I have a typical XML file with many field like example
<field
type="custom"
name="city"
id="city"
label="City"
size="40"/>
In the view I display this field - everything is fine.
Moreover I'm using state filtering on this field.
model populateState():
$filter = $app->input->get('city');
$this->setState('filter.city', $filter);
The problem is that, field doesn't has a value after form submit (form has get method). I can't write in field value something like $this->getState('city') because it's xml file. Maybe anyone has a solution... I was thinking about JS, but mainly I want to have a PHP solution.
Problem solved!
Here is solution:
1. Have all fields name in jform array. It makes automatically if you use form in xml.
2. When you're loading form data, send second parameter as true: $model->getForm('formName', true) because second parameter is $loadData. By this option, Joomla will load form data.
3. You have load data from loadFormData function:
protected function loadFormData() {
$data = JFactory::getApplication()->getUserStateFromRequest('jform', 'jform');
if (empty($data)) {
$data = $this->getItem();
}
return $data;
}
That's all.
I'm not 100% clear on what you're asking, but if you're using a standard JForm and inserting it with something like this:
echo $this->form->getInput('articletext');
The it's likely the your field's name in the form isn't city, it's more likely to be something like:
`jform[articletext]`
If you can add more of the XML file, so we can see grouping etc and the php used to display the form we can probably help pin it down exactly, it will also help if you tell us which version of Joomla you're using.
Related
I'm trying to do something very basic: retrieve a post value from a hidden field. The hidden field is obviously in my view file and I want to retrieve the value in my controller. I'm using the framework SimpleMVCFramework.
I have a hidden field in my projects.php file (the list with projects). When you click on a project, a method in the controller renders the clicked project and the corresponding page. This corresponding page is called project.php
The hidden field in my projects.php view:
<form method="post" action="project.php">
<input type="hidden" name="project-id" value="<?php echo $project['id'];?>">
</form>
This hidden form is displayed correctly in my lists with projects. I checked them in the console.
In my ProjectController.php, I try to retrieve the data using
$data['id'] = $_POST['project-id'];
Then, I send the $data variable with the rendered page, so that I can use the id. So every project in projects.php has a hidden file that outputs correctly. When I try and click on a project, it brings me to project.php, but when I check out the $data variable, the id is just empty.
The routing works like a charm, because e.g. $data['title'] = "Project"; works great and is visible when I check the $data variable. When I change
$data['id'] = $_POST['project-id'];
to
$data['id'] = "foobar";
the id in project.php isn't empty anymore, but shows foobar. So I guess that something goes wrong with retrieving the value.
I also tried to remove the action=".." from the form, but that also didn't work.
The thing I'm trying to achieve is so simple, that I don't understand what is going wrong. Is it possible that the problem lies with the framework and that the code is right?
Thanks in advance and sorry for my bad English.
I am trying to export cgridview data (current search results) to a CSV by using the excelview extension, by clicking a button.
However, I am not getting the filtered data in my CSV; instead, I'm getting all the records in the model.
This is my controller action I am calling:
public function actionExcel()
{
$model = new PackagingMetric('search');
$this->widget('application.extensions.EExcelView', array(
'dataProvider'=> $model->search(),
'grid_mode'=>'export',
'exportType'=>'Excel5',
'filename'=>'report',
));
}
Would anyone know how to resolve this issue, or where my error is ?
You don't have any search criteria there. Usually you do it like this:
$model = new PackagingMetric('search');
$model->attributes = $_POST['PackagingMetric']; // this would be the model associated with the search form
$model->search();
I don't see anything in your code that takes values from user input, so you should use your search form somehow. Of course, you could have default values in your model, but I don't think that's the case.
Edit:
I looked a bit more into the source code of the extension you are using. It seems that the export buttons are actually standard <a href=''></a> links that send you to a page that's supposed to output the Excel sheet. However, because the actual filter data is not transmitted to that page, there's no way to apply those filters server-side.
Since this is the intended behavior of the extension, there's no elegant way to solve it, but there are messy ways.
