Delete From Table - Via Form - php

I have a HTML table that displays all my table entries. Also in the table is a delete button next to every SQL entry.
I want to be able to delete an entry the user selects. I've made the form to Post PHP_Self, and I'm passing in the index $i from the while loop as a reference:
$i = 0;
while($row = mysqli_fetch_array($result)){
?>
<tr>
<td>
<? echo $row['uniqueIdentifier']; ?>
</td>
<td>
<form action="<? echo $_SERVER['PHP_SELF']; ?>" method="post">
<input type='hidden' name='remove_entrie_ID' value='<? echo $i; ?>' />
<input type='submit' value='Delete' name='remove_entrie'>
</form>
</td>
</tr>
<?
$i++;
}
So this is passed to itself, I now want to do a DELETE WHERE 'INDEX OF TABLE' == $i, type thing? I don't even know if this is possible.
if(isset($_POST['remove_entrie'])){
$index = $_POST['remove_entrie_ID']
echo "Index: " . $index;
//mysqli_query($con, "DELETE FROM Users WHERE INDEX = '$index'");
}
I'm basically using the $i to pick out the index of how the table was loaded, and then using that to pick out which row I want to delete. But I have a feeling this can't be done?
I basically want to delete a row the user has selected from the table.

You don't need $i variable. Just make simple modification in your list:
while($row = mysqli_fetch_array($result)){
?>
<tr>
<td>
<? echo $row['uniqueIdentifier']; ?>
</td>
<td>
<form action="" method="post">
<input type="hidden" name="remove_entrie_ID" value="<? echo $row['uniqueIdentifier']; ?>" />
<input type="submit" value="Delete" name="remove_entrie">
</form>
</td>
</tr>
<?
}
It is also good idea to escape specials chars etc in your post variable to avoid sql injection.

Related

How to add a delete button in the html table to delete entire row from database? [duplicate]

I have outputted the results of a MySQL table to an HTML table. In the last column, I want to add a delete option which calls another form and deletes the user from the MySQL table. I can't seem to get it to work though.
This is my code for the results page:
<?php
$contacts = mysql_query("
SELECT * FROM contacts ORDER BY ID ASC") or die( mysql_error() );
// If results
if( mysql_num_rows( $contacts ) > 0 )
?>
<table id="contact-list">
<thead>
<tr>
<th>Name</th>
<th>Email</th>
<th>Telephone</th>
<th>Address</th>
<th>Delete</th>
</tr>
</thead>
<tbody>
<?php while( $contact = mysql_fetch_array( $contacts ) ) : ?>
<tr>
<td class="contact-name"><?php echo $contact['name']; ?></td>
<td class="contact-email"><?php echo $contact['email']; ?></td>
<td class="contact-telephone"><?php echo $contact['telephone']; ?></td>
<td class="contact-address"><?php echo $contact['address']; ?></td>
<td class="contact-delete"><form action='delete.php' method="post">
<input type="hidden" name="name" value="">
<input type="submit" name="submit" value="Delete">
</form></td>
</tr>
<?php endwhile; ?>
</tbody>
</table>
and, this is my delete.php script
<?php
//Define the query
$query = "DELETE FROM contacts WHERE name={$_POST['name']} LIMIT 1";
//sends the query to delete the entry
mysql_query ($query);
if (mysql_affected_rows() == 1) {
//if it updated
?>
<strong>Contact Has Been Deleted</strong><br /><br />
<?php
} else {
//if it failed
?>
<strong>Deletion Failed</strong><br /><br />
<?php
}
?>
I cannot figure out why this is not working.
You have to pass a variable in the delete link. You have to pass <?php echo $contact['name']; ?> (the name value) in a hidden field or pass this value in URL:
Replace
<td class="contact-delete">
<form action='delete.php' method="post">
<input type="hidden" name="name" value="">
<input type="submit" name="submit" value="Delete">
</form>
</td>
With
<td class="contact-delete">
<form action='delete.php?name="<?php echo $contact['name']; ?>"' method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
</form>
</td>
USe javascript
<input name="Submit2" type="button" class="button" onclick="javascript:location.href='delete.php?id=<?php echo $your_id;?>';" value="« Back" />
and in delet.php
$id=$_GET['id'];
and put $id in your sql statement.
You are missing to pass name in this line:
<input type="hidden" name="name" value="">
You need to have something (<?php echo $contact['name']; ?>) in the value attribute.
BTW, do not use deprecated mysql_* functions, use PDO or mysqli_* instead.
<input type="hidden" name="name" value="">
You are missing a value which wil be picked up by this line in your delete file.
$query = "DELETE FROM contacts WHERE name={$_POST['name']} LIMIT 1";
Right now it isn't receiving anything, which is why it will not work.
So add a value to it and it will work. Example:
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
First, you should not write the code in that way; the code has no protection against SQL injection.
1. Try to use primary IDs instead of using a name (what happens if 2 people has the same name?).
So, you can create a hidden field to know which 'person' you are dealing with.
<input type="hidden" name="contact_id" value="<?php $contact['contact_id']; ?>">
2. Sanitize variables to avoid attacks:
<?php $contact_id = isset($_POST['contact_id'])?intval($_POST['contact_id']):0;
// proceed with the query
if($contact_id>0) { $query = "DELETE FROM contacts WHERE contact_id = '$contact_id'";
}
// redirect to the main table with header("location: main.php");
?>

