using php code inside an echo - php

Question

My question to you is how do I get the code below to echo its entirety? I have multiples of these that I need to echo using while and I have toyed with it but have yet to figure out what to do. The answers I have seen, I have tried but they just don't work on my code. I need to have all this code here in one bunch but I am having an issue inserting the "like button" section. The issue starts at
$likes = (empty($_POST['like'])) ? : $_POST['like'] ;
and here's the full code
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
echo '
<div class="wrapper">
<div class="submissions">
<div class="logo-logo"><h2>Questions.</h2>
<div class="checkboxes">'.$row['formtype'].'
</div>
</div>
<div class="top-submit">
&#8220'. $row["actual_quote"] . '”
</div>
<div class="poster">- '. $row["poster"].'
<div class = "like">- '.
$likes = (empty($_POST['like'])) ? : $_POST['like'] ;
$dislikes = (empty($_POST['dislike'])) ? : $_POST['dislike'] ;
$ip = $_SERVER['REMOTE_ADDR'];
if(isset($_POST['like'])){
$likes1 = $likes+1;
$voted1 = $voted+1;
$query2 = $db->prepare("INSERT INTO voters (voted, ip) VALUES ( :voted, :ip)");
$query2->bindParam(':voted', $voted1, PDO::PARAM_STR);
$query2->bindParam(':ip', $ip, PDO::PARAM_STR);
$query2->execute();
header("Location: like.php?");
$update1 = $db->prepare("INSERT INTO votes (likes) VALUES ( :likes)");
$update1->bindParam(':likes', $likes1, PDO::PARAM_STR);
$update1->execute();
}
if(isset($_POST['dislike'])){
$dislikes1 = $dislikes+1;
$voted1 = $voted+1;
$query2 = $db->prepare("INSERT INTO voters (voted, ip) VALUES ( :voted, :ip)");
$query2->bindParam(':voted', $voted1, PDO::PARAM_STR);
$query2->bindParam(':ip', $ip, PDO::PARAM_STR);
$query2->execute();
header("Location: like.php?");
$update1 = $db->prepare("INSERT INTO votes (dislikes) VALUES ( :dislikes)");
$update1->bindParam(':dislikes', $dislikes1, PDO::PARAM_STR);
$update1->execute();
}
$stmt = $db->query("SELECT * FROM voters");
$stmt->setFetchMode(PDO::FETCH_ASSOC);
$row3 = $stmt->fetch();
echo "Likes: $likes <br /> Dislikes: $dislikes<br />";
if(isset($row3['voted'])){
if(isset($row3['ip'])){
echo "You have already voted for this.";
}
} else {
echo "<form action = '' method = 'post'> <input type = 'submit' name = 'like' value = 'like'> <input type = 'submit' name = 'dislike' value = 'dislike'></form>";
}'
</div>
<!-- use select to get the items to stay on the page-->
</div>
</div>
</div>
';
}
There may be a very simple solution but I have searched everywhere for it. I have tried using a . at the end but it doesn't like that. Any suggestions?
EDIT I have changed one portion, the whole code starting at $likes and ending after else{} has been put as this:
<div class = "like">';
include("like.php");
echo'</div>

Answer 1

You don't. You stop your echo, do your other code, and start echoing again.
echo 'foo';
bar();
echo 'baz';

Answer 2

You shouldn't use echo in this way.
Try to keep your HTML in variable and concatenate all needed additional HTML using dot after checking all necessary conditions.
$output = '<div>blahblah</div>';
if ($somedatafromDB == true) {
$output .= '<p>true!!</p>';
} else {
$output .= '<p>false :/</p>';
}
// and finally
echo $output;

Answer 3

An issue might also be the ternary operator:
Your code is currently
$likes = (empty($_POST['like'])) ? : $_POST['like'] ;
Try to change it to
$likes = (empty($_POST['like'])) ? 0 : $_POST['like'];
You need to specify what you would like to return if the $_POST['like'] is empty.
The ternary operator (x?y:z) returns y if x is true, else it returns z. In your case y is missing which might cause an error during execution.
A good practice is ini_set("display_errors", "on"); at the beginning of the script for debugging purposes.