A first option would be to tweak the extension yourself, but this will break compatibility with future versions. Another way is to use Javascript to send your data where you need it. In the view file where you are displaying the gridview, you should wrap the widget in a form element or in an ActiveForm with all validation disabled. Then you need to place the following piece of Javascript code somewhere on the page:
var $excelForm = $( '#your_form_id' );
$( '.summary a', $excelForm ).click( function() {
$excelForm.attr( 'action', this.href ).submit();
return false;
});
This will submit the form to the address specified by the export link. Because the form wraps the widget, it will contain the input elements that filter your results, so you will have access to the user-entered filters on the server. You can use the code I originally posted to pick up the data from there.
Note: I am using the default class name for the div that contains the export buttons, which is .summary. If you are using a different class, you should change the respective JS code.
I have an HTML form which contains a drop down, a tinyMCE textarea, and a save button.
The dropdown is used to select a file to edit.
I load up the required file into the tinyMCE editor by making an ajax call when the jquery change() event is triggered from the dropdown. That works fine.
The problem I'm having is saving the file off. I am trying to do it by posting the form off to another php page which will write to the file and then send us back to the main page.
This is the php code within my writeFile.php page:
<?php
session_start();
if (!isset($_SESSION['id'])) {
header ('Location: index.php?error=0');
}
else {
if (isset($_POST['save'])) {
$text = $_POST['mceContent'];
$index = $_POST['files']; // << PROBLEM LINE!
$array = array('homeText.txt', 'anotherText.txt');
$fileName = $array[$index];
$path = '../txt/'.$fileName;
$length = strlen($text);
echo "INDEX: $index"; // TO TEST THE INDEX VARIABLE.
$fh = fopen($text,'w',true);
fwrite($fh,$text,$length) or die('Could not write');
fclose($fh);
header ('Location: admin.php');
}
}
?>
The $index variable is meant to be the selected index in the dropdown, however it is posted by my form as the selected string value in the dropdown.
I can think of three solutions (ordered from least likely to work to most likely)
There is some way to get the index from that php post?
I can make a change in the HTML form/select tag to tell it to post the index and not the value string
I change it to a jquery event, with the on-click, and pass in the index to a post manually with xhr.
If someone could help me with implementing one of these method that would be great.
If you have your own, better solution I would be happy to hear that as well.
Also note that I can't build the path from the value string, because my dropdown uses descriptive strings, not actual file names.
Thanks in advance, bear in mind I'm new to php and especially jquery.
I am not sure why you can't use the value attribute - the descriptive string would be the text portion of the option element, the filename to save could be the value:
<option value="path/to/file_to_save.php">Descriptive file name</option>
Doing it that way, the user sees the descriptive text, the server gets a useful bit of information it needs when the form posts.
If that is not an option, you could add an onSubmit event to the form in which you pass the selectedIndex property to a hidden form field, then return true and let the form submit normally.
Form snippet
<form onsubmit="return beforeSubmit()">
<input type="hidden" name="file_index" value="" id="file_index_fld" />
<select id="file_name_dropdown">
<option>...</option>
Javascript snippet
var beforeSubmit = function () {
$('#file_index_fld').val($('#file_name_dropdown').attr("selectedIndex"));
return true;
}
... now in PHP's $_POST variable, you'll see $_POST['file_index'] contains the selectedIndex of the select element.
The long and short of it is that the selectedIndex property is a DOM item and not part of the POST data. No matter what, you are either going to have to intervene with javascript to add the data to POST, or modify your option elements to pass the desired data. I would always lean toward the former route as it is less complex.
Another option I can think of: Before posting, catch the new index in the change-event and write it to a hidden input-field of your form. After that, you can serialize and post it with jQuery.
I want to use the autocomplete plugin for jQuery to populate not one, but two fields when selecting one of the autocomplete values - the name of a band is entered in the #band input field, but the band url (if exists) should also automatically be added to the #url input field when selecting the band name.
Right now I simply have an un-pretty list in an external php file from which the autocompleter takes it's values:
$bands_sql = "SELECT bands.name, bands.url
FROM bands
ORDER BY name";
$bands_result = mysql_query($bands_sql) or print (mysql_error());
while ($bands_row = mysql_fetch_array($bands_result)) {
$band_name = $bands_row['name'];
$band_url = $bands_row['url'];
echo $band_name."\n"; #needs to be replaced with an array that holds name and url
}
My autocomplete function looks very basic atm, but as I'm an absolute beginner when it comes to jQuery (and also clueless when it comes to PHP arrays), I have no idea how to tell it to populate two fields and not one.
