {
if (...) // call the $callback again
else // finish;
}
we also pass to the closure $relations (as an array now) by reference in order to unshift its elements, and when we got them all (meaning we nested whereHas), we finally put the where clause instead of another whereHas, to search for our $related model.
finally let's return bool

There's really no easy nor canonical way, but here's a raw example of what I'd try to do.
class Entity extends Eloquent {
public function isRelatedTo($instance, $through)
{
$column = $instance->joiningTable($through) . '.' . $instance->getForeignKey();
$query = DB::table('');
this->buildJoin($query, $instance, $through);
return $query->where($column, '=', $instance->getKey())->exists();
}
public function relatesToMany($related, $through)
{
$that = $this;
$related = new $related;
return $related->whereIn($related->getKeyName(), function($query) use ($that, $related, $through) {
$that->buildJoin($query, $related, $through);
})->get();
}
protected function buildJoin($query, $related, $through)
{
$through = new $through;
$this_id = $this->getForeignKey();
$related_id = $related->getForeignKey();
$through_id = $through->getForeignKey();
$this_pivot = $this->joiningTable($through);
$related_pivot = $related->joiningTable($through);
$query->select($related_pivot . '.' . $related_id)->from($related_pivot)
->join($this_pivot, $related_pivot . '.' . $through_id, '=', $this_pivot . '.' . $through_id)
->where($this_pivot . '.' . $this_id, '=', $this->getKey());
}
}
Then, for your use case:
class User extends Entity {
public function isOwnerOf($task)
{
return $this->isRelatedTo($task, 'Transaction');
}
public function tasks()
{
return $this->relatesToMany('Task', 'Transaction');
}
}
Disclaimer: the code has not been tested.
Note that, in this very simplified example, relatesToMany directly returns a Collection. To have more advantages, it could instead return an instance of your own extension of Eloquent's Relation class - that takes longer to implement, clearly.
It shouldn't be difficult to add support for multiple intermediate entities; you could likely expect the $through argument to possibly be an array and then build the multi-join query accordingly.

If this is a Laravel project, then yes, you're trying far too hard.
If you're going to use Laravel, it's recommended that you use the features provided to you with Laravel, which are namely it's ORM, Eloquent, and it's bundled Schema tool. I'd recommend that you view Laravel's Getting Started page in their documentation, so that you can set your project up correctly to use Eloquent.
It would also be beneficial if you read up on the basics of how Eloquent handles relations in their models, as they do all of the work that you're trying to do.

Related

Overriding cast type on pivot model

I have below model:
Document.php
/**
* Get all of the documents field content.
*
* #return Illuminate\Database\Eloquent\Model
*/
public function fields()
{
return $this->morphToMany(Field::class, 'fieldable')
->using('App\FieldablePivot')
->withPivot(['content', 'type'])
->withTimestamps();
}
That's using a Pivot model called FieldablePivot, where I need to access return the content column.
This is my FieldablePivot, where I have overwritten the getCastType method:
protected function getCastType($key)
{
if ($key == 'content' && !empty($this->type)) {
return $this->type;
}
return parent::getCastType($key);
}
Below is the rows of fieldables:
id | name | content | type |
---------------------------------------------
1 | field_one | [somearray] | array |
2 | field_two | somestring | string |
However, when I access a document and it's fields to get the content of a field, like:
#foreach ($document->fields as $field)
{{dd($field->pivot->content)}}
#endforeach
It returns the first one as a string (even though the type is of array):
"[somearray]"
You will have to override the hasCast function as well to make sure Eloquent knows there is a cast for this column.
public function hasCast($key, $types = null)
{
if ($key === 'content') {
return true;
}
return parent::hasCast($key, $types);
}
If you don't, and the field is not in the $casts array, Eloquent will not detect that the attribute has a cast.