Add a delete button to a table populated from a database

I have a table which I populate from a mysql db. I want to add a delete button to each of the rows in the table, and when the button is clicked, I want to remove that line from the db table. I am using an array to update any changes made to the table. How can I use that array to delete a specific row too?
<table>
<tr><th>Category ID</th><th>Description</th><th>Valid</th><th></th></tr>
<?php
$query=mysqli_query($link,"SELECT * FROM cd_categories");
while($row = mysqli_fetch_array($query)){
$catid = $row['Catg_Id'];
$des = $row['Description'];
$datep = $row['Date_Posted'];
$postedb = $row['Posted_By'];
$valid = $row['Valid_YN'];
?>
<tr><td><input type="text" name="data[<?php echo $catid; ?>][catid]" value="<?php echo $catid; ?>" ></td>
<td><input type="text" name="data[<?php echo $catid; ?>][des]" value="<?php echo $des; ?>" ></td>
<td><input type="button" name="data[<?php echo $catid; ?>][delete]" value="Delete" ></td>
</tr>
<?php } ?>
</table>
<br>
<input type="submit" name="update" value="Save Changes" >
To remove a row from database you need to use a DELETE statement with a primary key, which you need to pass from this while loop.
Make a link inside while loop: [Demo]
<a href='delete.php?id=your_id'>Delete</a>
Now in your delete page, you need to capture or store the id using $_GET and using the DELETE Statement you can simply delete row from database.
DELETE FROM table_name WHERE primary_key=your_get_value;
Note: In your delete page just make a query for delete the row also
make some security.
Try this approach:
<table>
<tr><th>Category ID</th><th>Description</th><th>Valid</th><th></th></tr>
<?php
$query=mysqli_query($link,"SELECT * FROM cd_categories");
while($row = mysqli_fetch_array($query)){
$catid = $row['Catg_Id'];
$des = $row['Description'];
$datep = $row['Date_Posted'];
$postedb = $row['Posted_By'];
$valid = $row['Valid_YN'];
?>
<tr><td><input type="text" name="catid_<?php echo $catid; ?>" value="<?php echo $catid; ?>" ></td>
<td><input type="text" name="desc_<?php echo $catid; ?>" value="<?php echo $des; ?>" ></td>
<td>
Edit |
Delete</td>
</tr>
<?php } ?>
</table>
<br>
in delete.php:
delete from table where cat_id= $_GET["id"];
in edit.php
$desc =
update table set desc=$_GET["desc_".$_GET["id"]], catid = $_GET["catid_".$_GET["id"]] where cat_id= $_GET["id"];
Basically, to do this without javascript, you need to have a separate form for each row of your HTML table (which displays one row from your db). Add a hidden input field in your form which contains the unique identifier for that particular row, and a submit button to delete the row. Leave the form action field blank so the same page receives the submitted form data, then have PHP test for which button was submitted and if it was the delete button, delete the data and re-display the table.
Example HTML code:
<table>
<tr><td>
<form action="" method="post">
<input type="hidden" name="row_id" value="<?php echo 'identifier here'; ?>">
<?php echo 'stuff here'; ?>
<input type="submit" name="submit" value="Save Changes">
<input type="submit" name="submit" value="Delete">
</form>
</td></tr>
</table>
Example PHP code:
if (isset($_POST['submit')) // Form submitted
{
if ($_POST['submit'] == 'Delete') // Delete button clicked
{
// Run delete query based on the hidden field containing the row identifier
}
elseif ($_POST['submit'] == 'Save Changes')
{
// Run update query
}
}