$(document).ready(function() {
$("#band").autocomplete('/autocomplete-bands.php');
});
Is that even possible?!
sure check use result hadler so you can then do what you want once a choice has been made
I don't know about the particular plug-in you are using, but I would use the autocomplete widget for jQuery UI instead of a third party plug-in.
Here is an example of what you are looking for:
$("#band").autocomplete('/autocomplete-bands.php').result(function(event, data, formatted) {
if (data)
$('#url').(data['url']);
else {
// no data returned from autocomplete URL
}
});
I don't know much about php, but whatever the format of your data that is returned should be put where the data['url'] is currently in order to populate the #url input.
Im looking for a way to have a form in cakephp that the user can add and remove form fields before submitting, After having a look around and asking on the cake IRC the answer seems to be to use Jquery but after hours of looking around i cannot work out how to do it.
The one example i have of this in cake i found at - http://www.mail-archive.com/cake-php#googlegroups.com/msg61061.html but after my best efforts i cannot get this code to work correctly ( i think its calling controllers / models that the doesn't list in the example)
I also found a straight jquery example (http://mohdshaiful.wordpress.com/2007/05/31/form-elements-generation-using-jquery/) which does what i would like my form to do but i cannot work out how to use the cakephp form helper with it to get it working correctly and to get the naming correct. (obviously the $form helper is php so i cant generate anything with that after the browser has loaded).
I an new to cake and have never used jQuery and i am absolutely stumped with how to do this so if anyone has a cakephp example they have working or can point me in the right direction of what i need to complete this it would be very much appreciated.
Thanks in advance
I would take the straight jquery route, personally. I suppose you could have PHP generate the code for jquery to insert (that way you could use the form helper), but it adds complexity without gaining anything.
Since the form helper just generates html, take a look at the html you want generated. Suppose you want something to "add another field", that when clicked, will add another field in the html. Your html to be added will be something like:
<input type="text" name="data[User][field][0]" />
Now, to use jquery to insert it, I'd do something like binding the function add_field to the click event on the link.
$(document).ready( function() {
$("#link_id").click( 'add_field' );
var field_count = 1;
} );
function add_field()
{
var f = $("#div_addfield");
f.append( '<input type="text" name="data[User][field][' + field_count + ']" />' );
field_count++;
}
Of course, if a user leaves this page w/o submitting and returns, they lose their progress, but I think this is about the basics of what you're trying to accomplish.
This was my approach to remove elements:
In the view, I had this:
echo $form->input('extrapicture1uploaddeleted', array('value' => 0));
The logic I followed was that value 0 meant, not deleted yet, and value 1 meant deleted, following a boolean logic.
That was a regular input element but with CSS I used the 'display: none' property because I did not want users to see that in the form. Then what I did was that then users clicked the "Delete" button to remove an input element to upload a picture, there was a confirmation message, and when confirming, the value of the input element hidden with CSS would change from 0 to 1:
$("#deleteextrapicture1").click(
function() {
if (confirm('Do you want to delete this picture?')) {
$('#extrapicture1upload').hide();
// This is for an input element that contains a boolean value where 0 means not deleted, and 1 means deleted.
$('#DealExtrapicture1uploaddeleted').attr('value', '1');
}
// This is used so that the link does not attempt to take users to another URL when clicked.
return false;
}
);
In the controller, the condition $this->data['Deal']['extrapicture1uploaddeleted']!='1' means that extra picture 1 has not been deleted (deleting the upload button with JavaScript). $this->data['Deal']['extrapicture1uploaddeleted']=='1' means that the picture was deleted.
I tried to use an input hidden element and change its value with JavaScript the way I explained above, but I was getting a blackhole error from CakePHP Security. Apparently it was not allowing me to change the value of input elements with JavaScript and then submit the form. But when I used regular input elements (not hidden), I could change their values with JavaScript and submit the form without problems. My approach was to use regular input elements and hide them with CSS, since using input hidden elements was throwing the blackhole error when changing their values with JavaScript and then submitting the form.
Hopefully the way I did it could give some light as a possible approach to remove form fields in CakePHP using JavaScript.