Pass Eloquent pivot value to Laravel API resource

Laravel 5.7. I have 2 Eloquent models: Owner, Cat.
Owner model:
public function cats()
{
return $this->belongsToMany('App\Cat')->withPivot('borrowed');
}
Cat model:
public function owners()
{
return $this->belongsToMany('App\Owner')->withPivot('borrowed');
}
The cat_owner pivot table has these fields:
id | cat_id | owner_id | borrowed
---------------------------------
1 | 3 | 2 | 1
I want my API to return a list of all cats, and if the logged-in user has borrowed this cat, I want the borrowed field to be set to true. This is what I have so far:
Controller:
public function index()
{
return CatResource::collection(Cat::all());
}
CatResource:
public function toArray()
{
$data = ['id' => $this->id, 'borrowed' => false];
$owner = auth()->user();
$ownerCat = $owner->cats()->where('cat_id', $this->id)->first();
if ($ownerCat) {
$data['borrowed'] = $ownerCat->pivot->borrowed == 1 ? true : false;
}
return $data;
}
This works, but it seems wasteful to request the $owner for every cat, e.g. if there's 5000 cats in the database. Is there a more efficient way to do this? I can think of 2 possible ways:
Pass the $owner to the CatResource (requires overriding existing collection resource).
Get this information in the controller first, before passing to the CatResource.
I prefer the second way, but can't see how to do it.
Try Conditional Relationship.
public function toArray($request)
{
return [
'id' => $this->id,
'borrowed' => false,
'borrowed' => $this->whenPivotLoaded('cat_owner', function () {
return $this->owner_id === auth()->id() && $this->pivot->borrowed == 1 ? true : false;
})
];
}
then call return CatResource::collection(Cat::with('owners')->get());
You are right, this does a lot of extra loading. I think you are running into the limitation that you can't know which record form cat_owner you want until you know both the records you're using from the cat and owner table.
For anyone still interested, my solution would be to make a resource that gives you just the pivot values
Since the following returns a collection you canNOT go to the pivot table on it:
/*
* returns a collection
*/
$data['borrowed'] = $this->owners
/*
* So this doesNOT work. Since you can’t get the pivot
* data on a collection, only on a single record
*/
$data['borrowed'] = $this->owners->pivot
You should receive the collection and then you can read the pivot data in the Resource of the owner Record. If this resource is only for the pivot data I would call it something like attributes.
create a new resourse for the attributes, something like:
class CatOwnerAttributeResource extends JsonResource
{
public function toArray($request)
{
return [
'borrowed' => $this->pivot->borrowed,
];
}
}
Then receive the collection like so:
$data = ['id' => $this->id, 'borrowed' => false];
/*
* Get the collection of attributes and grab the first (and only) record.
* NOTE: the filtering is done in the collection, not in the DBM. If there
* is a possibility that the collection of owners who own this cat gets really
* big this is not the way to go!
*/
if ($attributes =
CatOwnerAttributeResource::collection(
$this->owner
->where(‘id’ = $auth->user()->id)
->first()
) {
$data[‘borrowed’] = $attributes->borrowed == 1 ? true : false;
}
return $data;
Couldn’t run this code so please point errors out if you try it and it gives you any, I will adjust.

Yii2: select last record from a hasMany relation

my knowledge on mysql is very basic and now im facing a "complex" (for me) query in which im stuck so thank you in advance if someone could give me some light on this.
I have three tables:
Orders
id | name | comments | ...
OrderLines
id | name | sDate | eDate | comments | ...
OrderLinesStats
id | lineID | date | status | ...
Every day OrderLinesStats is updated via a cron job and gets a new record with actual date, status and other fields so the highest id is the actual data.
Im trying to get that last stats row with a relation in yii2 as follows:
in OrdersLines model:
public function getLastOrdersLinesStats()
{
return $this->hasMany(OrdersLinesStats::className(), ['lineID' => 'id'])
->orderBy(['id'=>SORT_DESC])
->groupBy('lineID');
}
OrdersModel:
public function getOrdersLines()
{
return $this
->hasMany(OrdersLines::className(), ['orderID' => 'id'])
->orderBy(['typeID' => SORT_ASC, 'name' => SORT_ASC])
->with(['lastOrdersLinesStats']);
}
But when I debug the query looks like this:
SELECT * FROM `ordersLinesStats` WHERE `lineID` IN (1873, 1872, 1884, 1883, 1870, 1874, 1876, 1880, 1871, 1877, 1881, 1882, 1885, 1886, 1869, 1875, 1878) GROUP BY `lineID` ORDER BY `id` DESC
and doesnt give me the last stats record for each line... in fact, it gives me the oldest one. Seems that im missing something but i cant find it.
Thanks again
All you need to do is change the getLastOrdersLinesStats() to be as follows:
public function getLastOrdersLinesStats()
{
return $this->hasMany(OrdersLinesStats::className(), ['lineID' => 'id'])
->orderBy(['id'=>SORT_DESC])
->one();
}
This basically returns the last OrderLinesStats row that you want for each Order
You can access this as follows:
if you have an object called myOrder for example
then you can access the row you want as myOrder->lastOrderLinesStats
In OrdersModel add getLastOrderLineStat() method that uses via() junction:
public function getLastOrderLineStat()
{
return $this->hasOne(OrdersLinesStats::className(), ['lineID' => 'id'])
->orderBy(['id'=>SORT_DESC])
->groupBy('lineID')
->via('ordersLines');
}
If $model is an OrdersModel instance, you obtain the last stat row using:
$model->lastOrderLineStat
I am just answering this to be thorough and hopefully help other's who stumble upon this page.
I recommend always including both, hasOne and hasMany. This way, you can pop the top record, or retrieve all of them.
/**
* #return \yii\db\ActiveQuery
*/
public function getUserPlan()
{
return $this->hasOne(UserPlan::className(), ['user_id' => 'id'])
->orderBy(['id' => SORT_DESC])
->one();
}
/**
* #return \yii\db\ActiveQuery
*/
public function getUserPlans()
{
return $this->hasMany(UserPlan::className(), ['user_id' => 'id'])
->orderBy(['id' => SORT_DESC])
->all();
}
hasMany will return an array of ActiveQuery Objects, where hasOne will return just an ActiveQuery Object by itself.
You use them like so (example in UserController on User model):
$model = $this->findOne($id);
or
$model = User::findOne($id);
or
$model = User::find()->where(['id' => $id])->one();
Then grab the relations like so:
$plan = $model->userPlan
or
$plans = $model->userPlans
For userPlan:
$planId = $plan->id;
Handling userPlans:
foreach($plans as $plan) {
$plan->id;
}