html dynamic form, pass multiple values through post and insert mysql

i have this database
and this form, dynamically generated from the database
<table border="1" cellspacing="0" cellpadding="6">
<tr bgcolor="#CCCCCC">
<td><strong>product id</strong></td>
<td><strong>product name</strong></td>
<td><strong>product price</strong></td>
<td><strong>quantity</strong></td>
</tr>
<form method="post" action="insert.php">
<?php
$query = $dbh->query('SELECT * FROM products');
$results = $query->fetchAll(PDO::FETCH_ASSOC);
foreach ($results as $row)
{
?>
<tr>
<td><?php echo $row['product_id']; ?></td>
<td><?php echo $row['product_name']; ?></td>
<td><?php echo $row['product_price']; ?></td>
<td><input name="quantity" type="text" value="0"></td>
</tr>
</form>
<?php } ?>
</table>
<br>
<input type="submit" value="Add Records">
the quantity in the form is a textbox so i can modify it.
I would like to enter the quantities and the pressing the button to insert the values in the order_products table (including the quantity).
1) How can i pass ALL the quantities and product_id (and the rest) to the next page through post? (until now i know how to pass single values)
2) is there a better way to achieve it?
3) the insert statements should be in the same page or the page where i get the post vars?
db scheme
http://i.stack.imgur.com/oqdOy.jpg
thanks
Rob
1) First, you have to wrap your <input>s inside a single form (move your </form> tag after your <input type="submit" value="Add Records">, the way you have it now closes the <form> tag at first iteration) and submit it via HTTP POST method. Then, based on your schema, the only field you'll have to insert aside of quantity is product_id, which value you can assign inside a hidden field, like:
<?php
echo "<input type='hidden' name='pid_$row['product_id']' value='$row['product_id']'>";
echo $row['product_id'];
?>
Notice that you can still echo the value itself for viewing purposes. You also have to generate your quantity <input> field name property dynamically, otherwise $_POST will overwrite values when their keys are the same.
<?php
echo "<input type='text' name='pid-qtd_$row['product_id']'>";
?>
2) It depends on your development priorities. There are some frameworks out there that might simplify your process. I'd recommend you to keep all your DB queries and connection data within a DB helper class and require it wherever you need it.
3) Since you're using PDO, I assume you have an OOP design, which implies in doing that at your DB helper class or such. The page receiving the HTTP request must require your helper and deal with the $_POST parsing to parameters to its query methods. Don't forget to prepare your statements and parameterizing your queries.
Using hidden element you can post your data to second page. Using counter variable you can add dynamic form element and post it into second page.
<form method="post" action="test2.php">
<table border="1" cellspacing="0" cellpadding="6">
<tr bgcolor="#CCCCCC">
<td><strong>product id</strong></td>
<td><strong>product name</strong></td>
<td><strong>product price</strong></td>
<td><strong>quantity</strong></td>
</tr>
<?php
$query = $con->query('SELECT * FROM product'); //your query goes here
$results = $query->fetchAll(PDO::FETCH_ASSOC);
$i=0; //counter variable
foreach ($results as $row)
{
?>
<tr>
<td>
<?php echo $row['prod_id']; ?>
<input type="hidden" name="prod_id<?php echo $i; ?>" value="<?php echo $row['prod_id']; ?>" />
</td>
<td>
<?php echo $row['prodname']; ?>
<input type="hidden" name="name<?php echo $i; ?>" value="<?php echo $row['prodname']; ?>" />
</td>
<td>
<?php echo $row['price']; ?>
<input type="hidden" name="price<?php echo $i; ?>" value="<?php echo $row['price']; ?>" />
</td>
<td><input name="quantity<?php echo $i; ?>" type="text" value="0"></td>
</tr>
<?php
$i++; //increment counter variable
}
?>
<input type="hidden" name="rows" id="rows" value="<?php echo $i; ?>" />
</table>
<br>
<input type="submit" value="Add Records">
</form>
Your insert page code goes here....
for($i=0;$i<=$_POST['rows'];$i++)
{
$prodid = $_POST['prod_id'.$i];
$pname = $_POST['name'.$i];
$pprice = $_POST['price'.$i];
$con ->exec("insert into product(prod_id,prodname,price)values('$prodid', '$pname','$pprice' )" );
}
I suggest putting the product_id in a hidden form element like this:
<tr>
<input type='hidden' name='product_id' value='<?php echo $row['product_id']; ?>'/>
<td><?php echo $row['product_id']; ?></td>
<td><?php echo $row['product_name']; ?></td>
<td><?php echo $row['product_price']; ?></td>
<td><input name="quantity" type="text" value="0"></td>
</tr>
This will send the product_id with your quantity and you can use it in your insert statement.
The only problem with this is if you have more than one row, there will be more than one hidden element for product_id, etc. Ways to overcome this include differentiating them by appending an incrementing number on the hidden element's name, e.g.:
$i = 1;
foreach ($results as $row)
{
$product_id_name = 'product_id_'.$i;
$quantity_name = 'quantity_'.$i;
... echo your table row, using $product_id_name in the hidden element, and $quantity_name in your text input
$i++;
}
Then in your inserting code you have to look for all the items in $_POST whose keys start with "quantity_", and if they are non-zero, get the integer NNN after the key prefix "quantity_", and get the corresponding product_id_NNN value to do your insert.

