PHP replace wildcards (%s, %d) in string with vars - php

Question

I have translate function t($var);
function t($word) {
return $this->words[$word];
}
where $this->words is array
$this->words = array(
'word1' => 'word',
'word2' => 'something'
);
I am using functions as <?php echo t('word1'); ?>
and output is : word
My goal is to use wildcards %s, %d, %f to replace them with variables.
Example:
$this->words = array(
'word1' => 'word',
'word2' => 'something',
'sentence' => 'Hello, my name is %s. I am %d years old.'
);
Then parse variables into t() function.
<?php echo t('sentence', array('Mike', 99));
So output will be: Hello, my name is Mike. I am 99 years old.
My Work so far:
function t($word, $vars = array()) {
foreach ($vars as $key) {
if(is_string($key)){
$this->words[$word] = str_replace ('%s', $key, $this->words[$word]);
}
if(is_int($key)) {
$this->words[$word] = str_replace ('%d', $key, $this->words[$word]);
}
if(is_float($key)){
$this->words[$word] = str_replace ('%f', $key, $this->words[$word]);
}
}
return $this->words[$word];
}
But this function doesn't work with more than one of each type of variable.

Answer 1

I've seen people recommend using sprintf but personally I'd recommend using vsprintf: http://www.php.net/manual/en/function.vsprintf.php
function t($word, $vars = array()) {
return vsprintf($this->words[$word], $vars);
}
This allows you to pass in an array of variables instead of passing them in as separate parameters.
Generally translate functions will first check for a translation and if not found just return the lookup key.
function t($word, $vars = array()) {
return isset($this->words[$word]) ? vsprintf($this->words[$word], $vars) : $word;
}

Answer 2

You can define the t function like below :
function t($array)
{
return sprintf($array['sentence'],$array['word1'],$array['word1']);
}
Where array is :
$array = array(
'word1' => 'word',
'word2' => 'something',
'sentence' => 'Hello, my name is %s. I am %d years old.'
);
Call the function :
echo t($array);