Currency formatting in laravel

Could you help me with formatting amount figures in the Laravel blade based on model currency, please? Value is stored as double and currency as char(3) 'usd','eur','czk','huf'...
The projects has to be displayed in given currency format:
| 1 | project A | $1,250.00 |
| 2 | project B | €6,000.00 |
| 3 | project C | 1,250.00CZK |
PHP money_format uses locale where I want to use project specific currency in each row or each project page.
You can implement your own transformers, something like this:
In your controller
public function getRows(Request $request, CurrencyTransformer $transformer) {
// get data
$rows = Model::where('some', 'condition')->get()->toArray();
$data = $transformer->transformCollection($rows);
return view('some.view', compact('data'));
}
Create a abstract transformer class
abstract class Transformer
{
public function transformCollection(array $items)
{
return array_map([$this, 'transform'], $items);
}
public abstract function transform($item);
}
create a currency transformer
class CurrencyTransformer extends Transformer
{
public function transform($item) {
switch($item['currency']) {
case "usd":
$item['value'] = "$" . $item['value'];
break;
...
}
return $item;
}
}

Laravel parent / child relationship on the same model

The Setup And Dummy Data
I have a simple model called Category, which has the following schema:
|----------------------------------------------|
| cat_id | cat_name | parent_id |
|----------------------------------------------|
| 1 | Home | 0 |
|----------------------------------------------|
| 2 | Products | 1 |
|----------------------------------------------|
| 3 | Services | 1 |
|----------------------------------------------|
| 4 | Product A | 2 |
|----------------------------------------------|
| 5 | Product B | 2 |
|----------------------------------------------|
The Desired Output
So you can see that we would get a very straight forward hierarchy as follows:
Home
- Products
- Product A
- Product B
- Services
The Issue
I'm trying to map this relationship in Laravel 4.2, so that I can query a model and get its parent (it will always have a parent), and child categories if they exist.
I've defined the relationship in the Category model using:
public function children()
{
return $this->hasMany('Category', 'parent_id', 'cat_id');
}
public function parent()
{
return $this->belongsTo('Category', 'parent_id');
}
The Problem
I can get the parent name working, using
$category = Category::findOrFail($id);
return $category->parent->cat_name;
However, I don't understand how to get the child objects.
I've tried:
$category = Category::findOrFail($id);
$children = $category->children();
But when I dd($children) it doesn't output what I'd expect.
Calling the relationship function (->children()) will return an instance of the relation class. You either need to call then get() or just use the property:
$children = $category->children()->get();
// or
$children = $category->children;
Further explanation
Actually children() and children are something pretty different. children() just calls the method you defined for your relationship. The method returns an object of HasMany. You can use this to apply further query methods. For example:
$category->children()->orderBy('firstname')->get();
Now accessing the property children works differently. You never defined it, so Laravel does some magic in the background.
Let's have a look at Illuminate\Database\Eloquent\Model:
public function __get($key)
{
return $this->getAttribute($key);
}
The __get function is called when you try to access a property on a PHP object that doesn't actually exist.
public function getAttribute($key)
{
$inAttributes = array_key_exists($key, $this->attributes);
// If the key references an attribute, we can just go ahead and return the
// plain attribute value from the model. This allows every attribute to
// be dynamically accessed through the _get method without accessors.
if ($inAttributes || $this->hasGetMutator($key))
{
return $this->getAttributeValue($key);
}
// If the key already exists in the relationships array, it just means the
// relationship has already been loaded, so we'll just return it out of
// here because there is no need to query within the relations twice.
if (array_key_exists($key, $this->relations))
{
return $this->relations[$key];
}
// If the "attribute" exists as a method on the model, we will just assume
// it is a relationship and will load and return results from the query
// and hydrate the relationship's value on the "relationships" array.
$camelKey = camel_case($key);
if (method_exists($this, $camelKey))
{
return $this->getRelationshipFromMethod($key, $camelKey);
}
}
Then in getAttribute first is some code that checks for "normal" attributes and returns then. And finally, at the end of the method, if there's a relation method defined getRelationshipFromMethod is called.
It will then retrieve the result of the relationship and return that.
Set this in model and try :
public function children()
{
return $this->hasMany(self::class, 'parent_id');
}
public function grandchildren()
{
return $this->children()->with('grandchildren');
}

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