Insert to database when the button is click

im currently displaying all the information from the table product in a tabular format, i have a button ADD which when click should add only the id, name and price from the table product to the table product_add in the same database. but my problem is that when i click on the button ADD, nothing is entered in the product_add table.
<?php
include'connect.php';
$image =$_GET['image'];
$id =$_GET['id'];
$name =$_GET['name'];
$price=$_GET['price'];
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0)
{
?>
<form method="post" id="form" name="form">
<table border='1'>
<?php
while ($row = mysql_fetch_array($result))
{
extract($row);
?>
<tr>
<td><?php echo $row['id']?></td>
<td><img src=<?php echo $row['image'] ?> /></td>
<td><?php echo $row['name']?></td>
<td><?php echo $row['price']?></td>
<td><input type='button' value='ADD' id="insert" name="insert"/></td>
</tr>
<?php
}
?>
</table>
</form>
<?php
}
if(isset($_REQUEST['insert']))
{
$insert = "INSERT INTO product_add(id, name, price)
VALUES ('$row[id]','$row['name']','$row['price']')";
$insertQuery=mysql_query($insert);
}
?>
</body>
</html>
I have updated the codes as shown below but the last row from the table product is being added to the table product_add. I want to add only a specific row when i click on the button submit.
<?php
include'connect.php';
$image = isset($_GET['image']) ? $_GET['image'] : "";
$id = isset($_GET['id']) ? $_GET['id'] : "";
$name = isset($_GET['name']) ? $_GET['name'] : "";
$price= isset($_GET['price']) ? $_GET['price'] : "";
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0){
?>
<form method="POST" id="form" name="form">
<table border='1'>
<tr>
<th>Id</th>
<th>Image</th>
<th>Name</th>
<th>Price MUR</th>
</tr>
<?php
while ($row = mysql_fetch_array($result)){
extract($row);
?>
<tr>
<td><input name="id" value="<?php echo htmlspecialchars($row['id']); ?>">
</td>
<td><img src=<?php echo $row['image'] ?> width='120' height='100'/></td>
<td><input name="name" value="<?php echo htmlspecialchars($row['name']);
?>"></td>
<td><input name="price" value="<?php echo htmlspecialchars($row['price']);
?>"></td>
<td>
<input id="submit" type="submit" name="submit" value='Add to cart' />
</td>
</tr>
<?php
}
?>
</table>
</form>
<?php
}
if (isset($_REQUEST['submit']))
{
$insert = "INSERT INTO product_add(id, name, price) VALUES ('$id',
'$name','$price')";
$insertQuery=mysql_query($insert);
}
?>
Apart from the method (if your form uses POST, you should use $_POST in php), you do not have any form fields.
For example:
<?php echo $row['id']?>
Should be something like:
<input type="hidden" name="id" value="<?php echo $row['id']; ?>">
and:
<?php echo $row['name']?>
should be:
<input name="name" value="<?php echo htmlspecialchars($row['name']); ?>">
etc.
You should also switch to PDO or mysqli and prepared statements as the code you have now is vulnerable to sql injection. And ID's in html need to be unique.
One point is, you have multiple
<input type='button' ...>
with the same id="insert". ids must be unique within a web page.
The other thing is, you need a submit input to send the form
<input type="submit" ...>
From Submit Button state (type=submit)
The input element represents a button that, when activated, submits the form.
With <input type='button' ...> nothing happens, because it has no default action, see Button state (type=button)
The input element represents a button with no default behavior.
If you want an <input type='button' ...> to submit the form, you must do so by using some Javascript code.
One idea is to load content once the button is clicked.
js
$("#button").click(function() {
$("#holder").load("insert.php");
});
insert.php
$db->query("INSERT INTO table VALUES('one','two','three')");

How to add a delete button to a PHP form that will delete a row from a MySQL table

I have outputted the results of a MySQL table to an HTML table. In the last column, I want to add a delete option which calls another form and deletes the user from the MySQL table. I can't seem to get it to work though.
This is my code for the results page:
<?php
$contacts = mysql_query("
SELECT * FROM contacts ORDER BY ID ASC") or die( mysql_error() );
// If results
if( mysql_num_rows( $contacts ) > 0 )
?>
<table id="contact-list">
<thead>
<tr>
<th>Name</th>
<th>Email</th>
<th>Telephone</th>
<th>Address</th>
<th>Delete</th>
</tr>
</thead>
<tbody>
<?php while( $contact = mysql_fetch_array( $contacts ) ) : ?>
<tr>
<td class="contact-name"><?php echo $contact['name']; ?></td>
<td class="contact-email"><?php echo $contact['email']; ?></td>
<td class="contact-telephone"><?php echo $contact['telephone']; ?></td>
<td class="contact-address"><?php echo $contact['address']; ?></td>
<td class="contact-delete"><form action='delete.php' method="post">
<input type="hidden" name="name" value="">
<input type="submit" name="submit" value="Delete">
</form></td>
</tr>
<?php endwhile; ?>
</tbody>
</table>
and, this is my delete.php script
<?php
//Define the query
$query = "DELETE FROM contacts WHERE name={$_POST['name']} LIMIT 1";
//sends the query to delete the entry
mysql_query ($query);
if (mysql_affected_rows() == 1) {
//if it updated
?>
<strong>Contact Has Been Deleted</strong><br /><br />
<?php
} else {
//if it failed
?>
<strong>Deletion Failed</strong><br /><br />
<?php
}
?>
I cannot figure out why this is not working.
You have to pass a variable in the delete link. You have to pass <?php echo $contact['name']; ?> (the name value) in a hidden field or pass this value in URL:
Replace
<td class="contact-delete">
<form action='delete.php' method="post">
<input type="hidden" name="name" value="">
<input type="submit" name="submit" value="Delete">
</form>
</td>
With
<td class="contact-delete">
<form action='delete.php?name="<?php echo $contact['name']; ?>"' method="post">
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
<input type="submit" name="submit" value="Delete">
</form>
</td>
USe javascript
<input name="Submit2" type="button" class="button" onclick="javascript:location.href='delete.php?id=<?php echo $your_id;?>';" value="« Back" />
and in delet.php
$id=$_GET['id'];
and put $id in your sql statement.
You are missing to pass name in this line:
<input type="hidden" name="name" value="">
You need to have something (<?php echo $contact['name']; ?>) in the value attribute.
BTW, do not use deprecated mysql_* functions, use PDO or mysqli_* instead.
<input type="hidden" name="name" value="">
You are missing a value which wil be picked up by this line in your delete file.
$query = "DELETE FROM contacts WHERE name={$_POST['name']} LIMIT 1";
Right now it isn't receiving anything, which is why it will not work.
So add a value to it and it will work. Example:
<input type="hidden" name="name" value="<?php echo $contact['name']; ?>">
First, you should not write the code in that way; the code has no protection against SQL injection.
1. Try to use primary IDs instead of using a name (what happens if 2 people has the same name?).
So, you can create a hidden field to know which 'person' you are dealing with.
<input type="hidden" name="contact_id" value="<?php $contact['contact_id']; ?>">
2. Sanitize variables to avoid attacks:
<?php $contact_id = isset($_POST['contact_id'])?intval($_POST['contact_id']):0;
// proceed with the query
if($contact_id>0) { $query = "DELETE FROM contacts WHERE contact_id = '$contact_id'";
}
// redirect to the main table with header("location: main.php");
?>

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